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An ideal gas has a volume of V at 2 atm pressure. Keeping the temprature of gas constant, its pressure is doubled. The volume of gas will become
- a)0.5 V
- b)V
- c)2 V
- d)4 V
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
An ideal gas has a volume of V at 2 atm pressure. Keeping the tempratu...
Explanation:
To solve this problem, we can use the ideal gas law, which states that the pressure (P), volume (V), and temperature (T) of an ideal gas are related by the equation PV = nRT, where n is the number of moles of gas and R is the ideal gas constant.
Given that the temperature of the gas is constant, we can rewrite the ideal gas law as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
In this case, the initial pressure (P1) is 2 atm, and the final pressure (P2) is 4 atm (double the initial pressure). We want to find the final volume (V2).
Step 1:
Using the ideal gas law equation, we can write:
P1V1 = P2V2
Step 2:
Plugging in the given values, we have:
2 atm * V1 = 4 atm * V2
Step 3:
Simplifying the equation, we can cancel out the atm units:
2V1 = 4V2
Step 4:
Dividing both sides of the equation by 2, we get:
V1 = 2V2
Step 5:
Finally, rearranging the equation, we find:
V2 = 0.5V1
Therefore, the volume of the gas will become 0.5 times the initial volume. This means that the correct answer is option 'A' - 0.5V.
To solve this problem, we can use the ideal gas law, which states that the pressure (P), volume (V), and temperature (T) of an ideal gas are related by the equation PV = nRT, where n is the number of moles of gas and R is the ideal gas constant.
Given that the temperature of the gas is constant, we can rewrite the ideal gas law as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
In this case, the initial pressure (P1) is 2 atm, and the final pressure (P2) is 4 atm (double the initial pressure). We want to find the final volume (V2).
Step 1:
Using the ideal gas law equation, we can write:
P1V1 = P2V2
Step 2:
Plugging in the given values, we have:
2 atm * V1 = 4 atm * V2
Step 3:
Simplifying the equation, we can cancel out the atm units:
2V1 = 4V2
Step 4:
Dividing both sides of the equation by 2, we get:
V1 = 2V2
Step 5:
Finally, rearranging the equation, we find:
V2 = 0.5V1
Therefore, the volume of the gas will become 0.5 times the initial volume. This means that the correct answer is option 'A' - 0.5V.
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Community Answer
An ideal gas has a volume of V at 2 atm pressure. Keeping the tempratu...
Pressure (p) is inversely proportional to Volume (V)
so,
P1/P2=V2/V1
2/4=V2/V
1/2=V2/V
V/2=V2
so V2=1/2=0.5V
so,
P1/P2=V2/V1
2/4=V2/V
1/2=V2/V
V/2=V2
so V2=1/2=0.5V
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An ideal gas has a volume of V at 2 atm pressure. Keeping the temprature of gas constant, its pressure is doubled. The volume of gas will becomea)0.5 Vb)Vc)2 Vd)4 VCorrect answer is option 'A'. Can you explain this answer?
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