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Select the most stable covalent hydride a)BiG3 b)NH3 c)HF d)SbH3 Correct answer is c please explain it?
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Select the most stable covalent hydride a)BiG3 b)NH3 c)HF d)SbH3 Corre...
The most stable covalent hydride among the given options is HF (hydrogen fluoride).
1. Stability of Covalent Hydrides:
Covalent hydrides are compounds formed by the combination of hydrogen with other elements. The stability of these hydrides is determined by factors such as the electronegativity difference between the hydrogen and the other element, the bond strength, and the polarity of the molecule.
2. Electronegativity Difference:
The electronegativity difference between hydrogen and the other element affects the polarity of the bond. Higher electronegativity difference leads to a more polar bond, which results in a more stable hydride.
3. Bond Strength:
The strength of the bond between hydrogen and the other element also contributes to the stability of the hydride. Stronger bonds are generally more stable.
4. Polarity of the Molecule:
The polarity of the molecule is determined by the electronegativity difference and the molecular geometry. A more polar molecule is generally more stable.
5. Analysis of Options:
a) BiH3 (bismuth hydride): Bismuth is a metal with a low electronegativity, and the electronegativity difference with hydrogen is relatively large. This results in a polar bond and a stable hydride. However, BiH3 is less stable compared to the other options.
b) NH3 (ammonia): Nitrogen is more electronegative than hydrogen, resulting in a polar bond. NH3 is a stable hydride due to the small size of nitrogen and the strong bond between nitrogen and hydrogen.
c) HF (hydrogen fluoride): Fluorine is the most electronegative element, resulting in a highly polar bond with hydrogen. HF is a stable hydride due to the small size of fluorine and the strong bond between fluorine and hydrogen.
d) SbH3 (antimony hydride): Antimony has a lower electronegativity than fluorine but higher than bismuth. SbH3 has a moderately polar bond and is less stable compared to HF.
6. Conclusion:
Among the given options, HF (hydrogen fluoride) is the most stable covalent hydride. It has a highly polar bond due to the large electronegativity difference between hydrogen and fluorine. The small size of fluorine and the strong bond between fluorine and hydrogen contribute to the stability of HF.
1. Stability of Covalent Hydrides:
Covalent hydrides are compounds formed by the combination of hydrogen with other elements. The stability of these hydrides is determined by factors such as the electronegativity difference between the hydrogen and the other element, the bond strength, and the polarity of the molecule.
2. Electronegativity Difference:
The electronegativity difference between hydrogen and the other element affects the polarity of the bond. Higher electronegativity difference leads to a more polar bond, which results in a more stable hydride.
3. Bond Strength:
The strength of the bond between hydrogen and the other element also contributes to the stability of the hydride. Stronger bonds are generally more stable.
4. Polarity of the Molecule:
The polarity of the molecule is determined by the electronegativity difference and the molecular geometry. A more polar molecule is generally more stable.
5. Analysis of Options:
a) BiH3 (bismuth hydride): Bismuth is a metal with a low electronegativity, and the electronegativity difference with hydrogen is relatively large. This results in a polar bond and a stable hydride. However, BiH3 is less stable compared to the other options.
b) NH3 (ammonia): Nitrogen is more electronegative than hydrogen, resulting in a polar bond. NH3 is a stable hydride due to the small size of nitrogen and the strong bond between nitrogen and hydrogen.
c) HF (hydrogen fluoride): Fluorine is the most electronegative element, resulting in a highly polar bond with hydrogen. HF is a stable hydride due to the small size of fluorine and the strong bond between fluorine and hydrogen.
d) SbH3 (antimony hydride): Antimony has a lower electronegativity than fluorine but higher than bismuth. SbH3 has a moderately polar bond and is less stable compared to HF.
6. Conclusion:
Among the given options, HF (hydrogen fluoride) is the most stable covalent hydride. It has a highly polar bond due to the large electronegativity difference between hydrogen and fluorine. The small size of fluorine and the strong bond between fluorine and hydrogen contribute to the stability of HF.
Community Answer
Select the most stable covalent hydride a)BiG3 b)NH3 c)HF d)SbH3 Corre...
HF is most stable due to strong hydrogen bonding between H and F
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Select the most stable covalent hydride a)BiG3 b)NH3 c)HF d)SbH3 Correct answer is c please explain it?
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Select the most stable covalent hydride a)BiG3 b)NH3 c)HF d)SbH3 Correct answer is c please explain it? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Select the most stable covalent hydride a)BiG3 b)NH3 c)HF d)SbH3 Correct answer is c please explain it? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Select the most stable covalent hydride a)BiG3 b)NH3 c)HF d)SbH3 Correct answer is c please explain it?.
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