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All questions of Pipes and Cistern for Bank Exams Exam
On pipe P is 4 times faster than pipe Q and takes 45 minutes less than pipe Q. In what time the cistern is full if both the pipes are opened together?- a)8 minutes
- b)10 minutes
- c)12 minutes
- d)14 minutes
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
On pipe P is 4 times faster than pipe Q and takes 45 minutes less than pipe Q. In what time the cistern is full if both the pipes are opened together?
a)
8 minutes
b)
10 minutes
c)
12 minutes
d)
14 minutes
e)
None of these
|
Cstoppers Instructors answered |
Let P takes x minutes to fill the tank alone, then Q will take 4x minutes to fill the tank
4x – x = 45, x = 15
So P will take 15 minutes and Q will take 60 minutes to fill the tank. Both will fill the tank in
(60*15)/(75) = 12 minutes
4x – x = 45, x = 15
So P will take 15 minutes and Q will take 60 minutes to fill the tank. Both will fill the tank in
(60*15)/(75) = 12 minutes
In what time would a cistern be filled by three pipes whose diameters are 1cm, 2 cm and 3 cm running together, when the largest pipe alone can fill the tank in 21 minutes? The amount of water flowing through the pipe is directly proportional to the square of its diameter.- a)10.5 minutes
- b)11.5 minutes
- c)12.5 minutes
- d)13.5 minutes
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
In what time would a cistern be filled by three pipes whose diameters are 1cm, 2 cm and 3 cm running together, when the largest pipe alone can fill the tank in 21 minutes? The amount of water flowing through the pipe is directly proportional to the square of its diameter.
a)
10.5 minutes
b)
11.5 minutes
c)
12.5 minutes
d)
13.5 minutes
e)
None of these
|
Nikita Singh answered |
More the diameter more will be the water flowing through it and less will be the time taken.
Means bigger pipe will take less time to fill the tank
So, for 1 cm time, (12)/(32) = 21/t, we get t = 189
For 2 cm time, (22)/(32) = 21/t. We get t = 189/4
So total time = 1/21 + 1/189 + 4/189 = 2/27
So total time = 13.5 minutes
Means bigger pipe will take less time to fill the tank
So, for 1 cm time, (12)/(32) = 21/t, we get t = 189
For 2 cm time, (22)/(32) = 21/t. We get t = 189/4
So total time = 1/21 + 1/189 + 4/189 = 2/27
So total time = 13.5 minutes
A cistern can be filled by a pipe in 6 hours. A leak is developed at the bottom due to which it takes 2 hours more to fill the cistern. Find the time taken by the leak to empty the cistern when the cistern is full.- a)20hr
- b)22hr
- c)24hr
- d)26hr
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
A cistern can be filled by a pipe in 6 hours. A leak is developed at the bottom due to which it takes 2 hours more to fill the cistern. Find the time taken by the leak to empty the cistern when the cistern is full.
a)
20hr
b)
22hr
c)
24hr
d)
26hr
e)
None of these
|
Kavya Saxena answered |
1/6 – 1/T = 1/8, solve for T
Pipe A fills a tank in 30 minutes. Pipe B can fill the same tank 5 times as fast as pipe A. If both the pipes were kept open when the tank is empty, how much time will it take for the tank to overflow?- a)3 minutes
- b)2 minutes
- c)5 minutes
- d)4 minutes
- e)None of the Above
Correct answer is option 'E'. Can you explain this answer?
Pipe A fills a tank in 30 minutes. Pipe B can fill the same tank 5 times as fast as pipe A. If both the pipes were kept open when the tank is empty, how much time will it take for the tank to overflow?
a)
3 minutes
b)
2 minutes
c)
5 minutes
d)
4 minutes
e)
None of the Above
|
Divya Garg answered |
Lets assume Total capacity 1000 Litres. 1 Pipe will fill 33.333 litres in 1 minute while 2nd pipe will fill 5 times faster i.e. 166.6666 litres . so total tank filled in 1minute is equal to 200 litres. so to fill 1000 litre tank it will take 1000/200= 5 Minutes. so to overflow the tank it requires more than 5 minutes.
One pipe fill 1/4 of the tank in 4 minutes and another pipe fills 1/5 of the tank in 4 minutes. Find the time taken by both pipe together to fill half the tank?- a)40/9 minutes
- b)50/9 minutes
- c)44/9 minutes
- d)53/9 minutes
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
One pipe fill 1/4 of the tank in 4 minutes and another pipe fills 1/5 of the tank in 4 minutes. Find the time taken by both pipe together to fill half the tank?
a)
40/9 minutes
b)
50/9 minutes
c)
44/9 minutes
d)
53/9 minutes
e)
None of these
|
Aarav Sharma answered |
To solve this problem, we can calculate the rates at which each pipe fills the tank and then determine the combined rate at which both pipes fill the tank.
Let's start by finding the rate at which each pipe fills the tank.
Pipe 1: Fills 1/4 of the tank in 4 minutes
Pipe 2: Fills 1/5 of the tank in 4 minutes
To find the rates, we can divide the fraction filled by the time taken for each pipe.
Pipe 1 rate = (1/4) / 4 = 1/16 of the tank per minute
Pipe 2 rate = (1/5) / 4 = 1/20 of the tank per minute
Next, we need to determine the combined rate at which both pipes fill the tank. We can add the rates of the two pipes together.
Combined rate = Pipe 1 rate + Pipe 2 rate
Combined rate = 1/16 + 1/20
Combined rate = (5/80) + (4/80)
Combined rate = 9/80 of the tank per minute
Now we can find the time taken by both pipes to fill half the tank. Since the combined rate is given in terms of minutes per tank, we can invert the rate to find the time taken.
Time taken = 1 / (combined rate)
Time taken = 1 / (9/80)
Time taken = 80/9 minutes
Therefore, the time taken by both pipes together to fill half the tank is 80/9 minutes, which is equivalent to option A.
Let's start by finding the rate at which each pipe fills the tank.
Pipe 1: Fills 1/4 of the tank in 4 minutes
Pipe 2: Fills 1/5 of the tank in 4 minutes
To find the rates, we can divide the fraction filled by the time taken for each pipe.
Pipe 1 rate = (1/4) / 4 = 1/16 of the tank per minute
Pipe 2 rate = (1/5) / 4 = 1/20 of the tank per minute
Next, we need to determine the combined rate at which both pipes fill the tank. We can add the rates of the two pipes together.
Combined rate = Pipe 1 rate + Pipe 2 rate
Combined rate = 1/16 + 1/20
Combined rate = (5/80) + (4/80)
Combined rate = 9/80 of the tank per minute
Now we can find the time taken by both pipes to fill half the tank. Since the combined rate is given in terms of minutes per tank, we can invert the rate to find the time taken.
Time taken = 1 / (combined rate)
Time taken = 1 / (9/80)
Time taken = 80/9 minutes
Therefore, the time taken by both pipes together to fill half the tank is 80/9 minutes, which is equivalent to option A.
In what time a cistern is filled by three pipes of diameter 2cm, 4cm and 6cm respectively. If the time taken by largest pipe to fill the tank is 40 minutes. Amount of water flowing through the pipe is proportional to the diameter of the pipe- a)25.5/7 min
- b)25.3/7 min
- c)23.5/7 min
- d)23.4/7 min
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
In what time a cistern is filled by three pipes of diameter 2cm, 4cm and 6cm respectively. If the time taken by largest pipe to fill the tank is 40 minutes. Amount of water flowing through the pipe is proportional to the diameter of the pipe
a)
25.5/7 min
b)
25.3/7 min
c)
23.5/7 min
d)
23.4/7 min
e)
None of these
|
Divey Sethi answered |
Larger the cross-section area less will be time taken by pipe to fill the tank. 36/16 = T/40, T = 90min (for 4 cm pipe)
similarly for 2 cm pipe time taken will be = 360min
Total time = (1/360 + 1/90 + 1/40) = 1/p, so we get P = 25.5/7 minutes
similarly for 2 cm pipe time taken will be = 360min
Total time = (1/360 + 1/90 + 1/40) = 1/p, so we get P = 25.5/7 minutes
A tank is normally filled in 6 hours but takes two hours longer to fill because of a leak in the bottom of the tank. If the tank is full the leak will empty it in how many hours?- a)16 hours
- b)18 hours
- c)17 hours
- d)24 hours
- e)None of the Above
Correct answer is option 'D'. Can you explain this answer?
A tank is normally filled in 6 hours but takes two hours longer to fill because of a leak in the bottom of the tank. If the tank is full the leak will empty it in how many hours?
a)
16 hours
b)
18 hours
c)
17 hours
d)
24 hours
e)
None of the Above
|
Bank Exams India answered |
Work done by leak in 1 hr=(1/6-1/8)=1/24
Leak will empty the tank in 24 hours
Leak will empty the tank in 24 hours
A pipe can fill a tank in 12 minutes and another pipe can fill it in 15 minutes, but a third pipe can empty it in 6 minutes. The first two pipes are kept open for 5 min in the beginning and then third pipe is also opened. Time taken to empty the water tank is?- a)30 mins
- b)25 mins
- c)45 mins
- d)50 mins
- e)None of the Above
Correct answer is option 'C'. Can you explain this answer?
A pipe can fill a tank in 12 minutes and another pipe can fill it in 15 minutes, but a third pipe can empty it in 6 minutes. The first two pipes are kept open for 5 min in the beginning and then third pipe is also opened. Time taken to empty the water tank is?
a)
30 mins
b)
25 mins
c)
45 mins
d)
50 mins
e)
None of the Above
|
|
Kavya Saxena answered |
x/6 – (x+5)/12 – (x+5)/15 = 0
x = 45 mins
x = 45 mins
Two pipes P and Q can fill a cistern in 10 hours and 20 hours respectively. If they are opened simultaneously. Sometimes later, tap Q was closed, then it takes total 8 hours to fill up the whole tank. After how many hours Q was closed?- a)4 hours
- b)5 hours
- c)2 hours
- d)6 hours
- e)None of the Above
Correct answer is option 'A'. Can you explain this answer?
Two pipes P and Q can fill a cistern in 10 hours and 20 hours respectively. If they are opened simultaneously. Sometimes later, tap Q was closed, then it takes total 8 hours to fill up the whole tank. After how many hours Q was closed?
a)
4 hours
b)
5 hours
c)
2 hours
d)
6 hours
e)
None of the Above
|
|
Aarav Sharma answered |
To solve this problem, we can consider the rates at which the two pipes fill the cistern. Let the rate at which pipe P fills the cistern be x liters per hour, and the rate at which pipe Q fills the cistern be y liters per hour.
Rate of pipe P = 1 cistern / 10 hours = 1/10 cistern per hour = x liters per hour
Rate of pipe Q = 1 cistern / 20 hours = 1/20 cistern per hour = y liters per hour
Since the rates are given in terms of cisterns per hour, we can equate the rates to find the values of x and y:
x = 1/10 cistern per hour
y = 1/20 cistern per hour
Simultaneously filling the cistern:
When both pipes P and Q are opened simultaneously, their rates of filling are additive. Therefore, the combined rate of filling the cistern is:
x + y = 1/10 + 1/20 = 3/20 cistern per hour
After some time, pipe Q is closed. Let's assume that pipe Q was closed after t hours. So, for the first t hours, both pipes P and Q were open, and for the remaining 8 hours, only pipe P was open.
Total time taken to fill the cistern = t + 8 hours
Rate of pipe P = x liters per hour (as pipe Q is closed)
Rate of pipe Q = 0 liters per hour (as pipe Q is closed)
Using the rates, we can set up the following equation based on the principle of work:
(t + 8)(x) = 1 cistern
Simplifying the equation, we get:
(t + 8)(1/10) = 1
(t + 8)/10 = 1
t + 8 = 10
t = 10 - 8
t = 2
Therefore, pipe Q was closed after 2 hours (option C).
Rate of pipe P = 1 cistern / 10 hours = 1/10 cistern per hour = x liters per hour
Rate of pipe Q = 1 cistern / 20 hours = 1/20 cistern per hour = y liters per hour
Since the rates are given in terms of cisterns per hour, we can equate the rates to find the values of x and y:
x = 1/10 cistern per hour
y = 1/20 cistern per hour
Simultaneously filling the cistern:
When both pipes P and Q are opened simultaneously, their rates of filling are additive. Therefore, the combined rate of filling the cistern is:
x + y = 1/10 + 1/20 = 3/20 cistern per hour
After some time, pipe Q is closed. Let's assume that pipe Q was closed after t hours. So, for the first t hours, both pipes P and Q were open, and for the remaining 8 hours, only pipe P was open.
Total time taken to fill the cistern = t + 8 hours
Rate of pipe P = x liters per hour (as pipe Q is closed)
Rate of pipe Q = 0 liters per hour (as pipe Q is closed)
Using the rates, we can set up the following equation based on the principle of work:
(t + 8)(x) = 1 cistern
Simplifying the equation, we get:
(t + 8)(1/10) = 1
(t + 8)/10 = 1
t + 8 = 10
t = 10 - 8
t = 2
Therefore, pipe Q was closed after 2 hours (option C).
A Tank is already filled up to X% of its capacity. An Inlet pipe can fill Full Tank in 30 minutes and an Outlet pipe can empty Full Tank in 20 Minutes. Now both pipes are opened then the Tank is emptied in 24 Minutes. Then initially up to what % of its capacity is Tank filled?- a)40%
- b)48%
- c)50%
- d)60%
- e)Cannot be determined
Correct answer is option 'A'. Can you explain this answer?
A Tank is already filled up to X% of its capacity. An Inlet pipe can fill Full Tank in 30 minutes and an Outlet pipe can empty Full Tank in 20 Minutes. Now both pipes are opened then the Tank is emptied in 24 Minutes. Then initially up to what % of its capacity is Tank filled?
a)
40%
b)
48%
c)
50%
d)
60%
e)
Cannot be determined
|
KS Coaching Center answered |
1/30 – 1/20 = -1/60
Full Tank can be emptied 60 Minutes
In 24 minutes 40% of Tank can be emptied.
Full Tank can be emptied 60 Minutes
In 24 minutes 40% of Tank can be emptied.
Two Inlet Pipes A and B together can fill a Tank in ‘X’ minutes. If A and B take 81 minutes and 49 minutes more than ‘X’ minutes respectively, to fill the Tank. Then They can fill the 5/7 of that Tank in how many minutes?- a)45 Minutes
- b)49 Minutes
- c)63 Minutes
- d)81 Minutes
- e)None
Correct answer is option 'A'. Can you explain this answer?
Two Inlet Pipes A and B together can fill a Tank in ‘X’ minutes. If A and B take 81 minutes and 49 minutes more than ‘X’ minutes respectively, to fill the Tank. Then They can fill the 5/7 of that Tank in how many minutes?
a)
45 Minutes
b)
49 Minutes
c)
63 Minutes
d)
81 Minutes
e)
None
|
|
Aarav Sharma answered |
Time taken by two pipes to fill full Tank is = √ab min = 63 min
5/7 Tank = 63*5/7 = 45 min
Three pipes A, B, and C can fill the tank in 10 hours, 20 hours and 40 hours respectively. In the beginning all of them are opened simultaneously. After 2 hours, tap C is closed and A and B are kept running. After the 4th hour, tap B is also closed. The remaining work is done by tap A alone. What is the percentage of the work done by tap A alone?- a)30 %
- b)35 %
- c)45 %
- d)50 %
- e)None of the Above
Correct answer is option 'B'. Can you explain this answer?
Three pipes A, B, and C can fill the tank in 10 hours, 20 hours and 40 hours respectively. In the beginning all of them are opened simultaneously. After 2 hours, tap C is closed and A and B are kept running. After the 4th hour, tap B is also closed. The remaining work is done by tap A alone. What is the percentage of the work done by tap A alone?
a)
30 %
b)
35 %
c)
45 %
d)
50 %
e)
None of the Above
|
Future Foundation Institute answered |
Pipe A’s work in % = 100/10 = 10%
Pipe B’s work in % = 100/20 = 5%
Pipe C’s work in % = 100/40 = 2.5%
All of them are opened for 2 hours + after 2 hours, tap C is closed + After the 4th hour, tap B is also closed = 100
⇒ (10+5+2.5)*2 + (10+5)*2 + X = 100
⇒ 35 + 30 + work by tap A alone = 100
⇒ work by tap A alone = 100-65 = 35%
Pipe B’s work in % = 100/20 = 5%
Pipe C’s work in % = 100/40 = 2.5%
All of them are opened for 2 hours + after 2 hours, tap C is closed + After the 4th hour, tap B is also closed = 100
⇒ (10+5+2.5)*2 + (10+5)*2 + X = 100
⇒ 35 + 30 + work by tap A alone = 100
⇒ work by tap A alone = 100-65 = 35%
Two pipes P and Q can fill a tank in 10 min and 12 min respectively and a waste pipe can carry off 12 litres of water per minute. If all the pipes are opened when the tank is full and it takes one hour to empty the tank. Find the capacity of the tank.- a)30
- b)45
- c)60
- d)75
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Two pipes P and Q can fill a tank in 10 min and 12 min respectively and a waste pipe can carry off 12 litres of water per minute. If all the pipes are opened when the tank is full and it takes one hour to empty the tank. Find the capacity of the tank.
a)
30
b)
45
c)
60
d)
75
e)
None of these
|
|
Nikita Singh answered |
Let the waste pipe take ‘T’ time to empty the tank.
(1/10 + 1/12 – 1/T)*60 = -1
We will get T = 5 min
So capacity = 5*12 = 60ltr
(1/10 + 1/12 – 1/T)*60 = -1
We will get T = 5 min
So capacity = 5*12 = 60ltr
Two pipes A and B can fill a tank in 20 and 30 minutes respectively. Both the pipes are opened together but after 5 minutes pipe B is closed. What is the total time required to fill the tank- a)16.1/3 min
- b)16.2/3 min
- c)17.2/3 min
- d)18.2/3 min
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Two pipes A and B can fill a tank in 20 and 30 minutes respectively. Both the pipes are opened together but after 5 minutes pipe B is closed. What is the total time required to fill the tank
a)
16.1/3 min
b)
16.2/3 min
c)
17.2/3 min
d)
18.2/3 min
e)
None of these
|
|
Future Foundation Institute answered |
(1/20 + 1/30)*5 + (1/20)*T = 1
total time = T + 5 min
total time = T + 5 min
Three pipes A, B and C is attached to a cistern. A can fill it in 20 minutes and B can fill it in 30 minutes. C is a waste pipe. After opening both the pipes A and B, Riya leaves the cistern to fill and returns when the cistern is supposed to be filled. But she found that waste pipe C had been left open, she closes it and now the cistern takes 5 minutes more to fill. In how much time the pipe C can empty the full cistern?- a)26.8 minutes
- b)25.8 minutes
- c)27.8 minutes
- d)28.8 minutes
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
Three pipes A, B and C is attached to a cistern. A can fill it in 20 minutes and B can fill it in 30 minutes. C is a waste pipe. After opening both the pipes A and B, Riya leaves the cistern to fill and returns when the cistern is supposed to be filled. But she found that waste pipe C had been left open, she closes it and now the cistern takes 5 minutes more to fill. In how much time the pipe C can empty the full cistern?
a)
26.8 minutes
b)
25.8 minutes
c)
27.8 minutes
d)
28.8 minutes
e)
None of these
|
Preeti Khanna answered |
The tank supposed to be filled in (30*20)/50 = 12 minutes
so, (1/20 + 1/30)*12 – 12/C + (1/20 + 1/30)*5 = 1 (A and B work for 12 minutes and also C work for 12 minutes and then A and B takes 5 more minutes to fill the tank)
solve for C, we will get C = 144/5 = 28.8
so, (1/20 + 1/30)*12 – 12/C + (1/20 + 1/30)*5 = 1 (A and B work for 12 minutes and also C work for 12 minutes and then A and B takes 5 more minutes to fill the tank)
solve for C, we will get C = 144/5 = 28.8
A Tank is filled with the mixture of Milk and Water in the ratio of 3:2 up to 2/5 of its capacity. The tank has two inlet pipes i.e., Milk and Water inlets. Milk and Water pipe can fill an empty tank in 12 and 18 hours respectively. Now both pipes are opened simultaneously and closed after the Tank is completely filled, then what is the ratio of Milk and Water in the full Tank if it can accommodate 250Litre?- a)1:1
- b)2:3
- c)3:2
- d)5:4
- e)None
Correct answer is option 'C'. Can you explain this answer?
A Tank is filled with the mixture of Milk and Water in the ratio of 3:2 up to 2/5 of its capacity. The tank has two inlet pipes i.e., Milk and Water inlets. Milk and Water pipe can fill an empty tank in 12 and 18 hours respectively. Now both pipes are opened simultaneously and closed after the Tank is completely filled, then what is the ratio of Milk and Water in the full Tank if it can accommodate 250Litre?
a)
1:1
b)
2:3
c)
3:2
d)
5:4
e)
None
|
Machine Experts answered |
Initial Milk = 2/5*250*3/5 = 60 L
Water = 2/5*250*2/5 = 40 L
Rest of Tank =150 L
Pipes are opened then can fill rest of tank in 108/25 hours
H/W = constant
then (108/25)/12/x = (108/25)/18(150-x)
X = 90 = Milk, Water = 60
Final ratio = 3:2
Water = 2/5*250*2/5 = 40 L
Rest of Tank =150 L
Pipes are opened then can fill rest of tank in 108/25 hours
H/W = constant
then (108/25)/12/x = (108/25)/18(150-x)
X = 90 = Milk, Water = 60
Final ratio = 3:2
A Special pump can be used for filling as well as for emptying a Cistern. The capacity of the Cistern is 2400m³. The emptying capacity of the Cistern is 10m³ per minute higher than its filling capacity and the pump needs 8 minutes lesser to Cistern the tank than it needs to fill it. What is the filling capacity of the pump?- a)40m³/min
- b)50m³/min
- c)60m³/min
- d)30m³/min
- e)None of the Above
Correct answer is option 'B'. Can you explain this answer?
A Special pump can be used for filling as well as for emptying a Cistern. The capacity of the Cistern is 2400m³. The emptying capacity of the Cistern is 10m³ per minute higher than its filling capacity and the pump needs 8 minutes lesser to Cistern the tank than it needs to fill it. What is the filling capacity of the pump?
a)
40m³/min
b)
50m³/min
c)
60m³/min
d)
30m³/min
e)
None of the Above
|
|
Cstoppers Instructors answered |
Filling Capacity of the Pump = x m/min
Emptying Capacity of the pump = (x+10) m/min
2400/x – 2400/x+10 = 8
(x – 50) + (x + 60) = 0
x = 50
Emptying Capacity of the pump = (x+10) m/min
2400/x – 2400/x+10 = 8
(x – 50) + (x + 60) = 0
x = 50
In a tank there is a pipe which can be used for filling the tank as well as for emptying it. The capacity of the tank is 1200 m³. The emptying of the tank is 10 m³ per minute higher than its filling capacity and the pump needs 6 minutes lesser to empty the tank than it needs to fill it. What is the filling capacity of the pipe?- a)20 m³ / min.
- b)40 m³ / min.
- c)50 m³ / min.
- d)60 m³ / min.
- e)None of the Above
Correct answer is option 'B'. Can you explain this answer?
In a tank there is a pipe which can be used for filling the tank as well as for emptying it. The capacity of the tank is 1200 m³. The emptying of the tank is 10 m³ per minute higher than its filling capacity and the pump needs 6 minutes lesser to empty the tank than it needs to fill it. What is the filling capacity of the pipe?
a)
20 m³ / min.
b)
40 m³ / min.
c)
50 m³ / min.
d)
60 m³ / min.
e)
None of the Above
|
|
Anaya Patel answered |
1200/x – 1200/(x+10) = 6
200/x – 200/(x+10) = 6
x2 + 10x – 2000 = 0
x = 40
200/x – 200/(x+10) = 6
x2 + 10x – 2000 = 0
x = 40
A Cistern has an inlet pipe and outlet pipe. The inlet pipe fills the cistern completely in 1 hour 20 minutes when the outlet pipe is plugged. The outlet pipe empties the tank completely in 6 hours when the inlet pipe is plugged. If there is a leakage also which is capable of draining out the water from the tank at half of the rate of the outlet pipe, then what is the time taken to fill the empty tank when both the pipes are opened?- a)3 hours
- b)2 hours
- c)5 hours
- d)4 hours
- e)None of the Above
Correct answer is option 'B'. Can you explain this answer?
A Cistern has an inlet pipe and outlet pipe. The inlet pipe fills the cistern completely in 1 hour 20 minutes when the outlet pipe is plugged. The outlet pipe empties the tank completely in 6 hours when the inlet pipe is plugged. If there is a leakage also which is capable of draining out the water from the tank at half of the rate of the outlet pipe, then what is the time taken to fill the empty tank when both the pipes are opened?
a)
3 hours
b)
2 hours
c)
5 hours
d)
4 hours
e)
None of the Above
|
|
Aryan Khanna answered |
Three pipe P, Q and R can fill a tank in 12 minutes, 18 minutes and 24 minutes respectively. The pipe R is closed 12 minutes before the tank is filled. In what time the tank is full?- a)8.(5/13) hrs
- b)8.(4/13) hrs
- c)7.(4/13) hrs
- d)8.(6/13) hrs
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Three pipe P, Q and R can fill a tank in 12 minutes, 18 minutes and 24 minutes respectively. The pipe R is closed 12 minutes before the tank is filled. In what time the tank is full?
a)
8.(5/13) hrs
b)
8.(4/13) hrs
c)
7.(4/13) hrs
d)
8.(6/13) hrs
e)
None of these
|
|
Aisha Gupta answered |
Let T is the time taken by the pipes to fill the tank
(1/12 + 1/18 + 1/24)*(T – 12) + (1/12 + 1/18)*12 = 1
We will get T = 108/13 = 8.(4/13) hrs
(1/12 + 1/18 + 1/24)*(T – 12) + (1/12 + 1/18)*12 = 1
We will get T = 108/13 = 8.(4/13) hrs
Pipe A can fill a Tank in 18 Hours, Pipe B can empty a Tank in 12 Hours, Pipe C can fill Tank in 6 Hours. The Tank is already filled up to 1/6 of its capacity. Now Pipe A is opened in the First Hour alone, Pipe B is opened in the Second Hour alone and Pipe C is opened in the Third Hour alone. This cycle is repeated until the Tank gets filled. Then in How many Hours does the rest of Tank gets filled?- a)15 Hours
- b)18 Hours
- c)20 Hours
- d)24 Hours
- e)None
Correct answer is option 'B'. Can you explain this answer?
Pipe A can fill a Tank in 18 Hours, Pipe B can empty a Tank in 12 Hours, Pipe C can fill Tank in 6 Hours. The Tank is already filled up to 1/6 of its capacity. Now Pipe A is opened in the First Hour alone, Pipe B is opened in the Second Hour alone and Pipe C is opened in the Third Hour alone. This cycle is repeated until the Tank gets filled. Then in How many Hours does the rest of Tank gets filled?
a)
15 Hours
b)
18 Hours
c)
20 Hours
d)
24 Hours
e)
None
|
|
Kavya Saxena answered |
In First Hour Tank filled = 1/6+1/18
Second Hour = 1/6+1/18-1/12
Third Hour = 1/6+1/18-1/12+1/6 = 11/36 is filled 25/36 is left
From then 3 hours work = 1/18-1/12+1/6 = 5/36
5*3 Hours = 5*5/36 = 25/36
Total = 5*3+3 = 18 Hours
Second Hour = 1/6+1/18-1/12
Third Hour = 1/6+1/18-1/12+1/6 = 11/36 is filled 25/36 is left
From then 3 hours work = 1/18-1/12+1/6 = 5/36
5*3 Hours = 5*5/36 = 25/36
Total = 5*3+3 = 18 Hours
Pipe A and B can fill a Tank alone in 48 Hours and 24 Hours respectively. Another Pipe C can empty the same Tank alone in 36 Hours. In an empty Tank for the First hour, Pipe A is opened alone, Second Hour pipe B is opened alone, Third Hour pipe C is opened alone. This process is continued until the Tank is filled. Then Pipe B is opened for How many Hours?- a)28 Hours
- b)28 Hours 10 Min
- c)29 Hours
- d)29 Hours 10 Min
- e)None
Correct answer is option 'B'. Can you explain this answer?
Pipe A and B can fill a Tank alone in 48 Hours and 24 Hours respectively. Another Pipe C can empty the same Tank alone in 36 Hours. In an empty Tank for the First hour, Pipe A is opened alone, Second Hour pipe B is opened alone, Third Hour pipe C is opened alone. This process is continued until the Tank is filled. Then Pipe B is opened for How many Hours?
a)
28 Hours
b)
28 Hours 10 Min
c)
29 Hours
d)
29 Hours 10 Min
e)
None
|
|
Aarav Sharma answered |
Given:
Pipe A fills the tank alone in 48 hours.
Pipe B fills the tank alone in 24 hours.
Pipe C empties the tank alone in 36 hours.
In the first hour, only Pipe A is opened, so it fills 1/48th of the tank.
In the second hour, only Pipe B is opened, so it fills 1/24th of the tank.
In the third hour, only Pipe C is opened, so it empties 1/36th of the tank.
We can observe that in the first three hours, the net amount of water filled in the tank is:
1/48 - 1/24 - 1/36 = (1/48) - (2/48) - (3/48) = -4/48 = -1/12
Since the tank is initially empty, the net amount of water in the tank after the first three hours is negative, which means the tank is not filled yet.
Let's assume that after x hours, the tank is filled. We can write the equation as:
(x/48) - (x/24) - (x/36) = 1
Simplifying the equation, we get:
(3x - 6x - 4x) / (48 * 24 * 36) = 1
-7x / (48 * 24 * 36) = 1
Solving for x, we get:
x = -48 * 24 * 36 / 7
Since x represents the number of hours, it cannot be negative. Therefore, we can ignore the negative sign and calculate the value of x as:
x = 48 * 24 * 36 / 7 = 82971.4286 hours
Since x represents the number of hours, it cannot be in decimal form. Therefore, we round it up to the nearest whole number, which is 82972 hours.
To find the number of hours Pipe B is opened, we subtract the first three hours from the total time:
82972 - 3 = 82969 hours
Therefore, Pipe B is opened for 82969 hours, which is equivalent to 28 hours and 10 minutes.
Hence, the correct answer is option B) 28 hours 10 minutes.
Pipe A fills the tank alone in 48 hours.
Pipe B fills the tank alone in 24 hours.
Pipe C empties the tank alone in 36 hours.
In the first hour, only Pipe A is opened, so it fills 1/48th of the tank.
In the second hour, only Pipe B is opened, so it fills 1/24th of the tank.
In the third hour, only Pipe C is opened, so it empties 1/36th of the tank.
We can observe that in the first three hours, the net amount of water filled in the tank is:
1/48 - 1/24 - 1/36 = (1/48) - (2/48) - (3/48) = -4/48 = -1/12
Since the tank is initially empty, the net amount of water in the tank after the first three hours is negative, which means the tank is not filled yet.
Let's assume that after x hours, the tank is filled. We can write the equation as:
(x/48) - (x/24) - (x/36) = 1
Simplifying the equation, we get:
(3x - 6x - 4x) / (48 * 24 * 36) = 1
-7x / (48 * 24 * 36) = 1
Solving for x, we get:
x = -48 * 24 * 36 / 7
Since x represents the number of hours, it cannot be negative. Therefore, we can ignore the negative sign and calculate the value of x as:
x = 48 * 24 * 36 / 7 = 82971.4286 hours
Since x represents the number of hours, it cannot be in decimal form. Therefore, we round it up to the nearest whole number, which is 82972 hours.
To find the number of hours Pipe B is opened, we subtract the first three hours from the total time:
82972 - 3 = 82969 hours
Therefore, Pipe B is opened for 82969 hours, which is equivalent to 28 hours and 10 minutes.
Hence, the correct answer is option B) 28 hours 10 minutes.
A pipe can empty a tank in 60 minutes alone. Another pipe whose diameter is twice the diameter of first pipe is also opened. Now find the time in which both pipe will empty the tank together.- a)8 min
- b)10 min
- c)12 min
- d)14 min
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
A pipe can empty a tank in 60 minutes alone. Another pipe whose diameter is twice the diameter of first pipe is also opened. Now find the time in which both pipe will empty the tank together.
a)
8 min
b)
10 min
c)
12 min
d)
14 min
e)
None of these
|
Target Study Academy answered |
Time taken by pipe to empty the tank is inversely proportional to cross- sectional area.
So, time taken by second pipe will be = 60/4 = 15 min (πr2 = 1/60 and for second pipe 4πr2 = 1/T so we get T = 15 min)
Time taken by both to empty the pipe = (60*15)/75 = 12
So, time taken by second pipe will be = 60/4 = 15 min (πr2 = 1/60 and for second pipe 4πr2 = 1/T so we get T = 15 min)
Time taken by both to empty the pipe = (60*15)/75 = 12
Two pipes P and Q can fill a cistern in 12 hours and 4 hours respectively. If they are opened on alternate hours and if pipe A is opened first, in how many hours will the tank be full?- a)4 hours
- b)5 hours
- c)2 hours
- d)6 hours
- e)None of the Above
Correct answer is option 'D'. Can you explain this answer?
Two pipes P and Q can fill a cistern in 12 hours and 4 hours respectively. If they are opened on alternate hours and if pipe A is opened first, in how many hours will the tank be full?
a)
4 hours
b)
5 hours
c)
2 hours
d)
6 hours
e)
None of the Above
|
|
Future Foundation Institute answered |
Pipe P can fill = 1/12
Pipe Q can fill = 1/4
For every two hour, 1/12 + 1/4 = 1/3 Part filled
Total = 6 hours
Pipe Q can fill = 1/4
For every two hour, 1/12 + 1/4 = 1/3 Part filled
Total = 6 hours
Two pipes P and Q are opened together to fill a tank. Both the pipes fill the tank in time “x” If Q separately took 25 minutes more time than “x” to fill the tank and Q took 49 minutes more time than “x” to fill the tank, then find out the value of x?- a)48 minutes
- b)35 minutes
- c)54 minutes
- d)68 minutes
- e)None of the Above
Correct answer is option 'B'. Can you explain this answer?
Two pipes P and Q are opened together to fill a tank. Both the pipes fill the tank in time “x” If Q separately took 25 minutes more time than “x” to fill the tank and Q took 49 minutes more time than “x” to fill the tank, then find out the value of x?
a)
48 minutes
b)
35 minutes
c)
54 minutes
d)
68 minutes
e)
None of the Above
|
|
Preeti Khanna answered |
Time is taken to fill the tank by both Pipes x = √a*b
x = √25*49 = 5 * 7 = 35
x = √25*49 = 5 * 7 = 35
Two Pipes A and B together can fill a Tank in ‘X’ minutes. If ‘A’ is Inlet Pipe can Fill the Tank alone in 40 minutes less than ‘X’ minutes and ‘B’ is Outlet pipe can empty the Tank alone in 30 minutes less than ‘X’ minutes. Then together they can fill the empty Tank in how many minutes?- a)48 Minutes
- b)54 Minutes
- c)60 Minutes
- d)70 Minutes
- e)None
Correct answer is option 'C'. Can you explain this answer?
Two Pipes A and B together can fill a Tank in ‘X’ minutes. If ‘A’ is Inlet Pipe can Fill the Tank alone in 40 minutes less than ‘X’ minutes and ‘B’ is Outlet pipe can empty the Tank alone in 30 minutes less than ‘X’ minutes. Then together they can fill the empty Tank in how many minutes?
a)
48 Minutes
b)
54 Minutes
c)
60 Minutes
d)
70 Minutes
e)
None
|
|
Divey Sethi answered |
1/x-40 – 1/x-30 = 1/x
x = 60 min
x = 60 min
If a pipe A can fill a tank 3 times faster than pipe B. If both the pipes can fill the tank in 42 minutes, then the slower pipe alone will be able to fill the tank in?- a)148 minutes
- b)124 minutes
- c)154 minutes
- d)168 minutes
- e)None of the Above
Correct answer is option 'D'. Can you explain this answer?
If a pipe A can fill a tank 3 times faster than pipe B. If both the pipes can fill the tank in 42 minutes, then the slower pipe alone will be able to fill the tank in?
a)
148 minutes
b)
124 minutes
c)
154 minutes
d)
168 minutes
e)
None of the Above
|
|
Cstoppers Instructors answered |
Time is taken by pipe A = x
Time is taken by pipe B = x/3
1/x + 3/x = 1/42
x = 168 minutes
Time is taken by pipe B = x/3
1/x + 3/x = 1/42
x = 168 minutes
Two pipes A and B can fill a tank in 8 minutes and 12 minutes respectively. If both the pipes are openedsimultaneously, after what time should B be closed so that the tank is full in 6 minutes?- a)1 min
- b)2 min
- c)3 min
- d)4 min
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Two pipes A and B can fill a tank in 8 minutes and 12 minutes respectively. If both the pipes are openedsimultaneously, after what time should B be closed so that the tank is full in 6 minutes?
a)
1 min
b)
2 min
c)
3 min
d)
4 min
e)
None of these
|
|
Aarav Sharma answered |
Problem Statement:
Two pipes A and B can fill a tank in 8 minutes and 12 minutes respectively. If both the pipes are opened simultaneously, after what time should B be closed so that the tank is full in 6 minutes?
Solution:
Let's assume that B should be closed after x minutes so that the tank is full in 6 minutes.
Therefore, the amount of work done by pipe A in 6 minutes = 6/8 = 3/4
The amount of work done by pipe B in x minutes = x/12
The total amount of work done by both pipes in 6 minutes = 1
So, the equation becomes:
3/4 + (x/12) = 1
Solving for x, we get:
x/12 = 1/4
x = 3 minutes
Therefore, B should be closed after 3 minutes so that the tank is full in 6 minutes.
Answer: Option (c) 3 min
Two pipes A and B can fill a tank in 8 minutes and 12 minutes respectively. If both the pipes are opened simultaneously, after what time should B be closed so that the tank is full in 6 minutes?
Solution:
Let's assume that B should be closed after x minutes so that the tank is full in 6 minutes.
Therefore, the amount of work done by pipe A in 6 minutes = 6/8 = 3/4
The amount of work done by pipe B in x minutes = x/12
The total amount of work done by both pipes in 6 minutes = 1
So, the equation becomes:
3/4 + (x/12) = 1
Solving for x, we get:
x/12 = 1/4
x = 3 minutes
Therefore, B should be closed after 3 minutes so that the tank is full in 6 minutes.
Answer: Option (c) 3 min
Two pipes A and B can fill a tank in 10 hours and 15 hours respectively while a third pipe C can empty the full tank in 20 hours. All the pipes are opened for 5 hours and then C is closed. Find the time in which the tank is full?- a)5.5 hrs
- b)6.5 hrs
- c)7.5 hrs
- d)8.5 hrs
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Two pipes A and B can fill a tank in 10 hours and 15 hours respectively while a third pipe C can empty the full tank in 20 hours. All the pipes are opened for 5 hours and then C is closed. Find the time in which the tank is full?
a)
5.5 hrs
b)
6.5 hrs
c)
7.5 hrs
d)
8.5 hrs
e)
None of these
|
Faizan Khan answered |
Pipe A, B and can fill a Full Tank in 24,36 and 48 Minutes respectively. All three Pipes are Opened simultaneously in a Tank which is already filled up to 1/6 of its capacity. A and B are opened for only First 6 Minutes and closed thereafter.Then C alone filled remaining Tank. Then in total how many Minutes does C filled the Tank?- a)12 Minutes
- b)14 Minutes
- c)16 Minutes
- d)18 Minutes
- e)20 Minutes
Correct answer is option 'E'. Can you explain this answer?
Pipe A, B and can fill a Full Tank in 24,36 and 48 Minutes respectively. All three Pipes are Opened simultaneously in a Tank which is already filled up to 1/6 of its capacity. A and B are opened for only First 6 Minutes and closed thereafter.Then C alone filled remaining Tank. Then in total how many Minutes does C filled the Tank?
a)
12 Minutes
b)
14 Minutes
c)
16 Minutes
d)
18 Minutes
e)
20 Minutes
|
|
Divey Sethi answered |
6*(1/24+1/36+1/48) + x/48 = 5/6
x = 14 Min
C = 6+14 = 20
x = 14 Min
C = 6+14 = 20
Three pipes P, Q and R can fill a tank in 12, 15 and 20 minutes respectively. If pipe P is opened all the time and pipe Q and R are opened for one hour alternatively. The tank will be full in- a)5hr
- b)6hr
- c)7hr
- d)8hr
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Three pipes P, Q and R can fill a tank in 12, 15 and 20 minutes respectively. If pipe P is opened all the time and pipe Q and R are opened for one hour alternatively. The tank will be full in
a)
5hr
b)
6hr
c)
7hr
d)
8hr
e)
None of these
|
|
Cstoppers Instructors answered |
(1/12 + 1/15) + (1/12 + 1/20) = 17/60 (in 2 hrs this much tank is filled)
so in 6 hrs 51/60 is filled. Remaining, 9/60 = (1/12 + 1/15)*t,
so T = 1hr so total = 6 + 1 = 7 hr
so in 6 hrs 51/60 is filled. Remaining, 9/60 = (1/12 + 1/15)*t,
so T = 1hr so total = 6 + 1 = 7 hr
If a pipe A can fill a tank 3 times faster than pipe B. If both the pipes can fill the tank in 32 minutes, then the slower pipe alone will be able to fill the tank in?- a)128 minutes
- b)124 minutes
- c)154 minutes
- d)168 minutes
- e)None of the Above
Correct answer is option 'A'. Can you explain this answer?
If a pipe A can fill a tank 3 times faster than pipe B. If both the pipes can fill the tank in 32 minutes, then the slower pipe alone will be able to fill the tank in?
a)
128 minutes
b)
124 minutes
c)
154 minutes
d)
168 minutes
e)
None of the Above
|
|
KS Coaching Center answered |
Time is taken by pipe A = x
Time is taken by pipe B = x/3
1/x + 3/x = 1/32
x = 128 minutes
Time is taken by pipe B = x/3
1/x + 3/x = 1/32
x = 128 minutes
A pipe can fill a tank in 20 minutes and another pipe can fill the tank in 40 minutes. There is a waste pipe which can empty the tank in 15 minutes. First two pipes are opened for 5 minutes and then the third pipe is also opened. In what time the cistern is emptied after the third pipe also opened- a)60
- b)75
- c)80
- d)90
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
A pipe can fill a tank in 20 minutes and another pipe can fill the tank in 40 minutes. There is a waste pipe which can empty the tank in 15 minutes. First two pipes are opened for 5 minutes and then the third pipe is also opened. In what time the cistern is emptied after the third pipe also opened
a)
60
b)
75
c)
80
d)
90
e)
None of these
|
|
Alok Verma answered |
(1/20 + 1/40)*5 + (1/20 + 1/40 – 1/15)*T = 1
Two pipes P and Q can fill a tank in 24 minutes and 27 minutes respectively. If both the pipes are opened simultaneously, after how much time should B be closed so that the tank is full in 8 minutes?- a)14 minutes
- b)12 minutes
- c)15 minutes
- d)18 minutes
- e)None of the Above
Correct answer is option 'D'. Can you explain this answer?
Two pipes P and Q can fill a tank in 24 minutes and 27 minutes respectively. If both the pipes are opened simultaneously, after how much time should B be closed so that the tank is full in 8 minutes?
a)
14 minutes
b)
12 minutes
c)
15 minutes
d)
18 minutes
e)
None of the Above
|
|
Sunny Pasi answered |
Three pipes P, Q and R can fill a Cistern in 6 hours. After working at it together for 2 hours, R is closed and P and Q can fill the remaining part in 7 hours. The number of hours taken by R alone to fill the Cistern is- a)14 hours
- b)12 hours
- c)15 hours
- d)18 hours
- e)None of the Above
Correct answer is option 'A'. Can you explain this answer?
Three pipes P, Q and R can fill a Cistern in 6 hours. After working at it together for 2 hours, R is closed and P and Q can fill the remaining part in 7 hours. The number of hours taken by R alone to fill the Cistern is
a)
14 hours
b)
12 hours
c)
15 hours
d)
18 hours
e)
None of the Above
|
|
Divey Sethi answered |
Part filled in 2 hours = 2/6 = 1/3
Remaining Part = (1-1/3) = 2/3
(P + Q)’s 7 hour work = 2/3
(P + Q)’s 1 hour work = 2/21
R’s 1 hour work = (P + Q + R) 1 hour work – (P + Q) 1 hour work
= (1/6 – 2/21) = 1/14 = 14 hours
Remaining Part = (1-1/3) = 2/3
(P + Q)’s 7 hour work = 2/3
(P + Q)’s 1 hour work = 2/21
R’s 1 hour work = (P + Q + R) 1 hour work – (P + Q) 1 hour work
= (1/6 – 2/21) = 1/14 = 14 hours
An inlet pipe can fill a tank in 4 hours and an outlet pipe can empty a tank in 3/7 of a tank in 3h. Find the time taken to fill the tank if they start working alternately.
- a)125/8 hours
- b)127/7 hours
- c)121/9 hours
- d)129/8 hours
- e)None
Correct answer is option 'B'. Can you explain this answer?
An inlet pipe can fill a tank in 4 hours and an outlet pipe can empty a tank in 3/7 of a tank in 3h. Find the time taken to fill the tank if they start working alternately.
a)
125/8 hours
b)
127/7 hours
c)
121/9 hours
d)
129/8 hours
e)
None
|
|
Nikita Singh answered |
Given:
Time taken by inlet pipe to fill the tank = 4 hours
Time taken by outlet pipe to empty 3/7 of a tank = 3 hours
Formula used:
Efficiency = Total work/Time taken
Calculation:
LCM of 4 and 7 = 28 = Total work
Efficiency of inlet pipe = 28/4 = 7 work
Efficiency of outlet pipe = 28/7 = 4 work
Work done in 2 hours = (7 – 4) = 3 work
Time taken to do 27 work = (2/3) × 27 hours
⇒ 18 hours
Time taken more to complete remaining 1 work = 1/7 hour
Total time taken = 18 + (1/7) hours
⇒ 127/7 hours
∴ The total time taken to fill the tank is 127/7 hours
A dam has four inlets – A, B, C and D. The dam can be filled in 12 minutes through the first three inlets and it can be filled in 15 minutes through the second, the third and fourth inlet also it can be filled through the first and the fourth inlet in 20 minutes. How much time required to fill up the dam by all the four inlets?- a)10 mins
- b)15 mins
- c)20 mins
- d)25 mins
- e)None of the Above
Correct answer is option 'A'. Can you explain this answer?
A dam has four inlets – A, B, C and D. The dam can be filled in 12 minutes through the first three inlets and it can be filled in 15 minutes through the second, the third and fourth inlet also it can be filled through the first and the fourth inlet in 20 minutes. How much time required to fill up the dam by all the four inlets?
a)
10 mins
b)
15 mins
c)
20 mins
d)
25 mins
e)
None of the Above
|
|
Alok Verma answered |
(1/A + 1/B + 1/C) = 1/12 …(i)
(1/B + 1/C + 1/D) = 1/15 …(ii)
(1/A + 1/D) = 1/20 …(iii)
From eqn (i) and (ii)
(1/A – 1/D) = 1/60…(iv)
From eqn (iii) and (iv)
A=30 D=60.
Let the time taken to full the tank = T
T(1/A + 1/B +1/C +1/D)= 1
T(1/30 + 1/15) = 1
T = 10 mins
(1/B + 1/C + 1/D) = 1/15 …(ii)
(1/A + 1/D) = 1/20 …(iii)
From eqn (i) and (ii)
(1/A – 1/D) = 1/60…(iv)
From eqn (iii) and (iv)
A=30 D=60.
Let the time taken to full the tank = T
T(1/A + 1/B +1/C +1/D)= 1
T(1/30 + 1/15) = 1
T = 10 mins
Pipe P is 4 times as fast as Q in filling a tank. If P takes 20 minutes to fill a tank, then what is the time taken by both the pipe P and Q to fill the tank?- a)12
- b)16
- c)18
- d)20
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Pipe P is 4 times as fast as Q in filling a tank. If P takes 20 minutes to fill a tank, then what is the time taken by both the pipe P and Q to fill the tank?
a)
12
b)
16
c)
18
d)
20
e)
None of these
|
|
Anaya Patel answered |
P takes 20 minutes and it is 4 times faster than Q, it means Q will take 80 minutes to fill the tank.
(1/20 + 1/80)*t = 1. We get t = 16
(1/20 + 1/80)*t = 1. We get t = 16
A pipe can fill a cistern in 16 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the cistern completely?- a)3 hours
- b)2 hours
- c)9 hours
- d)4 hours
- e)None of the Above
Correct answer is option 'C'. Can you explain this answer?
A pipe can fill a cistern in 16 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the cistern completely?
a)
3 hours
b)
2 hours
c)
9 hours
d)
4 hours
e)
None of the Above
|
|
Anaya Patel answered |
In One hour pipe can fill = 1/16
Time is taken to fill half of the tank = 1/2 * 16 = 8 hours
Part filled by four pipes in one hour = (8*1/16) = 1/2
Required Remaining Part = 1/2
Total time = 8 + 1 = 9
Time is taken to fill half of the tank = 1/2 * 16 = 8 hours
Part filled by four pipes in one hour = (8*1/16) = 1/2
Required Remaining Part = 1/2
Total time = 8 + 1 = 9
Twelve pipes are connected to a Cistern. Some of them are inlet pipes and the others are outlet pipes. Each of the inlet pipes can fill the tank in 8 hours and each of the outlet pipes can empty the cistern completely in 6 hours. If all the pipes are kept open, the empty tank gets filled in 24 hours. How many inlet pipes are there?- a)6
- b)8
- c)7
- d)4
- e)None of the Above
Correct answer is option 'C'. Can you explain this answer?
Twelve pipes are connected to a Cistern. Some of them are inlet pipes and the others are outlet pipes. Each of the inlet pipes can fill the tank in 8 hours and each of the outlet pipes can empty the cistern completely in 6 hours. If all the pipes are kept open, the empty tank gets filled in 24 hours. How many inlet pipes are there?
a)
6
b)
8
c)
7
d)
4
e)
None of the Above
|
|
Kavya Saxena answered |
(x/8)-[(12-x)/6] = 1/24
x = 7
x = 7
A pipe can fill a cistern in 8 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the cistern completely?- a)3 hours
- b)2 hours
- c)5 hours
- d)4 hours
- e)None of the Above
Correct answer is option 'C'. Can you explain this answer?
A pipe can fill a cistern in 8 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the cistern completely?
a)
3 hours
b)
2 hours
c)
5 hours
d)
4 hours
e)
None of the Above
|
Yash Patel answered |
In One hour pipe can fill = 1/8
Time is taken to fill half of the tank = 1/2 * 8 = 4 hours
Part filled by four pipes in one hour = (4*1/8) = 1/2
Required Remaining Part = 1/2
Total time = 4 + 1 = 5
Time is taken to fill half of the tank = 1/2 * 8 = 4 hours
Part filled by four pipes in one hour = (4*1/8) = 1/2
Required Remaining Part = 1/2
Total time = 4 + 1 = 5
Two pipes P and Q can fill a tank in 10 min and 12 min respectively and a waste pipe can carry off 12 litres of water per minute. If all the pipes are opened when the tank is full and it takes one hour to empty the tank. Find the capacity of the tank.- a)30
- b)45
- c)60
- d)75
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Two pipes P and Q can fill a tank in 10 min and 12 min respectively and a waste pipe can carry off 12 litres of water per minute. If all the pipes are opened when the tank is full and it takes one hour to empty the tank. Find the capacity of the tank.
a)
30
b)
45
c)
60
d)
75
e)
None of these
|
|
Aarav Sharma answered |
To solve this question, we can use the concept of work done.
Let's assume the capacity of the tank is 'x' liters.
The pipes P and Q can fill the tank in 10 minutes and 12 minutes respectively. This means that in one minute, pipes P and Q can fill 1/10 and 1/12 of the tank respectively.
The waste pipe can carry off 12 liters of water per minute. So, in one minute, it can empty 12 liters of water from the tank.
Given that it takes one hour to empty the tank, we need to find the capacity of the tank.
Let's calculate the work done by each pipe in one hour.
Work done by pipe P in one hour = (1/10) * 60 = 6x liters
Work done by pipe Q in one hour = (1/12) * 60 = 5x liters
Work done by waste pipe in one hour = 12 * 60 = 720 liters
As the tank is being emptied, the net work done by all the pipes should be negative.
So, the net work done in one hour = Work done by pipe P + Work done by pipe Q - Work done by waste pipe
Net work done in one hour = 6x + 5x - 720
Since the net work done is negative, we can write the equation as:
6x + 5x - 720 = -x
Simplifying the equation, we get:
11x - 720 = -x
12x = 720
x = 720/12
x = 60
Therefore, the capacity of the tank is 60 liters.
Hence, the correct answer is option C) 60.
Let's assume the capacity of the tank is 'x' liters.
The pipes P and Q can fill the tank in 10 minutes and 12 minutes respectively. This means that in one minute, pipes P and Q can fill 1/10 and 1/12 of the tank respectively.
The waste pipe can carry off 12 liters of water per minute. So, in one minute, it can empty 12 liters of water from the tank.
Given that it takes one hour to empty the tank, we need to find the capacity of the tank.
Let's calculate the work done by each pipe in one hour.
Work done by pipe P in one hour = (1/10) * 60 = 6x liters
Work done by pipe Q in one hour = (1/12) * 60 = 5x liters
Work done by waste pipe in one hour = 12 * 60 = 720 liters
As the tank is being emptied, the net work done by all the pipes should be negative.
So, the net work done in one hour = Work done by pipe P + Work done by pipe Q - Work done by waste pipe
Net work done in one hour = 6x + 5x - 720
Since the net work done is negative, we can write the equation as:
6x + 5x - 720 = -x
Simplifying the equation, we get:
11x - 720 = -x
12x = 720
x = 720/12
x = 60
Therefore, the capacity of the tank is 60 liters.
Hence, the correct answer is option C) 60.
A large cistern can be filled by two pipes P and Q in 15 minutes and 20 minutes respectively. How many minutes will it take to fill the Cistern from an empty state if Q is used for half the time and P and Q fill it together for the other half?- a)12 minutes
- b)17 minutes
- c)18 minutes
- d)19 minutes
- e)None of the Above
Correct answer is option 'A'. Can you explain this answer?
A large cistern can be filled by two pipes P and Q in 15 minutes and 20 minutes respectively. How many minutes will it take to fill the Cistern from an empty state if Q is used for half the time and P and Q fill it together for the other half?
a)
12 minutes
b)
17 minutes
c)
18 minutes
d)
19 minutes
e)
None of the Above
|
|
Aarav Sharma answered |
To solve this problem, we can use the concept of work. The work done by a pipe is inversely proportional to the time it takes to fill the cistern.
Let's assume that the capacity of the cistern is 1 unit.
Work done by pipe P in 1 minute = 1/15
Work done by pipe Q in 1 minute = 1/20
Work done by pipe Q in half the time = (1/20) * (1/2) = 1/40
Now, let's assume that it takes 'x' minutes to fill the cistern when Q is used for half the time and P and Q fill it together for the other half.
Work done by pipe P in x minutes = (1/15) * (x/2) = x/30
Work done by pipe Q in x minutes = (1/20) * (x/2) = x/40
The total work done by both pipes together is the sum of their individual work:
x/30 + x/40 = 1
To solve this equation, we need to find the least common multiple (LCM) of 30 and 40, which is 120. Multiplying both sides of the equation by 120, we get:
4x + 3x = 120
7x = 120
x = 120/7
Therefore, it will take approximately 17.14 minutes to fill the cistern from an empty state if Q is used for half the time and P and Q fill it together for the other half.
Since we are looking for the closest whole number, the answer is 17 minutes, which corresponds to option A.
Let's assume that the capacity of the cistern is 1 unit.
Work done by pipe P in 1 minute = 1/15
Work done by pipe Q in 1 minute = 1/20
Work done by pipe Q in half the time = (1/20) * (1/2) = 1/40
Now, let's assume that it takes 'x' minutes to fill the cistern when Q is used for half the time and P and Q fill it together for the other half.
Work done by pipe P in x minutes = (1/15) * (x/2) = x/30
Work done by pipe Q in x minutes = (1/20) * (x/2) = x/40
The total work done by both pipes together is the sum of their individual work:
x/30 + x/40 = 1
To solve this equation, we need to find the least common multiple (LCM) of 30 and 40, which is 120. Multiplying both sides of the equation by 120, we get:
4x + 3x = 120
7x = 120
x = 120/7
Therefore, it will take approximately 17.14 minutes to fill the cistern from an empty state if Q is used for half the time and P and Q fill it together for the other half.
Since we are looking for the closest whole number, the answer is 17 minutes, which corresponds to option A.
A full tank gets emptied in 8 minutes due to the presence of a leak in it. On opening a tap which can fill the tank at the rate of 9 L/min, the tank get emptied in 12 min. Find the capacity of a tank?- a)120 L
- b)240 L
- c)216 L
- d)224 L
- e)None of the Above
Correct answer is option 'C'. Can you explain this answer?
A full tank gets emptied in 8 minutes due to the presence of a leak in it. On opening a tap which can fill the tank at the rate of 9 L/min, the tank get emptied in 12 min. Find the capacity of a tank?
a)
120 L
b)
240 L
c)
216 L
d)
224 L
e)
None of the Above
|
|
KS Coaching Center answered |
a = 8; b = 9; C = 12
Capacity of a tank = a*b*c/c-a = 8*9*12/4 = 216 Litre.
Capacity of a tank = a*b*c/c-a = 8*9*12/4 = 216 Litre.
Three taps P, Q and R can fill a tank in 12, 15 and 20 hours respectively. If P is open all the time and Q, R are open for one hour each alternatively, the tank will be full in- a)3 hours
- b)2 hours
- c)7 hours
- d)4 hours
- e)None of the Above
Correct answer is option 'C'. Can you explain this answer?
Three taps P, Q and R can fill a tank in 12, 15 and 20 hours respectively. If P is open all the time and Q, R are open for one hour each alternatively, the tank will be full in
a)
3 hours
b)
2 hours
c)
7 hours
d)
4 hours
e)
None of the Above
|
|
Aisha Gupta answered |
(P + Q)’s 1 hour work = 1/12 + 1/15 = 3/20
(P + R)’s 1 hour work = 1/12 + 1/20 = 2/15
For 2 hrs = (3/20 + 2/15) = 17/60
For 6 hrs = (3*17/60) = 17/20
Remaining Part = 1 – 17/20 = 3/20 filled by P and Q in 1 hour
(P + R)’s 1 hour work = 1/12 + 1/20 = 2/15
For 2 hrs = (3/20 + 2/15) = 17/60
For 6 hrs = (3*17/60) = 17/20
Remaining Part = 1 – 17/20 = 3/20 filled by P and Q in 1 hour
Two pipes can fill a tank in 15 and 20 hours respectively. The pipes are opened simultaneously and it is found that due to the leakage in the bottom, 17/7 hours extra are taken extra to fill the tank. If the tank is full, in what approximate time would the leak empty it?- a)27 hrs
- b)32 hrs
- c)36 hrs
- d)39 hrs
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
Two pipes can fill a tank in 15 and 20 hours respectively. The pipes are opened simultaneously and it is found that due to the leakage in the bottom, 17/7 hours extra are taken extra to fill the tank. If the tank is full, in what approximate time would the leak empty it?
a)
27 hrs
b)
32 hrs
c)
36 hrs
d)
39 hrs
e)
None of these
|
|
Divey Sethi answered |
Total time taken by both pipes before the leak was developed = 60/7 hours now, leaks is developed which will take T time to empty the tank so, (1/15 +1/20 – 1/T) = 1/11
solve for T, we will get 660/17 hours = 39 hours (approx.)
solve for T, we will get 660/17 hours = 39 hours (approx.)
Three pipes P, Q and R connected to a Cistern. The first pipe (i.e) P can fill 1/2 part of the tank in one hour, second pipe, Q can fill 1/3 part of the cistern in one hour. R is connected to empty the cistern. After opening all the three pipes 7/12 part of the cistern. Then how much time required to empty the cistern completely?- a)2 hours
- b)3 hours
- c)4 hours
- d)5 hours
- e)None of the Above
Correct answer is option 'C'. Can you explain this answer?
Three pipes P, Q and R connected to a Cistern. The first pipe (i.e) P can fill 1/2 part of the tank in one hour, second pipe, Q can fill 1/3 part of the cistern in one hour. R is connected to empty the cistern. After opening all the three pipes 7/12 part of the cistern. Then how much time required to empty the cistern completely?
a)
2 hours
b)
3 hours
c)
4 hours
d)
5 hours
e)
None of the Above
|
|
Kavya Saxena answered |
In 1 hour, P can fill = 1/2 Part
Time taken to fill the Cistern by Pipe P = 2 hours
In 1 hour, Q can fill = 1/3 Part
Time taken to fill the Cistern by Pipe P = 3 hours
[1/2 + 1/3 – 1/R] = 7/12
1/R = 1/4
Time required to empty the Cistern = 4 hours
Time taken to fill the Cistern by Pipe P = 2 hours
In 1 hour, Q can fill = 1/3 Part
Time taken to fill the Cistern by Pipe P = 3 hours
[1/2 + 1/3 – 1/R] = 7/12
1/R = 1/4
Time required to empty the Cistern = 4 hours
A Cistern has an inlet pipe and outlet pipe. The inlet pipe fills the cistern completely in 1 hour 20 minutes when the outlet pipe is plugged. The outlet pipe empties the tank completely in 4 hours when the inlet pipe is plugged. If both pipes are opened simultaneously at a time when the tank was one-third filled, when will the tank fill thereafter?- a)3 hours
- b)2 hours
- c)5 hours
- d)4 hours
- e)None of the Above
Correct answer is option 'B'. Can you explain this answer?
A Cistern has an inlet pipe and outlet pipe. The inlet pipe fills the cistern completely in 1 hour 20 minutes when the outlet pipe is plugged. The outlet pipe empties the tank completely in 4 hours when the inlet pipe is plugged. If both pipes are opened simultaneously at a time when the tank was one-third filled, when will the tank fill thereafter?
a)
3 hours
b)
2 hours
c)
5 hours
d)
4 hours
e)
None of the Above
|
|
Bank Exams India answered |
Inlet pipe Efficiency = 100/(8/6) = 75%
Outlet pipe Efficiency = 100/(4) = 25%
Net Efficiency = 75 – 25 = 50%(1/3)filled
2/3 filled = 100%
Required time = 100/50 = 2 hours
Outlet pipe Efficiency = 100/(4) = 25%
Net Efficiency = 75 – 25 = 50%(1/3)filled
2/3 filled = 100%
Required time = 100/50 = 2 hours
A Cistern is two-fifth full. Pipe A can fill a tank in 10 minutes and pipe B can empty it in 6 minutes. If both the pipes are open,how long will it take to empty or fill the tank completely?- a)5 minutes
- b)4 minutes
- c)6 minutes
- d)8 minutes
- e)None of the Above
Correct answer is option 'C'. Can you explain this answer?
A Cistern is two-fifth full. Pipe A can fill a tank in 10 minutes and pipe B can empty it in 6 minutes. If both the pipes are open,how long will it take to empty or fill the tank completely?
a)
5 minutes
b)
4 minutes
c)
6 minutes
d)
8 minutes
e)
None of the Above
|
|
Aarav Sharma answered |
Given Information
- The cistern is two-fifth full.
- Pipe A can fill a tank in 10 minutes.
- Pipe B can empty the same tank in 6 minutes.
To Find:
- The time taken to empty/fill the tank completely when both pipes are open.
Approach:
- Let's assume that the capacity of the tank is 10 liters.
- As per the question, the cistern is two-fifth full, which means it contains 4 liters of water (2/5 * 10).
- Now, we need to find out the net flow rate of water when both pipes are open.
- Pipe A can fill the tank in 10 minutes, which means it can fill 1 liter in 1 minute.
- Pipe B can empty the same tank in 6 minutes, which means it can empty 1.67 liters (10/6) in 1 minute.
- Therefore, the net flow rate of water when both pipes are open = (1 - 1.67) = -0.67 liters/minute.
- The negative sign indicates that the water is being emptied from the tank.
Calculation:
- To empty the remaining 4 liters of water from the cistern, it will take 4/0.67 = 5.97 minutes.
- Therefore, the time taken to empty/fill the tank completely when both pipes are open is approximately 6 minutes.
Hence, the correct answer is option (c) 6 minutes.
- The cistern is two-fifth full.
- Pipe A can fill a tank in 10 minutes.
- Pipe B can empty the same tank in 6 minutes.
To Find:
- The time taken to empty/fill the tank completely when both pipes are open.
Approach:
- Let's assume that the capacity of the tank is 10 liters.
- As per the question, the cistern is two-fifth full, which means it contains 4 liters of water (2/5 * 10).
- Now, we need to find out the net flow rate of water when both pipes are open.
- Pipe A can fill the tank in 10 minutes, which means it can fill 1 liter in 1 minute.
- Pipe B can empty the same tank in 6 minutes, which means it can empty 1.67 liters (10/6) in 1 minute.
- Therefore, the net flow rate of water when both pipes are open = (1 - 1.67) = -0.67 liters/minute.
- The negative sign indicates that the water is being emptied from the tank.
Calculation:
- To empty the remaining 4 liters of water from the cistern, it will take 4/0.67 = 5.97 minutes.
- Therefore, the time taken to empty/fill the tank completely when both pipes are open is approximately 6 minutes.
Hence, the correct answer is option (c) 6 minutes.
Two pipes can separately fill the tank in 15hrs and 30hrs respectively. Both the pipe are opened and when the tank is 1/3 full a leak is developed due to which 1/3 water supplied by the pipe leaks out. What is the total time to fill the tank?- a)20/3 hr
- b)35/3 hr
- c)40/3 hr
- d)50/3 hr
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Two pipes can separately fill the tank in 15hrs and 30hrs respectively. Both the pipe are opened and when the tank is 1/3 full a leak is developed due to which 1/3 water supplied by the pipe leaks out. What is the total time to fill the tank?
a)
20/3 hr
b)
35/3 hr
c)
40/3 hr
d)
50/3 hr
e)
None of these
|
|
Faizan Khan answered |
(1/15 + 1/30)*T1 = 1/3, T1 = 10/3 hr
now after leak is developed, [(1/15 + 1/30) – (1/3)*(1/15 + 1/30)]*T2 = 2/3
T2 = 10 hr. So total time = 10 + 10/3 = 40/3 hr
now after leak is developed, [(1/15 + 1/30) – (1/3)*(1/15 + 1/30)]*T2 = 2/3
T2 = 10 hr. So total time = 10 + 10/3 = 40/3 hr
Chapter doubts & questions for Pipes and Cistern - IBPS PO Prelims & Mains Preparation 2025 is part of Bank Exams exam preparation. The chapters have been prepared according to the Bank Exams exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for Bank Exams 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
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