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A ball is thrown vertically upward with speed V form a heigh H metre above ground. The time taken for ball to hit the ground
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A ball is thrown vertically upward with speed V form a heigh H metre a...
Introduction:
When a ball is thrown vertically upward with an initial speed V from a height H above the ground, it follows a parabolic trajectory. The ball will eventually reach its maximum height and then fall back towards the ground due to the force of gravity. The time taken for the ball to hit the ground can be determined using the following steps:
Determining the time taken to reach maximum height:
1. The initial velocity of the ball is V, and it is thrown vertically upward. Therefore, the initial velocity can be considered as the final velocity at maximum height.
2. At the maximum height, the ball momentarily comes to rest. This means that the final velocity at maximum height is 0 m/s.
3. Using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken, we can rearrange the equation to solve for time.
4. Substituting the given values, we have 0 = V - gt, where g is the acceleration due to gravity (approximately 9.8 m/s²).
5. Solving the equation for t, we get t = V/g.
Determining the time taken to hit the ground:
1. The ball is now falling back towards the ground with an initial velocity of 0 m/s and an acceleration of -g (negative sign indicating the direction opposite to the initial motion).
2. To determine the time taken for the ball to hit the ground, we can again use the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken.
3. The final velocity when the ball hits the ground is again 0 m/s.
4. Rearranging the equation, we have 0 = 0 - gt.
5. Solving for t, we find t = 0/g.
Conclusion:
The time taken for the ball to hit the ground can be determined by adding the time taken to reach the maximum height (t = V/g) and the time taken to fall back to the ground (t = 0/g). The total time taken is t = V/g + 0/g = V/g. Therefore, the time taken for the ball to hit the ground is equal to the initial velocity divided by the acceleration due to gravity.
When a ball is thrown vertically upward with an initial speed V from a height H above the ground, it follows a parabolic trajectory. The ball will eventually reach its maximum height and then fall back towards the ground due to the force of gravity. The time taken for the ball to hit the ground can be determined using the following steps:
Determining the time taken to reach maximum height:
1. The initial velocity of the ball is V, and it is thrown vertically upward. Therefore, the initial velocity can be considered as the final velocity at maximum height.
2. At the maximum height, the ball momentarily comes to rest. This means that the final velocity at maximum height is 0 m/s.
3. Using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken, we can rearrange the equation to solve for time.
4. Substituting the given values, we have 0 = V - gt, where g is the acceleration due to gravity (approximately 9.8 m/s²).
5. Solving the equation for t, we get t = V/g.
Determining the time taken to hit the ground:
1. The ball is now falling back towards the ground with an initial velocity of 0 m/s and an acceleration of -g (negative sign indicating the direction opposite to the initial motion).
2. To determine the time taken for the ball to hit the ground, we can again use the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken.
3. The final velocity when the ball hits the ground is again 0 m/s.
4. Rearranging the equation, we have 0 = 0 - gt.
5. Solving for t, we find t = 0/g.
Conclusion:
The time taken for the ball to hit the ground can be determined by adding the time taken to reach the maximum height (t = V/g) and the time taken to fall back to the ground (t = 0/g). The total time taken is t = V/g + 0/g = V/g. Therefore, the time taken for the ball to hit the ground is equal to the initial velocity divided by the acceleration due to gravity.
Community Answer
A ball is thrown vertically upward with speed V form a heigh H metre a...
it's diagrammatic...so I can't even explain u well...so sorry for that...🙁
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A ball is thrown vertically upward with speed V form a heigh H metre above ground. The time taken for ball to hit the ground
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A ball is thrown vertically upward with speed V form a heigh H metre above ground. The time taken for ball to hit the ground for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball is thrown vertically upward with speed V form a heigh H metre above ground. The time taken for ball to hit the ground covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball is thrown vertically upward with speed V form a heigh H metre above ground. The time taken for ball to hit the ground.
A ball is thrown vertically upward with speed V form a heigh H metre above ground. The time taken for ball to hit the ground for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball is thrown vertically upward with speed V form a heigh H metre above ground. The time taken for ball to hit the ground covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball is thrown vertically upward with speed V form a heigh H metre above ground. The time taken for ball to hit the ground.
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