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The normality of a solution of mixture containing HCl and H2SO4 is N/5. Twenty millimeters of this solution reacts with excess of AgNO3 solution to give 0.287g of AgCl. The percentage of HCl in the mixture by mass is a)42.69% b)57.3% c)50% d)25%?
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The normality of a solution of mixture containing HCl and H2SO4 is N/5...
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The normality of a solution of mixture containing HCl and H2SO4 is N/5. Twenty millimeters of this solution reacts with excess of AgNO3 solution to give 0.287g of AgCl. The percentage of HCl in the mixture by mass is a)42.69% b)57.3% c)50% d)25%? Explain in details.
Solution:
To find the percentage of HCl in the mixture by mass, we need to determine the amount of HCl present in the solution.
Step 1: Calculate the number of moles of AgCl formed:
We are given that 20 milliliters of the solution reacts with excess AgNO3 to form 0.287 grams of AgCl.
The molar mass of AgCl is 143.32 g/mol.
Using the formula n = m/M, where n is the number of moles, m is the mass, and M is the molar mass, we can calculate the number of moles of AgCl formed.
n(AgCl) = 0.287g / 143.32 g/mol = 0.002 moles
Step 2: Calculate the number of moles of HCl:
Since AgNO3 reacts with Cl- ions to form AgCl, the number of moles of AgCl formed is equal to the number of moles of Cl- ions present in the solution.
Since AgNO3 is in excess, we can assume that all the Cl- ions come from HCl. Therefore, the number of moles of HCl is also 0.002 moles.
Step 3: Calculate the volume of the solution:
The normality of the solution is given as N/5. Normality is defined as the number of gram equivalents of solute per liter of solution.
Since the normality is N/5, it means the number of gram equivalents of solute in 1 liter of solution is N. Therefore, the number of gram equivalents in 20 milliliters of solution is N/50.
To find the volume of the solution, we can use the formula N = n/V, where N is the normality, n is the number of gram equivalents, and V is the volume in liters.
N/5 = (N/50) / V
V = 10 liters
Step 4: Calculate the number of moles of HCl in the solution:
Since the normality is N/5, the number of gram equivalents of HCl in 10 liters of solution is N. Therefore, the number of moles of HCl in the solution is N/5.
Step 5: Calculate the mass of HCl:
We know that the molar mass of HCl is 36.46 g/mol. Using the formula m = nM, where m is the mass, n is the number of moles, and M is the molar mass, we can calculate the mass of HCl.
m(HCl) = (N/5) * 36.46 g/mol
Step 6: Calculate the percentage of HCl:
The percentage of HCl in the mixture by mass is calculated by dividing the mass of HCl by the total
The normality of a solution of mixture containing HCl and H2SO4 is N/5. Twenty millimeters of this solution reacts with excess of AgNO3 solution to give 0.287g of AgCl. The percentage of HCl in the mixture by mass is a)42.69% b)57.3% c)50% d)25%? Explain in details.
Solution:
To find the percentage of HCl in the mixture by mass, we need to determine the amount of HCl present in the solution.
Step 1: Calculate the number of moles of AgCl formed:
We are given that 20 milliliters of the solution reacts with excess AgNO3 to form 0.287 grams of AgCl.
The molar mass of AgCl is 143.32 g/mol.
Using the formula n = m/M, where n is the number of moles, m is the mass, and M is the molar mass, we can calculate the number of moles of AgCl formed.
n(AgCl) = 0.287g / 143.32 g/mol = 0.002 moles
Step 2: Calculate the number of moles of HCl:
Since AgNO3 reacts with Cl- ions to form AgCl, the number of moles of AgCl formed is equal to the number of moles of Cl- ions present in the solution.
Since AgNO3 is in excess, we can assume that all the Cl- ions come from HCl. Therefore, the number of moles of HCl is also 0.002 moles.
Step 3: Calculate the volume of the solution:
The normality of the solution is given as N/5. Normality is defined as the number of gram equivalents of solute per liter of solution.
Since the normality is N/5, it means the number of gram equivalents of solute in 1 liter of solution is N. Therefore, the number of gram equivalents in 20 milliliters of solution is N/50.
To find the volume of the solution, we can use the formula N = n/V, where N is the normality, n is the number of gram equivalents, and V is the volume in liters.
N/5 = (N/50) / V
V = 10 liters
Step 4: Calculate the number of moles of HCl in the solution:
Since the normality is N/5, the number of gram equivalents of HCl in 10 liters of solution is N. Therefore, the number of moles of HCl in the solution is N/5.
Step 5: Calculate the mass of HCl:
We know that the molar mass of HCl is 36.46 g/mol. Using the formula m = nM, where m is the mass, n is the number of moles, and M is the molar mass, we can calculate the mass of HCl.
m(HCl) = (N/5) * 36.46 g/mol
Step 6: Calculate the percentage of HCl:
The percentage of HCl in the mixture by mass is calculated by dividing the mass of HCl by the total
Community Answer
The normality of a solution of mixture containing HCl and H2SO4 is N/5...
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The normality of a solution of mixture containing HCl and H2SO4 is N/5. Twenty millimeters of this solution reacts with excess of AgNO3 solution to give 0.287g of AgCl. The percentage of HCl in the mixture by mass is a)42.69% b)57.3% c)50% d)25%?
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The normality of a solution of mixture containing HCl and H2SO4 is N/5. Twenty millimeters of this solution reacts with excess of AgNO3 solution to give 0.287g of AgCl. The percentage of HCl in the mixture by mass is a)42.69% b)57.3% c)50% d)25%? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The normality of a solution of mixture containing HCl and H2SO4 is N/5. Twenty millimeters of this solution reacts with excess of AgNO3 solution to give 0.287g of AgCl. The percentage of HCl in the mixture by mass is a)42.69% b)57.3% c)50% d)25%? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The normality of a solution of mixture containing HCl and H2SO4 is N/5. Twenty millimeters of this solution reacts with excess of AgNO3 solution to give 0.287g of AgCl. The percentage of HCl in the mixture by mass is a)42.69% b)57.3% c)50% d)25%?.
The normality of a solution of mixture containing HCl and H2SO4 is N/5. Twenty millimeters of this solution reacts with excess of AgNO3 solution to give 0.287g of AgCl. The percentage of HCl in the mixture by mass is a)42.69% b)57.3% c)50% d)25%? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The normality of a solution of mixture containing HCl and H2SO4 is N/5. Twenty millimeters of this solution reacts with excess of AgNO3 solution to give 0.287g of AgCl. The percentage of HCl in the mixture by mass is a)42.69% b)57.3% c)50% d)25%? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The normality of a solution of mixture containing HCl and H2SO4 is N/5. Twenty millimeters of this solution reacts with excess of AgNO3 solution to give 0.287g of AgCl. The percentage of HCl in the mixture by mass is a)42.69% b)57.3% c)50% d)25%?.
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