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Calculation of Normality of HCL Solution
Given Information:
- Normality of the mixture = 0.5 N
- Volume of the mixture = 20 ml
- Mass of AgCl produced = 287 grams
Step 1: Calculation of Number of Moles of AgCl
We know that the reaction between HCl and AgNO3 is as follows:
HCl + AgNO3 → AgCl + HNO3
From the given information, we can calculate the number of moles of AgCl produced as follows:
Number of moles of AgCl = Mass of AgCl / Molar mass of AgCl
= 287 / 143.5 (Molar mass of AgCl)
= 2 moles
Step 2: Calculation of Number of Moles of HCl
From the balanced chemical equation, we know that one mole of HCl reacts with one mole of AgNO3 to produce one mole of AgCl. Therefore, the number of moles of HCl can be calculated as follows:
Number of moles of HCl = Number of moles of AgCl
= 2 moles
Step 3: Calculation of Volume of HCl Solution
We know that the volume of the mixture is 20 ml. Therefore, the volume of HCl in the mixture can be calculated as follows:
Volume of HCl in the mixture = Volume of mixture * Normality of HCl in the mixture / Normality of the mixture
= 20 * x / 0.5 (Let the normality of HCl in the mixture be x)
= 400 ml
Step 4: Calculation of Normality of HCl Solution
From the above calculations, we know that the volume of HCl in the mixture is 400 ml and the number of moles of HCl in the mixture is 2 moles. Therefore, the normality of HCl can be calculated as follows:
Normality of HCl = Number of moles of HCl / Volume of HCl in liters
= 2 / (400 / 1000)
= 5 N
Conclusion
The normality of the HCl solution is 5 N.