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A 50 kg girl is swinging on a swing from rest . Then , the power delivered when moving with a velocity of 2m/s upwards in a direction making an angle of 60 degree with the verticle is - a. 980 W. b . 490W c 490√3. d . 245W?
Verified Answer
A 50 kg girl is swinging on a swing from rest . Then , the power deliv...
P = F.V
= mg.vCostheta
= 50 x 9.8 x 2 Cos60deg.
=490W.
This question is part of UPSC exam. View all NEET courses
Most Upvoted Answer
A 50 kg girl is swinging on a swing from rest . Then , the power deliv...
The power delivered when a 50 kg girl is swinging on a swing can be calculated using the formula:
Power = Force x Velocity
To calculate the force, we need to consider the vertical and horizontal components separately.
Vertical Component:
The weight of the girl can be calculated using the formula:
Weight = mass x gravity
where mass = 50 kg and gravity = 9.8 m/s^2
Weight = 50 kg x 9.8 m/s^2 = 490 N
The vertical component of the force is equal to the weight of the girl, which is 490 N.
Horizontal Component:
The horizontal component of the force is equal to the tension in the swing ropes. Since the girl is moving with a velocity of 2 m/s upwards in a direction making an angle of 60 degrees with the vertical, the tension can be calculated using the formula:
Tension = (Weight / sinθ)
where θ = 60 degrees
Tension = (490 N) / sin(60°) = 490 N / (√3/2) = 980 N
The horizontal component of the force is equal to the tension, which is 980 N.
Total Force:
To find the total force, we can use the Pythagorean theorem:
Total Force = √(Vertical Component^2 + Horizontal Component^2)
Total Force = √((490 N)^2 + (980 N)^2) = √(240100 N^2) = 490 N
The power delivered can now be calculated using the formula mentioned earlier:
Power = Force x Velocity
Power = (490 N) x (2 m/s) = 980 W
Therefore, the power delivered when the girl is swinging with a velocity of 2 m/s upwards in a direction making an angle of 60 degrees with the vertical is 980 W. Hence, the correct option is a. 980 W.
Power = Force x Velocity
To calculate the force, we need to consider the vertical and horizontal components separately.
Vertical Component:
The weight of the girl can be calculated using the formula:
Weight = mass x gravity
where mass = 50 kg and gravity = 9.8 m/s^2
Weight = 50 kg x 9.8 m/s^2 = 490 N
The vertical component of the force is equal to the weight of the girl, which is 490 N.
Horizontal Component:
The horizontal component of the force is equal to the tension in the swing ropes. Since the girl is moving with a velocity of 2 m/s upwards in a direction making an angle of 60 degrees with the vertical, the tension can be calculated using the formula:
Tension = (Weight / sinθ)
where θ = 60 degrees
Tension = (490 N) / sin(60°) = 490 N / (√3/2) = 980 N
The horizontal component of the force is equal to the tension, which is 980 N.
Total Force:
To find the total force, we can use the Pythagorean theorem:
Total Force = √(Vertical Component^2 + Horizontal Component^2)
Total Force = √((490 N)^2 + (980 N)^2) = √(240100 N^2) = 490 N
The power delivered can now be calculated using the formula mentioned earlier:
Power = Force x Velocity
Power = (490 N) x (2 m/s) = 980 W
Therefore, the power delivered when the girl is swinging with a velocity of 2 m/s upwards in a direction making an angle of 60 degrees with the vertical is 980 W. Hence, the correct option is a. 980 W.
Community Answer
A 50 kg girl is swinging on a swing from rest . Then , the power deliv...
Answer is 490
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A 50 kg girl is swinging on a swing from rest . Then , the power delivered when moving with a velocity of 2m/s upwards in a direction making an angle of 60 degree with the verticle is - a. 980 W. b . 490W c 490√3. d . 245W?
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A 50 kg girl is swinging on a swing from rest . Then , the power delivered when moving with a velocity of 2m/s upwards in a direction making an angle of 60 degree with the verticle is - a. 980 W. b . 490W c 490√3. d . 245W? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A 50 kg girl is swinging on a swing from rest . Then , the power delivered when moving with a velocity of 2m/s upwards in a direction making an angle of 60 degree with the verticle is - a. 980 W. b . 490W c 490√3. d . 245W? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 50 kg girl is swinging on a swing from rest . Then , the power delivered when moving with a velocity of 2m/s upwards in a direction making an angle of 60 degree with the verticle is - a. 980 W. b . 490W c 490√3. d . 245W?.
A 50 kg girl is swinging on a swing from rest . Then , the power delivered when moving with a velocity of 2m/s upwards in a direction making an angle of 60 degree with the verticle is - a. 980 W. b . 490W c 490√3. d . 245W? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A 50 kg girl is swinging on a swing from rest . Then , the power delivered when moving with a velocity of 2m/s upwards in a direction making an angle of 60 degree with the verticle is - a. 980 W. b . 490W c 490√3. d . 245W? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 50 kg girl is swinging on a swing from rest . Then , the power delivered when moving with a velocity of 2m/s upwards in a direction making an angle of 60 degree with the verticle is - a. 980 W. b . 490W c 490√3. d . 245W?.
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