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The reagent silver sulphate solution is used to separate
- a)Nitrate and bromide
- b)Nitrate and chlorate
- c)Bromide and iodide
- d)Nitrate and nitrite
Correct answer is option 'A'. Can you explain this answer?
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The reagent silver sulphate solution is used to separatea)Nitrate and ...
Silver Sulphate Solution for Separation
The reagent silver sulphate solution is commonly used to separate ions based on their solubility in water. Specifically, it can be used to separate nitrate and bromide ions.
Solubility of Silver Bromide
When silver sulphate solution is added to a solution containing both nitrate and bromide ions, a white precipitate of silver bromide forms. This is because silver bromide is insoluble in water and forms a solid precipitate.
Solubility of Silver Nitrate
In contrast, silver nitrate is highly soluble in water and does not form a precipitate when silver sulphate solution is added. Therefore, the nitrate ions remain in solution while the bromide ions are separated as a solid.
Other Separations
Silver sulphate solution can also be used to separate other combinations of ions based on their solubility. For example:
- Nitrate and chloride ions can be separated using silver nitrate solution, which forms a white precipitate of silver chloride.
- Bromide and iodide ions can be separated using chlorine water, which oxidizes iodide ions to form iodine, which can then react with starch to form a blue-black color. Bromide ions do not react with chlorine water and remain in solution.
- Nitrate and nitrite ions can be separated using sulfamic acid, which converts nitrite ions to nitrous acid. Nitrous acid then reacts with sulfamic acid to form a white precipitate, while nitrate ions remain in solution.
The reagent silver sulphate solution is commonly used to separate ions based on their solubility in water. Specifically, it can be used to separate nitrate and bromide ions.
Solubility of Silver Bromide
When silver sulphate solution is added to a solution containing both nitrate and bromide ions, a white precipitate of silver bromide forms. This is because silver bromide is insoluble in water and forms a solid precipitate.
Solubility of Silver Nitrate
In contrast, silver nitrate is highly soluble in water and does not form a precipitate when silver sulphate solution is added. Therefore, the nitrate ions remain in solution while the bromide ions are separated as a solid.
Other Separations
Silver sulphate solution can also be used to separate other combinations of ions based on their solubility. For example:
- Nitrate and chloride ions can be separated using silver nitrate solution, which forms a white precipitate of silver chloride.
- Bromide and iodide ions can be separated using chlorine water, which oxidizes iodide ions to form iodine, which can then react with starch to form a blue-black color. Bromide ions do not react with chlorine water and remain in solution.
- Nitrate and nitrite ions can be separated using sulfamic acid, which converts nitrite ions to nitrous acid. Nitrous acid then reacts with sulfamic acid to form a white precipitate, while nitrate ions remain in solution.
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The reagent silver sulphate solution is used to separatea)Nitrate and ...
Silver can form precipitate with bromide but not with nitrate so its option (a)
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The reagent silver sulphate solution is used to separatea)Nitrate and bromideb)Nitrate and chloratec)Bromide and iodided)Nitrate and nitriteCorrect answer is option 'A'. Can you explain this answer?
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