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Calculate the depletion width of a Silicon P-N junction with ND=10^16/cm3 and NA = 10^18/cm3 at 300 K. Assume ni = 1010 cm-3, ɛs = ɛ0 x ɛSi = 8.854x10^-14 F/cm x 11.7?
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Calculate the depletion width of a Silicon P-N junction with ND=10^16/...
Calculate the depletion width of a Silicon P-N junction with ND=10^16/cm3 and NA = 10^18/cm3 at 300 K. Assume ni = 1010 cm-3, ɛs = ɛ0 x ɛSi = 8.854x10^-14 F/cm x 11.7.
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Calculate the depletion width of a Silicon P-N junction with ND=10^16/...
Depletion Width Calculation for a Silicon P-N Junction

Given Data:
- ND (Donor concentration) = 10^16/cm^3
- NA (Acceptor concentration) = 10^18/cm^3
- Temperature (T) = 300 K
- Intrinsic carrier concentration (ni) = 10^10 cm^-3
- Permittivity of free space (ε0) = 8.854 x 10^-14 F/cm
- Relative permittivity of Silicon (εSi) = 11.7

Depletion Width (W) Formula:
The depletion width of a P-N junction can be calculated using the formula:

W = sqrt((2 * εs * (Vbi + VR)) / (e * (1/ND + 1/NA)))

Where:
- W is the depletion width
- εs is the effective permittivity of the semiconductor
- Vbi is the built-in potential
- VR is the applied reverse bias voltage
- e is the elementary charge (1.6 x 10^-19 C)

Calculation Steps:

Step 1: Calculate the Effective Permittivity (εs)
The effective permittivity (εs) is calculated by multiplying the permittivity of free space (ε0) by the relative permittivity of Silicon (εSi).

εs = ε0 x εSi
= (8.854 x 10^-14 F/cm) x (11.7)
= 1.034 x 10^-12 F/cm

Step 2: Calculate the Built-in Potential (Vbi)
The built-in potential (Vbi) is calculated using the following formula:

Vbi = (k * T / e) * ln(NA * ND / (ni^2))

Where:
- k is Boltzmann's constant (8.617 x 10^-5 eV/K)
- T is the temperature in Kelvin
- e is the elementary charge (1.6 x 10^-19 C)
- ln is the natural logarithm function

Vbi = (8.617 x 10^-5 eV/K * 300 K / 1.6 x 10^-19 C) * ln((10^18/cm^3 * 10^16/cm^3) / (10^10 cm^-3)^2)
= 0.026 V * ln(10^34 / 10^20)
= 0.026 V * ln(10^14)
= 0.026 V * 31.83
= 0.827 V

Step 3: Calculate the Depletion Width (W)
Substituting the values into the depletion width formula:

W = sqrt((2 * εs * (Vbi + VR)) / (e * (1/ND + 1/NA)))
= sqrt((2 * 1.034 x 10^-12 F/cm * (0.827 V + VR)) / (1.6 x 10^-19 C * (1/10^16/cm^3 + 1/10^18/cm^3)))

Let's assume VR = 0 V for simplicity:

W = sqrt((2 * 1.034
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Calculate the depletion width of a Silicon P-N junction with ND=10^16/cm3 and NA = 10^18/cm3 at 300 K. Assume ni = 1010 cm-3, ɛs = ɛ0 x ɛSi = 8.854x10^-14 F/cm x 11.7?
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Calculate the depletion width of a Silicon P-N junction with ND=10^16/cm3 and NA = 10^18/cm3 at 300 K. Assume ni = 1010 cm-3, ɛs = ɛ0 x ɛSi = 8.854x10^-14 F/cm x 11.7? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about Calculate the depletion width of a Silicon P-N junction with ND=10^16/cm3 and NA = 10^18/cm3 at 300 K. Assume ni = 1010 cm-3, ɛs = ɛ0 x ɛSi = 8.854x10^-14 F/cm x 11.7? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the depletion width of a Silicon P-N junction with ND=10^16/cm3 and NA = 10^18/cm3 at 300 K. Assume ni = 1010 cm-3, ɛs = ɛ0 x ɛSi = 8.854x10^-14 F/cm x 11.7?.
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