GATE Exam  >  GATE Notes  >  Electronics and Communication Engineering (EC) 2013 GATE Paper (Set A) without solution

Electronics and Communication Engineering (EC) 2013 GATE Paper (Set A) without solution PDF Download

Download, print and study this document offline
Please wait while the PDF view is loading
 Page 1


|EC-GATE-2013 PAPER|  
 
1 
Q. No. 1 – 25 Carry One Mark Each 
1. A bulb in a staircase has two switches, one switch being at the ground floor
and the other one at the first floor. The bulb can be turned ON and also can
be turned OFF by any one of the switches irrespective of the state of the
other switch. The logic of switching of the bulb resembles
(A) an AND gate (B) an OR gate (C) an XOR gate (D) a NAND gate 
Answer: (C) 
Exp: (C) 
Let  Switches = 
1 2
p , p
1 2
p , p Z(o / p)
OFF OFF OFF
OFF ON ON
ON OFF ON
ON ON OFF
From Truth Table, it can be verified that Ex-OR logic is implemented. 
2. Consider a vector field ( ) A r


. The closed loop line integral A dl •
?
 

can be 
expressed as
(A) 
( )
A ds ?× •
??



 over the closed surface bounded by the loop 
(B) 
( )
A dv ?•
???


 over the closed volume bounded by the loop 
(C) 
( )
A dv ?•
???

 over the open volume bounded by the loop 
(D) 
( )
A ds ?× •
??


 over the closed surface bounded by the loop 
Answer: (D) 
Exp: (D) 
Stoke’s Theorem:  “ The Line Integral of a vector A around a closed path L  is 
equal to the integral of curl of A over the open surface  S enclosed by the closed 
path L”. 
( )
? = ?×
? ?? 
A.dl A .ds
3. Two systems with impulse responses 
( ) ( )
1 2
h t and h t are connected in cascade. 
Then the overall impulse response of the cascaded system is given by
(A) Product of 
( ) ( )
1 2
h t and h t
(B) Sum of 
( ) ( )
1 2
h t and h t
(C) Convolution of 
( ) ( )
1 2
h t and h t
(D) Subtraction of ( ) ( )
2 1
h t from h t
Page 2


|EC-GATE-2013 PAPER|  
 
1 
Q. No. 1 – 25 Carry One Mark Each 
1. A bulb in a staircase has two switches, one switch being at the ground floor
and the other one at the first floor. The bulb can be turned ON and also can
be turned OFF by any one of the switches irrespective of the state of the
other switch. The logic of switching of the bulb resembles
(A) an AND gate (B) an OR gate (C) an XOR gate (D) a NAND gate 
Answer: (C) 
Exp: (C) 
Let  Switches = 
1 2
p , p
1 2
p , p Z(o / p)
OFF OFF OFF
OFF ON ON
ON OFF ON
ON ON OFF
From Truth Table, it can be verified that Ex-OR logic is implemented. 
2. Consider a vector field ( ) A r


. The closed loop line integral A dl •
?
 

can be 
expressed as
(A) 
( )
A ds ?× •
??



 over the closed surface bounded by the loop 
(B) 
( )
A dv ?•
???


 over the closed volume bounded by the loop 
(C) 
( )
A dv ?•
???

 over the open volume bounded by the loop 
(D) 
( )
A ds ?× •
??


 over the closed surface bounded by the loop 
Answer: (D) 
Exp: (D) 
Stoke’s Theorem:  “ The Line Integral of a vector A around a closed path L  is 
equal to the integral of curl of A over the open surface  S enclosed by the closed 
path L”. 
( )
? = ?×
? ?? 
A.dl A .ds
3. Two systems with impulse responses 
( ) ( )
1 2
h t and h t are connected in cascade. 
Then the overall impulse response of the cascaded system is given by
(A) Product of 
( ) ( )
1 2
h t and h t
(B) Sum of 
( ) ( )
1 2
h t and h t
(C) Convolution of 
( ) ( )
1 2
h t and h t
(D) Subtraction of ( ) ( )
2 1
h t from h t
|EC-GATE-2013 PAPER|  
 
2 
Answer: (C) 
Exp:  
4. In a forward biased pn junction diode, the sequence of events that best describes
the mechanism of current flow is
(A) injection, and subsequent diffusion and recombination of minority carriers
(B) injection, and subsequent drift and generation of minority carriers
(C) extraction, and subsequent diffusion and generation of minority carriers
(D) extraction, and subsequent drift and recombination of minority carriers
Answer: (A) 
5. In IC technology, dry oxidation (using dry oxygen) as compared to wet oxidation
(using steam or water vapor) produces
(A) superior quality oxide with a higher growth rate
(B) inferior quality oxide with a higher growth rate
(C) inferior quality oxide with a lower growth rate
(D) superior quality oxide with a lower growth rate
Answer: (D) 
6. The maximum value of ? until which the approximation sin? ˜ ? holds to within 10%
error is
(A) 
o
10 (B) 
o
18 (C) 
o
50 (D) 
o
90
Answer: (B) 
Exp: 
3 5
sin .......
3! 5!
? ?
? = ?- + +
3
sin error
Error should 10% of
if 0.1
6
? = ?+
?
?
= ?
 
3
if 0.1
6
?
= ?
Then  higher order terms  also going to be less than 0.1?
So, sin? ˜ ? approximation is valid 
3
2
0.1
6
0.6
0.6
?
< ?
? <
? <
Consider 
max
0.6 0.7746 radians ? = =
180
(in degrees) 0.7746 45 ? = × °
p

Out of all possible options we need to go for max theta
 
below
  
45°
 
Hence it is
 
18°
 
x(t)
y(t)
1 2
h(t) *h(t)
x(t)
y(t) 1
h (t)
2
h (t)
Page 3


|EC-GATE-2013 PAPER|  
 
1 
Q. No. 1 – 25 Carry One Mark Each 
1. A bulb in a staircase has two switches, one switch being at the ground floor
and the other one at the first floor. The bulb can be turned ON and also can
be turned OFF by any one of the switches irrespective of the state of the
other switch. The logic of switching of the bulb resembles
(A) an AND gate (B) an OR gate (C) an XOR gate (D) a NAND gate 
Answer: (C) 
Exp: (C) 
Let  Switches = 
1 2
p , p
1 2
p , p Z(o / p)
OFF OFF OFF
OFF ON ON
ON OFF ON
ON ON OFF
From Truth Table, it can be verified that Ex-OR logic is implemented. 
2. Consider a vector field ( ) A r


. The closed loop line integral A dl •
?
 

can be 
expressed as
(A) 
( )
A ds ?× •
??



 over the closed surface bounded by the loop 
(B) 
( )
A dv ?•
???


 over the closed volume bounded by the loop 
(C) 
( )
A dv ?•
???

 over the open volume bounded by the loop 
(D) 
( )
A ds ?× •
??


 over the closed surface bounded by the loop 
Answer: (D) 
Exp: (D) 
Stoke’s Theorem:  “ The Line Integral of a vector A around a closed path L  is 
equal to the integral of curl of A over the open surface  S enclosed by the closed 
path L”. 
( )
? = ?×
? ?? 
A.dl A .ds
3. Two systems with impulse responses 
( ) ( )
1 2
h t and h t are connected in cascade. 
Then the overall impulse response of the cascaded system is given by
(A) Product of 
( ) ( )
1 2
h t and h t
(B) Sum of 
( ) ( )
1 2
h t and h t
(C) Convolution of 
( ) ( )
1 2
h t and h t
(D) Subtraction of ( ) ( )
2 1
h t from h t
|EC-GATE-2013 PAPER|  
 
2 
Answer: (C) 
Exp:  
4. In a forward biased pn junction diode, the sequence of events that best describes
the mechanism of current flow is
(A) injection, and subsequent diffusion and recombination of minority carriers
(B) injection, and subsequent drift and generation of minority carriers
(C) extraction, and subsequent diffusion and generation of minority carriers
(D) extraction, and subsequent drift and recombination of minority carriers
Answer: (A) 
5. In IC technology, dry oxidation (using dry oxygen) as compared to wet oxidation
(using steam or water vapor) produces
(A) superior quality oxide with a higher growth rate
(B) inferior quality oxide with a higher growth rate
(C) inferior quality oxide with a lower growth rate
(D) superior quality oxide with a lower growth rate
Answer: (D) 
6. The maximum value of ? until which the approximation sin? ˜ ? holds to within 10%
error is
(A) 
o
10 (B) 
o
18 (C) 
o
50 (D) 
o
90
Answer: (B) 
Exp: 
3 5
sin .......
3! 5!
? ?
? = ?- + +
3
sin error
Error should 10% of
if 0.1
6
? = ?+
?
?
= ?
 
3
if 0.1
6
?
= ?
Then  higher order terms  also going to be less than 0.1?
So, sin? ˜ ? approximation is valid 
3
2
0.1
6
0.6
0.6
?
< ?
? <
? <
Consider 
max
0.6 0.7746 radians ? = =
180
(in degrees) 0.7746 45 ? = × °
p

Out of all possible options we need to go for max theta
 
below
  
45°
 
Hence it is
 
18°
 
x(t)
y(t)
1 2
h(t) *h(t)
x(t)
y(t) 1
h (t)
2
h (t)
|EC-GATE-2013 PAPER|  
 
3 
7. The divergence of the vector field 
x y z
ˆ ˆ ˆ A xa ya za = + +

 is 
(A) 0 (B) 1/3 (C) 1 (D) 3 
Answer: (D) 
Exp: Given 
x y z
A xa ya za = + +
( ) ( ) ( )
( ) ( ) ( )
x y z
x y z
.A A A A
x y z
A x, A y, A z,
x y z
x y z
1 1 1 3
? ? ?
? = + +
? ? ?
= = =
? ? ?
= + +
? ? ?
= + + =
8. The impulse response of a system is 
( ) ( )
h t tu t . = For an input 
( )
u t 1 - , the output
is
(A) 
( )
2
t
u t
2
(B) 
( )
( )
t t 1
u t 1
2
-
- (C) 
( )
( )
2
t 1
u t 1
2
-
- (D) 
( )
2
t 1
u t 1
2
-
-
Answer: (C) 
Exp:  
For LTI system, if input gets delayed by one unit, output will also get delayed by 
one unit. 
2
(t 1)
u(t 1) u(t 1)
2
-
- ? - 
9. The Bode plot of a transfer function G (s) is shown in the figure below
The gain 
( ) ( )
20 log G s is 32 dB and –8 dB at 1 rad/s and 10 rad/s respectively.
The phase is negative for all ?. The G(s) is 
(A) 
39.8
s
 (B) 
2
39.8
s
 (C) 
32
s
 (D) 
2
32
s
40
32
20
1
0
10
8 -
100
( ) rad / s ?
Gain (dB) 
U(t) t u (t)
2
t
u(t)
2
LTI system
Page 4


|EC-GATE-2013 PAPER|  
 
1 
Q. No. 1 – 25 Carry One Mark Each 
1. A bulb in a staircase has two switches, one switch being at the ground floor
and the other one at the first floor. The bulb can be turned ON and also can
be turned OFF by any one of the switches irrespective of the state of the
other switch. The logic of switching of the bulb resembles
(A) an AND gate (B) an OR gate (C) an XOR gate (D) a NAND gate 
Answer: (C) 
Exp: (C) 
Let  Switches = 
1 2
p , p
1 2
p , p Z(o / p)
OFF OFF OFF
OFF ON ON
ON OFF ON
ON ON OFF
From Truth Table, it can be verified that Ex-OR logic is implemented. 
2. Consider a vector field ( ) A r


. The closed loop line integral A dl •
?
 

can be 
expressed as
(A) 
( )
A ds ?× •
??



 over the closed surface bounded by the loop 
(B) 
( )
A dv ?•
???


 over the closed volume bounded by the loop 
(C) 
( )
A dv ?•
???

 over the open volume bounded by the loop 
(D) 
( )
A ds ?× •
??


 over the closed surface bounded by the loop 
Answer: (D) 
Exp: (D) 
Stoke’s Theorem:  “ The Line Integral of a vector A around a closed path L  is 
equal to the integral of curl of A over the open surface  S enclosed by the closed 
path L”. 
( )
? = ?×
? ?? 
A.dl A .ds
3. Two systems with impulse responses 
( ) ( )
1 2
h t and h t are connected in cascade. 
Then the overall impulse response of the cascaded system is given by
(A) Product of 
( ) ( )
1 2
h t and h t
(B) Sum of 
( ) ( )
1 2
h t and h t
(C) Convolution of 
( ) ( )
1 2
h t and h t
(D) Subtraction of ( ) ( )
2 1
h t from h t
|EC-GATE-2013 PAPER|  
 
2 
Answer: (C) 
Exp:  
4. In a forward biased pn junction diode, the sequence of events that best describes
the mechanism of current flow is
(A) injection, and subsequent diffusion and recombination of minority carriers
(B) injection, and subsequent drift and generation of minority carriers
(C) extraction, and subsequent diffusion and generation of minority carriers
(D) extraction, and subsequent drift and recombination of minority carriers
Answer: (A) 
5. In IC technology, dry oxidation (using dry oxygen) as compared to wet oxidation
(using steam or water vapor) produces
(A) superior quality oxide with a higher growth rate
(B) inferior quality oxide with a higher growth rate
(C) inferior quality oxide with a lower growth rate
(D) superior quality oxide with a lower growth rate
Answer: (D) 
6. The maximum value of ? until which the approximation sin? ˜ ? holds to within 10%
error is
(A) 
o
10 (B) 
o
18 (C) 
o
50 (D) 
o
90
Answer: (B) 
Exp: 
3 5
sin .......
3! 5!
? ?
? = ?- + +
3
sin error
Error should 10% of
if 0.1
6
? = ?+
?
?
= ?
 
3
if 0.1
6
?
= ?
Then  higher order terms  also going to be less than 0.1?
So, sin? ˜ ? approximation is valid 
3
2
0.1
6
0.6
0.6
?
< ?
? <
? <
Consider 
max
0.6 0.7746 radians ? = =
180
(in degrees) 0.7746 45 ? = × °
p

Out of all possible options we need to go for max theta
 
below
  
45°
 
Hence it is
 
18°
 
x(t)
y(t)
1 2
h(t) *h(t)
x(t)
y(t) 1
h (t)
2
h (t)
|EC-GATE-2013 PAPER|  
 
3 
7. The divergence of the vector field 
x y z
ˆ ˆ ˆ A xa ya za = + +

 is 
(A) 0 (B) 1/3 (C) 1 (D) 3 
Answer: (D) 
Exp: Given 
x y z
A xa ya za = + +
( ) ( ) ( )
( ) ( ) ( )
x y z
x y z
.A A A A
x y z
A x, A y, A z,
x y z
x y z
1 1 1 3
? ? ?
? = + +
? ? ?
= = =
? ? ?
= + +
? ? ?
= + + =
8. The impulse response of a system is 
( ) ( )
h t tu t . = For an input 
( )
u t 1 - , the output
is
(A) 
( )
2
t
u t
2
(B) 
( )
( )
t t 1
u t 1
2
-
- (C) 
( )
( )
2
t 1
u t 1
2
-
- (D) 
( )
2
t 1
u t 1
2
-
-
Answer: (C) 
Exp:  
For LTI system, if input gets delayed by one unit, output will also get delayed by 
one unit. 
2
(t 1)
u(t 1) u(t 1)
2
-
- ? - 
9. The Bode plot of a transfer function G (s) is shown in the figure below
The gain 
( ) ( )
20 log G s is 32 dB and –8 dB at 1 rad/s and 10 rad/s respectively.
The phase is negative for all ?. The G(s) is 
(A) 
39.8
s
 (B) 
2
39.8
s
 (C) 
32
s
 (D) 
2
32
s
40
32
20
1
0
10
8 -
100
( ) rad / s ?
Gain (dB) 
U(t) t u (t)
2
t
u(t)
2
LTI system
|EC-GATE-2013 PAPER|  
 
4 
Answer: (B) 
Exp: Any two paints on same line segment of Bode plot satisfies the equation of 
straight line. 
2 1
2 1
G G
i.e, slope of the line segment.
log log
-
=
? - ?
 
For the initial straight line 
( )
2 1
2 1
1
N
1
2
2
G G
dB
40
dec
log log
0 32 40log
1
6.309 k ;Where N is type of system here initial slope is 
dB
40 Hence N = 2
dec
6.309 k
k 6.309
k 39.8
-
? = -
? - ?
? ? ?
? - = -
? ?
? ?
? ? = =
-
? =
? =
=
Hence ( )
2
39.8
G s
s
=
10. In the circuit shown below what is the output voltage 
( )
out
V if a silicon transistor 
Q and an ideal op-amp are used?
(A) –15V (B) –0.7V (C) +0.7V (D) +15V 
+
-
1 kO
5V
15V +
15V -
Q
out
V +
-
( ) 20log G j?
40 
32
20
8 -
w
10 
( ) w rad
1 
Page 5


|EC-GATE-2013 PAPER|  
 
1 
Q. No. 1 – 25 Carry One Mark Each 
1. A bulb in a staircase has two switches, one switch being at the ground floor
and the other one at the first floor. The bulb can be turned ON and also can
be turned OFF by any one of the switches irrespective of the state of the
other switch. The logic of switching of the bulb resembles
(A) an AND gate (B) an OR gate (C) an XOR gate (D) a NAND gate 
Answer: (C) 
Exp: (C) 
Let  Switches = 
1 2
p , p
1 2
p , p Z(o / p)
OFF OFF OFF
OFF ON ON
ON OFF ON
ON ON OFF
From Truth Table, it can be verified that Ex-OR logic is implemented. 
2. Consider a vector field ( ) A r


. The closed loop line integral A dl •
?
 

can be 
expressed as
(A) 
( )
A ds ?× •
??



 over the closed surface bounded by the loop 
(B) 
( )
A dv ?•
???


 over the closed volume bounded by the loop 
(C) 
( )
A dv ?•
???

 over the open volume bounded by the loop 
(D) 
( )
A ds ?× •
??


 over the closed surface bounded by the loop 
Answer: (D) 
Exp: (D) 
Stoke’s Theorem:  “ The Line Integral of a vector A around a closed path L  is 
equal to the integral of curl of A over the open surface  S enclosed by the closed 
path L”. 
( )
? = ?×
? ?? 
A.dl A .ds
3. Two systems with impulse responses 
( ) ( )
1 2
h t and h t are connected in cascade. 
Then the overall impulse response of the cascaded system is given by
(A) Product of 
( ) ( )
1 2
h t and h t
(B) Sum of 
( ) ( )
1 2
h t and h t
(C) Convolution of 
( ) ( )
1 2
h t and h t
(D) Subtraction of ( ) ( )
2 1
h t from h t
|EC-GATE-2013 PAPER|  
 
2 
Answer: (C) 
Exp:  
4. In a forward biased pn junction diode, the sequence of events that best describes
the mechanism of current flow is
(A) injection, and subsequent diffusion and recombination of minority carriers
(B) injection, and subsequent drift and generation of minority carriers
(C) extraction, and subsequent diffusion and generation of minority carriers
(D) extraction, and subsequent drift and recombination of minority carriers
Answer: (A) 
5. In IC technology, dry oxidation (using dry oxygen) as compared to wet oxidation
(using steam or water vapor) produces
(A) superior quality oxide with a higher growth rate
(B) inferior quality oxide with a higher growth rate
(C) inferior quality oxide with a lower growth rate
(D) superior quality oxide with a lower growth rate
Answer: (D) 
6. The maximum value of ? until which the approximation sin? ˜ ? holds to within 10%
error is
(A) 
o
10 (B) 
o
18 (C) 
o
50 (D) 
o
90
Answer: (B) 
Exp: 
3 5
sin .......
3! 5!
? ?
? = ?- + +
3
sin error
Error should 10% of
if 0.1
6
? = ?+
?
?
= ?
 
3
if 0.1
6
?
= ?
Then  higher order terms  also going to be less than 0.1?
So, sin? ˜ ? approximation is valid 
3
2
0.1
6
0.6
0.6
?
< ?
? <
? <
Consider 
max
0.6 0.7746 radians ? = =
180
(in degrees) 0.7746 45 ? = × °
p

Out of all possible options we need to go for max theta
 
below
  
45°
 
Hence it is
 
18°
 
x(t)
y(t)
1 2
h(t) *h(t)
x(t)
y(t) 1
h (t)
2
h (t)
|EC-GATE-2013 PAPER|  
 
3 
7. The divergence of the vector field 
x y z
ˆ ˆ ˆ A xa ya za = + +

 is 
(A) 0 (B) 1/3 (C) 1 (D) 3 
Answer: (D) 
Exp: Given 
x y z
A xa ya za = + +
( ) ( ) ( )
( ) ( ) ( )
x y z
x y z
.A A A A
x y z
A x, A y, A z,
x y z
x y z
1 1 1 3
? ? ?
? = + +
? ? ?
= = =
? ? ?
= + +
? ? ?
= + + =
8. The impulse response of a system is 
( ) ( )
h t tu t . = For an input 
( )
u t 1 - , the output
is
(A) 
( )
2
t
u t
2
(B) 
( )
( )
t t 1
u t 1
2
-
- (C) 
( )
( )
2
t 1
u t 1
2
-
- (D) 
( )
2
t 1
u t 1
2
-
-
Answer: (C) 
Exp:  
For LTI system, if input gets delayed by one unit, output will also get delayed by 
one unit. 
2
(t 1)
u(t 1) u(t 1)
2
-
- ? - 
9. The Bode plot of a transfer function G (s) is shown in the figure below
The gain 
( ) ( )
20 log G s is 32 dB and –8 dB at 1 rad/s and 10 rad/s respectively.
The phase is negative for all ?. The G(s) is 
(A) 
39.8
s
 (B) 
2
39.8
s
 (C) 
32
s
 (D) 
2
32
s
40
32
20
1
0
10
8 -
100
( ) rad / s ?
Gain (dB) 
U(t) t u (t)
2
t
u(t)
2
LTI system
|EC-GATE-2013 PAPER|  
 
4 
Answer: (B) 
Exp: Any two paints on same line segment of Bode plot satisfies the equation of 
straight line. 
2 1
2 1
G G
i.e, slope of the line segment.
log log
-
=
? - ?
 
For the initial straight line 
( )
2 1
2 1
1
N
1
2
2
G G
dB
40
dec
log log
0 32 40log
1
6.309 k ;Where N is type of system here initial slope is 
dB
40 Hence N = 2
dec
6.309 k
k 6.309
k 39.8
-
? = -
? - ?
? ? ?
? - = -
? ?
? ?
? ? = =
-
? =
? =
=
Hence ( )
2
39.8
G s
s
=
10. In the circuit shown below what is the output voltage 
( )
out
V if a silicon transistor 
Q and an ideal op-amp are used?
(A) –15V (B) –0.7V (C) +0.7V (D) +15V 
+
-
1 kO
5V
15V +
15V -
Q
out
V +
-
( ) 20log G j?
40 
32
20
8 -
w
10 
( ) w rad
1 
|EC-GATE-2013 PAPER|  
 
5 
Answer: (B) 
Exp:  
11. Consider a delta connection of resistors and its equivalent star connection as
shown below. If all elements of the delta connection are scaled by a factor k, k> 0,
the elements of the corresponding star equivalent will be scaled by a factor of
(A) 
2
k (B) k (C) 1/k (D) k
Answer: (B) 
Exp: 
a b
C
a b c
R R
R
R R R
=
+ +
=
+ +
=
+ +
a c
B
a b c
b c
A
a b c
R R
R
R R R
R R
R
R R R
Above expression shown that if 
a b c
R , R & R is scaled by k,  R
A
, R
B
 & R
C
 is scaled 
by k only. 
12. For 8085 microprocessor, the following program is executed
 MVI A, 05H; 
  MVIB, 05H; 
PTR: ADD B; 
 DCR B;  
 JNZ PTR; 
 ADI 03H; 
 HLT; 
At the end of program, accumulator contains 
(A) 17 H (B) 20 H (C) 23 H (D) 05 H 
b
R
a
R
c
R
C
R
B
R
A
R
a
R
b
R
c
R
C
R
A
R
B
R
out
V
1 kO
+
-
Q
+
-
5V
15V +
15V -
0.7v
+
-
out
V 0.7v = -
Read More

FAQs on Electronics and Communication Engineering (EC) 2013 GATE Paper (Set A) without solution

1. What is Electronics and Communication Engineering (EC)?
Ans. Electronics and Communication Engineering (EC) is a field of engineering that deals with the study and application of electronic devices, circuits, and communication systems. It involves designing, developing, and maintaining various electronic devices and communication networks.
2. What are the job opportunities for Electronics and Communication Engineering graduates?
Ans. Electronics and Communication Engineering graduates have a wide range of job opportunities. They can work in industries such as telecommunications, electronics, computer hardware, and software development. They can also pursue careers in research and development, consulting, and teaching.
3. What are the core subjects in Electronics and Communication Engineering?
Ans. Some of the core subjects in Electronics and Communication Engineering include digital electronics, analog electronics, communication systems, electromagnetic theory, microprocessors, control systems, signal processing, and electronic devices and circuits.
4. How can I prepare for the GATE exam in Electronics and Communication Engineering?
Ans. To prepare for the GATE exam in Electronics and Communication Engineering, it is important to have a strong understanding of the core subjects. Practice solving previous years' question papers and take mock tests to get familiar with the exam pattern and time management. Refer to standard textbooks and study materials, and join coaching classes or online courses if needed.
5. What are some important tips for cracking the GATE exam in Electronics and Communication Engineering?
Ans. Some important tips for cracking the GATE exam in Electronics and Communication Engineering are: - Create a study schedule and follow it consistently. - Focus on understanding concepts rather than memorizing them. - Solve as many practice questions as possible to improve problem-solving skills. - Revise the topics regularly to retain the learned information. - Stay updated with the latest syllabus and exam pattern. - Take mock tests and analyze your performance to identify areas of improvement. - Seek guidance from experienced faculty or mentors if needed.
Download as PDF
Explore Courses for GATE exam
Related Searches

Objective type Questions

,

pdf

,

Previous Year Questions with Solutions

,

Electronics and Communication Engineering (EC) 2013 GATE Paper (Set A) without solution

,

Semester Notes

,

shortcuts and tricks

,

practice quizzes

,

Summary

,

Free

,

Viva Questions

,

study material

,

ppt

,

Electronics and Communication Engineering (EC) 2013 GATE Paper (Set A) without solution

,

video lectures

,

Important questions

,

Exam

,

Extra Questions

,

Electronics and Communication Engineering (EC) 2013 GATE Paper (Set A) without solution

,

Sample Paper

,

MCQs

,

mock tests for examination

,

past year papers

;