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If the person uses spectacles of power + 1.0 Dioptre, What is the nearest distance of distinct vision for him?
- a)300 cm
- b)-33.3 cm
- c)-298 cm
- d)+298 cm
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
If the person uses spectacles of power + 1.0 Dioptre, What is the near...
See here is your answer __!!
here,
Power=+1.0
therefore,
focal length=1m
At the nearest point of distinct vision, all objects from infinite dist. form an image there.
therefore,
by using the relation:
1/f=1/v-1/u
1=1/v-1/(infinity)
so,
v=1m <--- this="" is="" the="" dist.="" of="" nearest="">
hope you get helped
here,
Power=+1.0
therefore,
focal length=1m
At the nearest point of distinct vision, all objects from infinite dist. form an image there.
therefore,
by using the relation:
1/f=1/v-1/u
1=1/v-1/(infinity)
so,
v=1m <--- this="" is="" the="" dist.="" of="" nearest="">
hope you get helped
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Community Answer
If the person uses spectacles of power + 1.0 Dioptre, What is the near...
Explanation:
The power of a lens is measured in dioptres (D). It indicates the ability of the lens to converge or diverge light. A positive power indicates convergence, while a negative power indicates divergence.
The formula to calculate the nearest distance of distinct vision (D) is given by:
D = 1/f
where f is the focal length of the lens.
The focal length of a spectacle lens is equal to the reciprocal of its power:
f = 1/P
Given that the person uses spectacles of power 1.0 dioptre, we can calculate the focal length as follows:
f = 1/1.0 = 1.0 meter
Therefore, the nearest distance of distinct vision for the person is equal to the focal length of the lens:
D = 1.0 meter
Option B: -33.3 cm
The correct answer is not option B, but rather the inverse of the focal length, which is 1.0 meter. The negative value of -33.3 cm suggests a divergence of light, which is not applicable in this scenario. The person requires spectacles for correcting their vision, indicating the need for convergence of light.
The power of a lens is measured in dioptres (D). It indicates the ability of the lens to converge or diverge light. A positive power indicates convergence, while a negative power indicates divergence.
The formula to calculate the nearest distance of distinct vision (D) is given by:
D = 1/f
where f is the focal length of the lens.
The focal length of a spectacle lens is equal to the reciprocal of its power:
f = 1/P
Given that the person uses spectacles of power 1.0 dioptre, we can calculate the focal length as follows:
f = 1/1.0 = 1.0 meter
Therefore, the nearest distance of distinct vision for the person is equal to the focal length of the lens:
D = 1.0 meter
Option B: -33.3 cm
The correct answer is not option B, but rather the inverse of the focal length, which is 1.0 meter. The negative value of -33.3 cm suggests a divergence of light, which is not applicable in this scenario. The person requires spectacles for correcting their vision, indicating the need for convergence of light.
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If the person uses spectacles of power + 1.0 Dioptre, What is the nearest distance of distinct vision for him?a)300 cmb)-33.3 cmc)-298 cmd)+298 cmCorrect answer is option 'B'. Can you explain this answer?
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