2.5 litre of 1M. NAOH solution mixed with another 3 litre of 0.5 NAOH solution then find out molarity of resultant solution?

Question

Answer

0.727

Answer

Answer

Answer

MV=(M1V1)+(M2V2)
on solving M=0.7272

Answer

To find out the molarity of the resultant solution, we need to calculate the number of moles of NaOH in both the 2.5 liter 1M NaOH solution and the 3 liter 0.5M NaOH solution, and then combine them.

Let's start by calculating the number of moles in the 2.5 liter 1M NaOH solution.

Molarity (M) is defined as moles of solute divided by volume of solution in liters.
Since the given solution is 1M NaOH, it means there is 1 mole of NaOH in 1 liter of solution.

Moles of NaOH in the 2.5 liter 1M NaOH solution = Molarity × Volume
= 1M × 2.5 liters
= 2.5 moles

Now, let's calculate the number of moles in the 3 liter 0.5M NaOH solution.

Moles of NaOH in the 3 liter 0.5M NaOH solution = Molarity × Volume
= 0.5M × 3 liters
= 1.5 moles

Next, we need to add the number of moles from both solutions together to get the total number of moles.

Total moles of NaOH = Moles from 1M NaOH solution + Moles from 0.5M NaOH solution
= 2.5 moles + 1.5 moles
= 4 moles

To find the molarity of the resultant solution, we divide the total moles by the total volume of the solution.

Total volume of the resultant solution = 2.5 liters + 3 liters
= 5.5 liters

Molarity of the resultant solution = Total moles ÷ Total volume
= 4 moles ÷ 5.5 liters
≈ 0.727 M

Therefore, the molarity of the resultant solution is approximately 0.727 M.

In summary, to find the molarity of the resultant solution, we calculate the number of moles of NaOH in both the 1M and 0.5M solutions, add them together, and then divide by the total volume of the solution.

Answer

0.7

Answer

0.727 M

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