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At 380 degree Celsius the time for the 1st order reaction 2H2O2 -> 2H2O O2 is 360 min. The energy of activation of the reaction is 200kJ/mol. Calculate the time required for 75% decomposition at 450 degree Celsius . ? Ans - 20.4 min? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about At 380 degree Celsius the time for the 1st order reaction 2H2O2 -> 2H2O O2 is 360 min. The energy of activation of the reaction is 200kJ/mol. Calculate the time required for 75% decomposition at 450 degree Celsius . ? Ans - 20.4 min? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At 380 degree Celsius the time for the 1st order reaction 2H2O2 -> 2H2O O2 is 360 min. The energy of activation of the reaction is 200kJ/mol. Calculate the time required for 75% decomposition at 450 degree Celsius . ? Ans - 20.4 min?.

Solutions for At 380 degree Celsius the time for the 1st order reaction 2H2O2 -> 2H2O O2 is 360 min. The energy of activation of the reaction is 200kJ/mol. Calculate the time required for 75% decomposition at 450 degree Celsius . ? Ans - 20.4 min? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

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