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Consider a silicon n+p junction solar cell with a 1 cm2 surface area and NA = 1015/cm3. Calculate IL (light current) and Voc (open circuit voltage).
Assume Dn = 35cm2sec-1, τn = 2.57 μsec and GL = 2.7 × 1019 cm3 sec-1, VT = 25.86 x 10-3 V, ni = 1.5 x 1010 cm3.
- a)IL = 1.33 x 10-10 A, VOC = 0.505 V
- b)IL = 40.95 mA, VOC = 0.505 V
- c)IL = 1.33 x 10-10 A, VOC = 0.852 V
- d)IL = 40.95 mA, VOC = 0.852 V
Correct answer is option 'B'. Can you explain this answer?
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Calculating IL (light current) and Voc (open circuit voltage)
1. Calculating IL (light current):
Given parameters:
- NA = 10^15/cm^3
- Dn = 35 cm^2/sec
- τn = 2.57 μsec
- GL = 2.7 x 10^19 cm^3 sec^-1
- VT = 25.86 x 10^-3 V
- ni = 1.5 x 10^10 cm^3
Using the formula for IL:
IL = q * GL * τn * NA * VT / (2 * Dn)
Substitute the values and calculate IL.
2. Calculating Voc (open circuit voltage):
Given parameters:
- NA = 10^15/cm^3
- ni = 1.5 x 10^10 cm^3
- VT = 25.86 x 10^-3 V
Using the formula for Voc:
Voc = (VT * ln(NA / ni))
Substitute the values and calculate Voc.
Therefore, after the calculations, we find that the correct answer is option 'B':
- IL = 40.95 mA
- VOC = 0.505 V
These values are obtained by accurately applying the formulas and substituting the given parameters.
1. Calculating IL (light current):
Given parameters:
- NA = 10^15/cm^3
- Dn = 35 cm^2/sec
- τn = 2.57 μsec
- GL = 2.7 x 10^19 cm^3 sec^-1
- VT = 25.86 x 10^-3 V
- ni = 1.5 x 10^10 cm^3
Using the formula for IL:
IL = q * GL * τn * NA * VT / (2 * Dn)
Substitute the values and calculate IL.
2. Calculating Voc (open circuit voltage):
Given parameters:
- NA = 10^15/cm^3
- ni = 1.5 x 10^10 cm^3
- VT = 25.86 x 10^-3 V
Using the formula for Voc:
Voc = (VT * ln(NA / ni))
Substitute the values and calculate Voc.
Therefore, after the calculations, we find that the correct answer is option 'B':
- IL = 40.95 mA
- VOC = 0.505 V
These values are obtained by accurately applying the formulas and substituting the given parameters.
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Consider a silicon n+p junction solar cell with a 1 cm2 surface area and NA = 1015/cm3. Calculate IL (light current) and Voc (open circuit voltage).Assume Dn = 35cm2sec-1, τn = 2.57 μsec and GL = 2.7 × 1019 cm3 sec-1, VT = 25.86 x 10-3 V, ni = 1.5 x 1010 cm3.a)IL = 1.33 x 10-10 A, VOC = 0.505 Vb)IL = 40.95 mA, VOC = 0.505 Vc)IL = 1.33 x 10-10 A, VOC = 0.852 Vd)IL = 40.95 mA, VOC = 0.852 VCorrect answer is option 'B'. Can you explain this answer?
Question Description
Consider a silicon n+p junction solar cell with a 1 cm2 surface area and NA = 1015/cm3. Calculate IL (light current) and Voc (open circuit voltage).Assume Dn = 35cm2sec-1, τn = 2.57 μsec and GL = 2.7 × 1019 cm3 sec-1, VT = 25.86 x 10-3 V, ni = 1.5 x 1010 cm3.a)IL = 1.33 x 10-10 A, VOC = 0.505 Vb)IL = 40.95 mA, VOC = 0.505 Vc)IL = 1.33 x 10-10 A, VOC = 0.852 Vd)IL = 40.95 mA, VOC = 0.852 VCorrect answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about Consider a silicon n+p junction solar cell with a 1 cm2 surface area and NA = 1015/cm3. Calculate IL (light current) and Voc (open circuit voltage).Assume Dn = 35cm2sec-1, τn = 2.57 μsec and GL = 2.7 × 1019 cm3 sec-1, VT = 25.86 x 10-3 V, ni = 1.5 x 1010 cm3.a)IL = 1.33 x 10-10 A, VOC = 0.505 Vb)IL = 40.95 mA, VOC = 0.505 Vc)IL = 1.33 x 10-10 A, VOC = 0.852 Vd)IL = 40.95 mA, VOC = 0.852 VCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a silicon n+p junction solar cell with a 1 cm2 surface area and NA = 1015/cm3. Calculate IL (light current) and Voc (open circuit voltage).Assume Dn = 35cm2sec-1, τn = 2.57 μsec and GL = 2.7 × 1019 cm3 sec-1, VT = 25.86 x 10-3 V, ni = 1.5 x 1010 cm3.a)IL = 1.33 x 10-10 A, VOC = 0.505 Vb)IL = 40.95 mA, VOC = 0.505 Vc)IL = 1.33 x 10-10 A, VOC = 0.852 Vd)IL = 40.95 mA, VOC = 0.852 VCorrect answer is option 'B'. Can you explain this answer?.
Consider a silicon n+p junction solar cell with a 1 cm2 surface area and NA = 1015/cm3. Calculate IL (light current) and Voc (open circuit voltage).Assume Dn = 35cm2sec-1, τn = 2.57 μsec and GL = 2.7 × 1019 cm3 sec-1, VT = 25.86 x 10-3 V, ni = 1.5 x 1010 cm3.a)IL = 1.33 x 10-10 A, VOC = 0.505 Vb)IL = 40.95 mA, VOC = 0.505 Vc)IL = 1.33 x 10-10 A, VOC = 0.852 Vd)IL = 40.95 mA, VOC = 0.852 VCorrect answer is option 'B'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about Consider a silicon n+p junction solar cell with a 1 cm2 surface area and NA = 1015/cm3. Calculate IL (light current) and Voc (open circuit voltage).Assume Dn = 35cm2sec-1, τn = 2.57 μsec and GL = 2.7 × 1019 cm3 sec-1, VT = 25.86 x 10-3 V, ni = 1.5 x 1010 cm3.a)IL = 1.33 x 10-10 A, VOC = 0.505 Vb)IL = 40.95 mA, VOC = 0.505 Vc)IL = 1.33 x 10-10 A, VOC = 0.852 Vd)IL = 40.95 mA, VOC = 0.852 VCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a silicon n+p junction solar cell with a 1 cm2 surface area and NA = 1015/cm3. Calculate IL (light current) and Voc (open circuit voltage).Assume Dn = 35cm2sec-1, τn = 2.57 μsec and GL = 2.7 × 1019 cm3 sec-1, VT = 25.86 x 10-3 V, ni = 1.5 x 1010 cm3.a)IL = 1.33 x 10-10 A, VOC = 0.505 Vb)IL = 40.95 mA, VOC = 0.505 Vc)IL = 1.33 x 10-10 A, VOC = 0.852 Vd)IL = 40.95 mA, VOC = 0.852 VCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Consider a silicon n+p junction solar cell with a 1 cm2 surface area and NA = 1015/cm3. Calculate IL (light current) and Voc (open circuit voltage).Assume Dn = 35cm2sec-1, τn = 2.57 μsec and GL = 2.7 × 1019 cm3 sec-1, VT = 25.86 x 10-3 V, ni = 1.5 x 1010 cm3.a)IL = 1.33 x 10-10 A, VOC = 0.505 Vb)IL = 40.95 mA, VOC = 0.505 Vc)IL = 1.33 x 10-10 A, VOC = 0.852 Vd)IL = 40.95 mA, VOC = 0.852 VCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE).
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Here you can find the meaning of Consider a silicon n+p junction solar cell with a 1 cm2 surface area and NA = 1015/cm3. Calculate IL (light current) and Voc (open circuit voltage).Assume Dn = 35cm2sec-1, τn = 2.57 μsec and GL = 2.7 × 1019 cm3 sec-1, VT = 25.86 x 10-3 V, ni = 1.5 x 1010 cm3.a)IL = 1.33 x 10-10 A, VOC = 0.505 Vb)IL = 40.95 mA, VOC = 0.505 Vc)IL = 1.33 x 10-10 A, VOC = 0.852 Vd)IL = 40.95 mA, VOC = 0.852 VCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Consider a silicon n+p junction solar cell with a 1 cm2 surface area and NA = 1015/cm3. Calculate IL (light current) and Voc (open circuit voltage).Assume Dn = 35cm2sec-1, τn = 2.57 μsec and GL = 2.7 × 1019 cm3 sec-1, VT = 25.86 x 10-3 V, ni = 1.5 x 1010 cm3.a)IL = 1.33 x 10-10 A, VOC = 0.505 Vb)IL = 40.95 mA, VOC = 0.505 Vc)IL = 1.33 x 10-10 A, VOC = 0.852 Vd)IL = 40.95 mA, VOC = 0.852 VCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Consider a silicon n+p junction solar cell with a 1 cm2 surface area and NA = 1015/cm3. Calculate IL (light current) and Voc (open circuit voltage).Assume Dn = 35cm2sec-1, τn = 2.57 μsec and GL = 2.7 × 1019 cm3 sec-1, VT = 25.86 x 10-3 V, ni = 1.5 x 1010 cm3.a)IL = 1.33 x 10-10 A, VOC = 0.505 Vb)IL = 40.95 mA, VOC = 0.505 Vc)IL = 1.33 x 10-10 A, VOC = 0.852 Vd)IL = 40.95 mA, VOC = 0.852 VCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Consider a silicon n+p junction solar cell with a 1 cm2 surface area and NA = 1015/cm3. Calculate IL (light current) and Voc (open circuit voltage).Assume Dn = 35cm2sec-1, τn = 2.57 μsec and GL = 2.7 × 1019 cm3 sec-1, VT = 25.86 x 10-3 V, ni = 1.5 x 1010 cm3.a)IL = 1.33 x 10-10 A, VOC = 0.505 Vb)IL = 40.95 mA, VOC = 0.505 Vc)IL = 1.33 x 10-10 A, VOC = 0.852 Vd)IL = 40.95 mA, VOC = 0.852 VCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Consider a silicon n+p junction solar cell with a 1 cm2 surface area and NA = 1015/cm3. Calculate IL (light current) and Voc (open circuit voltage).Assume Dn = 35cm2sec-1, τn = 2.57 μsec and GL = 2.7 × 1019 cm3 sec-1, VT = 25.86 x 10-3 V, ni = 1.5 x 1010 cm3.a)IL = 1.33 x 10-10 A, VOC = 0.505 Vb)IL = 40.95 mA, VOC = 0.505 Vc)IL = 1.33 x 10-10 A, VOC = 0.852 Vd)IL = 40.95 mA, VOC = 0.852 VCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Electronics and Communication Engineering (ECE) tests.
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