Two dices are rolled what is the probability of getting the sum perfect cube and divisible by3?

Question

Answer

Probability of getting the sum perfect cube and divisible by 3 when rolling two dices

Understanding the problem: Before calculating the probability, it is important to understand the problem. Rolling two dices means there are 6 x 6 = 36 possible outcomes. The sum of the numbers on the two dices can range from 2 to 12.

Finding the sums divisible by 3: The sums that are divisible by 3 are 3, 6, 9, and 12.

Finding the common outcomes: The common outcomes between the perfect cubes and the sums divisible by 3 are (2, 6), (3, 9), (4, 8), (5, 7), (6, 6), (8, 4), (9, 3), and (12, 6).

Calculating the probability: The probability of getting a perfect cube and a sum divisible by 3 is the number of common outcomes divided by the total number of outcomes. Therefore, the probability is 8/36 or 2/9.

Conclusion

Therefore, the probability of getting the sum perfect cube and divisible by 3 when rolling two dices is 2/9.

Answer

Hey,

The total outcomes when 2 dices are rolled are: 36

1. P[sum is perfect cube] - Sample space [(2,6) (3,5) (4,4) (5,3) (6,2)]

Therefore P= 5/36 - These numbers add upto 8 who is the cube of 2.

2. P[sum is divisible by 3] - Sample space[ (1,2) (1,5) (2,1) (2,4) (3,3) (3,6) (4,2) (4,5) (5,1) (5,4) (6,3) (6,6)]

Therefore P= 12/36=1/3

Hope this is the question you meant and if yes, hope this helps you!