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For a reaction NH4COONH3--->2NH3 CO2,the equlibrium pressure is 3atm,kp for the reaction will be. A)27 B)4 C)3 D)9 Answer is B)4 plz explain me how we find this?
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For a reaction NH4COONH3--->2NH3 CO2,the equlibrium pressure is 3atm...
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For a reaction NH4COONH3--->2NH3 CO2,the equlibrium pressure is 3atm...
To find the value of Kp for the given reaction NH4COONH3 ⟶ 2NH3 + CO2, we can use the equilibrium partial pressures.

1. Write the balanced chemical equation:
NH4COONH3 ⟶ 2NH3 + CO2

2. Write the expression for Kp:
Kp = (P(NH3))^2 * P(CO2)

3. Identify the given equilibrium pressure:
The given equilibrium pressure is 3 atm.

4. Use the given equilibrium pressure to find the partial pressures:
Since the reaction involves a 1:2 stoichiometric ratio between NH3 and CO2, we can assume that the partial pressure of NH3 is x atm. Therefore, the partial pressure of CO2 is 2x atm.

5. Substitute the partial pressures into the Kp expression:
Kp = (x)^2 * (2x)
= 2x^3

6. Substitute the given equilibrium pressure into the Kp expression:
3 atm = 2x^3

7. Solve for x:
Divide both sides of the equation by 2:
1.5 atm = x^3

Take the cube root of both sides:
x = 1.144 atm

8. Substitute the value of x into the Kp expression:
Kp = 2(1.144 atm)^3
= 4 atm

Therefore, the value of Kp for the given reaction is 4 atm.
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For a reaction NH4COONH3--->2NH3 CO2,the equlibrium pressure is 3atm,kp for the reaction will be. A)27 B)4 C)3 D)9 Answer is B)4 plz explain me how we find this?
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