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10ml of an HCl solution gave 0.1435g AgCl when treated with excess of AgNO3. The normality of the resulting solution is a)0.1 b)3 c)0.3 d)0.2 can u explain the answer plz?
Most Upvoted Answer
10ml of an HCl solution gave 0.1435g AgCl when treated with excess of ...
Given Data:
- Volume of HCl solution = 10ml
- Mass of AgCl formed = 0.1435g
Calculating Normality:
1. Calculate the moles of AgCl formed:
- The molar mass of AgCl = 107.87 (Ag: 107.87, Cl: 35.45)
- Moles of AgCl = Mass / Molar mass = 0.1435g / 143.32g/mol ≈ 1 x 10^-3 mol
2. Since AgNO3 is in excess, the moles of Cl- ions in HCl are equal to the moles of AgCl formed:
- Moles of Cl- ions = 1 x 10^-3 mol
3. Normality is defined as the number of equivalents per liter of solution:
- Normality = (Moles of Cl- ions / Volume of solution in liters) x n factor
- Since HCl dissociates into 1 H+ ion and 1 Cl- ion, the n factor is 1 for HCl
- Volume of solution in liters = 10ml = 10 x 10^-3 L
- Normality = (1 x 10^-3 mol / 10 x 10^-3 L) x 1 = 0.1 N
Answer:
The normality of the resulting solution is a) 0.1 N.
Community Answer
10ml of an HCl solution gave 0.1435g AgCl when treated with excess of ...
N =w*1000/ew*v
0.1435*1000/143.5*10
=0.1
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10ml of an HCl solution gave 0.1435g AgCl when treated with excess of AgNO3. The normality of the resulting solution is a)0.1 b)3 c)0.3 d)0.2 can u explain the answer plz?
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10ml of an HCl solution gave 0.1435g AgCl when treated with excess of AgNO3. The normality of the resulting solution is a)0.1 b)3 c)0.3 d)0.2 can u explain the answer plz? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 10ml of an HCl solution gave 0.1435g AgCl when treated with excess of AgNO3. The normality of the resulting solution is a)0.1 b)3 c)0.3 d)0.2 can u explain the answer plz? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 10ml of an HCl solution gave 0.1435g AgCl when treated with excess of AgNO3. The normality of the resulting solution is a)0.1 b)3 c)0.3 d)0.2 can u explain the answer plz?.
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