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A parallel plate capacitor consists of two circular plates with radius R = 10 cm separated by d = 0.5mm. The capacitor is being charged at a uniform rate by applying a changing potential difference between the two plates. Asume that the field is due to displacement current only and that the rate at which the electric field between the plates changes is 5 × 1013 (V/m-s). The displacement current in the capacitor is
- a)1.39 A
- b)13.9 A
- c)139 A
- d)0.139 A
Correct answer is option 'B'. Can you explain this answer?
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A parallel plate capacitor consists of two circular plates with radius...
We need to find the current flowing through the capacitor during charging.
The capacitance of a parallel plate capacitor is given by:
C = εA/d
where ε is the permittivity of the medium between the plates, A is the area of the plates, and d is the distance between them.
In this case, ε is not given, but we can assume it to be the permittivity of free space (8.85 x 10^-12 F/m). A = πR^2 = π(0.1)^2 = 0.0314 m^2. d = 0.5 mm = 0.0005 m.
So,
C = εA/d = (8.85 x 10^-12) x 0.0314 / 0.0005 = 5.57 x 10^-10 F
The potential difference between the plates is changing at a uniform rate, so we can assume that the rate of change of voltage is constant. Let this rate be V/t, where V is the potential difference and t is time.
The electric field between the plates is given by:
E = V/d
So,
dE/dt = d(V/d)/dt = 1/d x dV/dt = 5
The displacement current flowing through the capacitor is given by:
I = ε(dE/dt)A
Substituting the values,
I = (8.85 x 10^-12) x 5 x 0.0314 = 1.39 x 10^-12 A
Therefore, the current flowing through the capacitor during charging is 1.39 x 10^-12 A.
The capacitance of a parallel plate capacitor is given by:
C = εA/d
where ε is the permittivity of the medium between the plates, A is the area of the plates, and d is the distance between them.
In this case, ε is not given, but we can assume it to be the permittivity of free space (8.85 x 10^-12 F/m). A = πR^2 = π(0.1)^2 = 0.0314 m^2. d = 0.5 mm = 0.0005 m.
So,
C = εA/d = (8.85 x 10^-12) x 0.0314 / 0.0005 = 5.57 x 10^-10 F
The potential difference between the plates is changing at a uniform rate, so we can assume that the rate of change of voltage is constant. Let this rate be V/t, where V is the potential difference and t is time.
The electric field between the plates is given by:
E = V/d
So,
dE/dt = d(V/d)/dt = 1/d x dV/dt = 5
The displacement current flowing through the capacitor is given by:
I = ε(dE/dt)A
Substituting the values,
I = (8.85 x 10^-12) x 5 x 0.0314 = 1.39 x 10^-12 A
Therefore, the current flowing through the capacitor during charging is 1.39 x 10^-12 A.
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A parallel plate capacitor consists of two circular plates with radius R = 10 cm separated by d = 0.5mm. The capacitor is being charged at a uniform rate by applying a changing potential difference between the two plates. Asume that the field is due to displacement current only and that the rate at which the electric field between the plates changes is 5 × 1013 (V/m-s). The displacement current in the capacitor isa)1.39 Ab)13.9 Ac)139 Ad)0.139 ACorrect answer is option 'B'. Can you explain this answer?
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A parallel plate capacitor consists of two circular plates with radius R = 10 cm separated by d = 0.5mm. The capacitor is being charged at a uniform rate by applying a changing potential difference between the two plates. Asume that the field is due to displacement current only and that the rate at which the electric field between the plates changes is 5 × 1013 (V/m-s). The displacement current in the capacitor isa)1.39 Ab)13.9 Ac)139 Ad)0.139 ACorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A parallel plate capacitor consists of two circular plates with radius R = 10 cm separated by d = 0.5mm. The capacitor is being charged at a uniform rate by applying a changing potential difference between the two plates. Asume that the field is due to displacement current only and that the rate at which the electric field between the plates changes is 5 × 1013 (V/m-s). The displacement current in the capacitor isa)1.39 Ab)13.9 Ac)139 Ad)0.139 ACorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A parallel plate capacitor consists of two circular plates with radius R = 10 cm separated by d = 0.5mm. The capacitor is being charged at a uniform rate by applying a changing potential difference between the two plates. Asume that the field is due to displacement current only and that the rate at which the electric field between the plates changes is 5 × 1013 (V/m-s). The displacement current in the capacitor isa)1.39 Ab)13.9 Ac)139 Ad)0.139 ACorrect answer is option 'B'. Can you explain this answer?.
A parallel plate capacitor consists of two circular plates with radius R = 10 cm separated by d = 0.5mm. The capacitor is being charged at a uniform rate by applying a changing potential difference between the two plates. Asume that the field is due to displacement current only and that the rate at which the electric field between the plates changes is 5 × 1013 (V/m-s). The displacement current in the capacitor isa)1.39 Ab)13.9 Ac)139 Ad)0.139 ACorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A parallel plate capacitor consists of two circular plates with radius R = 10 cm separated by d = 0.5mm. The capacitor is being charged at a uniform rate by applying a changing potential difference between the two plates. Asume that the field is due to displacement current only and that the rate at which the electric field between the plates changes is 5 × 1013 (V/m-s). The displacement current in the capacitor isa)1.39 Ab)13.9 Ac)139 Ad)0.139 ACorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A parallel plate capacitor consists of two circular plates with radius R = 10 cm separated by d = 0.5mm. The capacitor is being charged at a uniform rate by applying a changing potential difference between the two plates. Asume that the field is due to displacement current only and that the rate at which the electric field between the plates changes is 5 × 1013 (V/m-s). The displacement current in the capacitor isa)1.39 Ab)13.9 Ac)139 Ad)0.139 ACorrect answer is option 'B'. Can you explain this answer?.
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