Calculating the Normality of a Hydrogen Peroxide Solution

To calculate the normality of a hydrogen peroxide solution, you need to know the volume of the solution and its molarity. The formula for normality is:

Normality = Molarity x Number of equivalents

In the case of hydrogen peroxide, each molecule has two equivalents of reactive oxygen, so the number of equivalents is twice the molarity.

Given:

Volume of H2O2 solution = 10 ml

Molarity of H2O2 solution = 20 V

To calculate the normality of the solution, you need to convert the volume from milliliters to liters:

Volume = 10 ml = 0.01 L

Next, you need to convert the "20V" notation to molarity. "V" stands for volume, so a "20V" solution means that it contains 20 volumes of oxygen peroxide in 100 ml of solution. One volume of hydrogen peroxide contains 11.2 milligrams of oxygen. Therefore, the molarity of a "20V" solution is:

Molarity = (20 x 11.2 mg) / 1000 mg/g = 0.224 M

Now you can calculate the normality of the solution:

Normality = Molarity x Number of equivalents

Number of equivalents = 2 (because each H2O2 molecule has 2 equivalents of reactive oxygen)

Normality = 0.224 M x 2 = 0.448 N

Therefore, the normality of the 10 ml "20V" H2O2 solution is 0.448 N, which corresponds to option B) 3.58.