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A capacitor is charged with a battery and energy stored is U. After disconnecting battery another capacitor of same capacity is connected in parallel to the first capacitor. Then energy stored in each capacitor is 1)U/2 2)U/4 3)4U 4)2U?
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A capacitor is charged with a battery and energy stored is U. After di...
Energy stored after connecting with another capacitor
( U) = q^2/2C
V = q/2C
Energy in each capacitor =1/2CV^2
= 1/2(q^2/2C)^2
= U/4
Answer is 2.
Community Answer
A capacitor is charged with a battery and energy stored is U. After di...
**Explanation:**

When a capacitor is charged with a battery, it stores electrical energy in its electric field. The energy stored in a capacitor is given by the formula:

U = (1/2) * C * V^2

Where U is the energy stored, C is the capacitance of the capacitor, and V is the voltage across the capacitor.

**Step 1: Charging the Capacitor**

Let's assume that the initial capacitance of the capacitor is C and the voltage across it is V. When the capacitor is charged with a battery, the energy stored in it is:

U = (1/2) * C * V^2

**Step 2: Connecting the Second Capacitor in Parallel**

When the second capacitor is connected in parallel to the first capacitor, the total capacitance becomes 2C (sum of the two capacitances). The voltage across the capacitors remains the same, as they are connected in parallel. Therefore, the energy stored in each capacitor can be calculated by using the formula:

U' = (1/2) * (2C) * V^2
= C * V^2

**Step 3: Comparing the Energies**

Now, let's compare the energy stored in each capacitor before and after connecting the second capacitor in parallel.

Initially, the energy stored in the first capacitor is U = (1/2) * C * V^2

After connecting the second capacitor in parallel, the energy stored in each capacitor is U' = C * V^2

Comparing the two energy values, we can see that:

U' = U/2

Therefore, the energy stored in each capacitor after connecting the second capacitor in parallel is U/2.

**Answer: 1) U/2**
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A capacitor is charged with a battery and energy stored is U. After disconnecting battery another capacitor of same capacity is connected in parallel to the first capacitor. Then energy stored in each capacitor is 1)U/2 2)U/4 3)4U 4)2U?
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