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The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is:
  • a)
    276
  • b)
    299
  • c)
    322
  • d)
    345
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The H.C.F. of two numbers is 23 and the other two factors of their L.C...
Clearly, the numbers are (23 x 13) and (23 x 14).

 Larger number = (23 x 14) = 322.
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The H.C.F. of two numbers is 23 and the other two factors of their L.C...
Given: H.C.F. = 23, L.C.M. factors = 13, 14

To find: Larger of two numbers

Let the two numbers be x and y

Hence, we can write:

x = 23a, y = 23b, where a and b are co-prime

L.C.M. of x and y = 23*13*14

We know that L.C.M. * H.C.F. = x * y

So, we can write:

23*13*14*23 = x * y * 23

x * y = 23^2 * 13 * 14

Now, we have two equations:

x = 23a, y = 23b

x * y = 23^2 * 13 * 14

Substituting the values, we get:

23a * 23b = 23^2 * 13 * 14

a * b = 23 * 13 * 14

Now, since a and b are co-prime, they must be 13 and 14 in some order.

If a = 13 and b = 14, then x = 23a = 23*13 = 299 and y = 23b = 23*14 = 322

If a = 14 and b = 13, then x = 23a = 23*14 = 322 and y = 23b = 23*13 = 299

Hence, the larger of the two numbers is 322.
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The H.C.F. of two numbers is 23 and the other two factors of their L.C...
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The H.C.F. of two numbers is 23 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is:a)276b)299c)322d)345Correct answer is option 'C'. Can you explain this answer?
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