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A body is moving with velocity 30 m/s towards east. After 10 seconds its velocity becomes 40 m/s towards north. The average acceleration of the body is [2011]
- a)1 m/s2
- b)6 m/s2
- c)7 m/s2
- d)5 m/s2
Correct answer is option 'D'. Can you explain this answer?
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A body is moving with velocity 30 m/s towards east. After 10 seconds i...
Average acceleration
< a > = 5 m/sec2
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A body is moving with velocity 30 m/s towards east. After 10 seconds i...
Given data:
Initial velocity (u) = 30 m/s towards east
Final velocity (v) = 40 m/s towards north
Time taken (t) = 10 seconds
To find:
Average acceleration (a)
Explanation:
Step 1: Finding the change in velocity
The change in velocity (∆v) can be found by subtracting the initial velocity from the final velocity.
∆v = v - u
The initial velocity is towards east and the final velocity is towards north, which are perpendicular directions. Therefore, we can use the Pythagorean theorem to find the magnitude of the change in velocity (∆v).
∆v = √[(v_x)^2 + (v_y)^2]
Where,
v_x = magnitude of velocity towards east = 30 m/s
v_y = magnitude of velocity towards north = 40 m/s
∆v = √[(30)^2 + (40)^2]
∆v = √[900 + 1600]
∆v = √2500
∆v = 50 m/s
Step 2: Finding the average acceleration
The average acceleration (a) can be calculated using the formula:
a = ∆v / t
Substituting the values,
a = 50 m/s / 10 s
a = 5 m/s²
Therefore, the average acceleration of the body is 5 m/s².
Conclusion:
The correct answer is option D) 5 m/s².
Initial velocity (u) = 30 m/s towards east
Final velocity (v) = 40 m/s towards north
Time taken (t) = 10 seconds
To find:
Average acceleration (a)
Explanation:
Step 1: Finding the change in velocity
The change in velocity (∆v) can be found by subtracting the initial velocity from the final velocity.
∆v = v - u
The initial velocity is towards east and the final velocity is towards north, which are perpendicular directions. Therefore, we can use the Pythagorean theorem to find the magnitude of the change in velocity (∆v).
∆v = √[(v_x)^2 + (v_y)^2]
Where,
v_x = magnitude of velocity towards east = 30 m/s
v_y = magnitude of velocity towards north = 40 m/s
∆v = √[(30)^2 + (40)^2]
∆v = √[900 + 1600]
∆v = √2500
∆v = 50 m/s
Step 2: Finding the average acceleration
The average acceleration (a) can be calculated using the formula:
a = ∆v / t
Substituting the values,
a = 50 m/s / 10 s
a = 5 m/s²
Therefore, the average acceleration of the body is 5 m/s².
Conclusion:
The correct answer is option D) 5 m/s².
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A body is moving with velocity 30 m/s towards east. After 10 seconds its velocity becomes 40 m/s towards north. The average acceleration of the body is [2011]a)1 m/s2b)6 m/s2c)7 m/s2d)5 m/s2Correct answer is option 'D'. Can you explain this answer?
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A body is moving with velocity 30 m/s towards east. After 10 seconds its velocity becomes 40 m/s towards north. The average acceleration of the body is [2011]a)1 m/s2b)6 m/s2c)7 m/s2d)5 m/s2Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body is moving with velocity 30 m/s towards east. After 10 seconds its velocity becomes 40 m/s towards north. The average acceleration of the body is [2011]a)1 m/s2b)6 m/s2c)7 m/s2d)5 m/s2Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body is moving with velocity 30 m/s towards east. After 10 seconds its velocity becomes 40 m/s towards north. The average acceleration of the body is [2011]a)1 m/s2b)6 m/s2c)7 m/s2d)5 m/s2Correct answer is option 'D'. Can you explain this answer?.
A body is moving with velocity 30 m/s towards east. After 10 seconds its velocity becomes 40 m/s towards north. The average acceleration of the body is [2011]a)1 m/s2b)6 m/s2c)7 m/s2d)5 m/s2Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body is moving with velocity 30 m/s towards east. After 10 seconds its velocity becomes 40 m/s towards north. The average acceleration of the body is [2011]a)1 m/s2b)6 m/s2c)7 m/s2d)5 m/s2Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body is moving with velocity 30 m/s towards east. After 10 seconds its velocity becomes 40 m/s towards north. The average acceleration of the body is [2011]a)1 m/s2b)6 m/s2c)7 m/s2d)5 m/s2Correct answer is option 'D'. Can you explain this answer?.
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