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A series R-L-C (R= 10 ohm, Xl = Xc = 20 ohm) circuit is supplied by V = 10Sinwt volt then power dissipation in circuit is A) zero B) 10 watt C) 5 watt D) 2.5 watt?
Most Upvoted Answer
A series R-L-C (R= 10 ohm, Xl = Xc = 20 ohm) circuit is supplied by V ...
**Solution:**
To find the power dissipation in the circuit, we need to calculate the total impedance and then use the formula for power dissipation.
**1. Finding the total impedance:**
The impedance of the circuit can be calculated using the formula:
Z = sqrt(R^2 + (Xl - Xc)^2)
Given:
R = 10 ohm
Xl = Xc = 20 ohm
Substituting the values, we get:
Z = sqrt((10)^2 + (20 - 20)^2)
= sqrt(100 + 0)
= sqrt(100)
= 10 ohm
**2. Calculating the power dissipation:**
The power dissipated in a series R-L-C circuit is given by the formula:
P = V^2 / Z
Given:
V = 10Sinwt volt
Z = 10 ohm
Substituting the values, we get:
P = (10Sinwt)^2 / 10
= 100Sin^2(wt) / 10
= 10Sin^2(wt)
Since the power is given by the square of the sine function, the average power over one complete cycle is given by:
P_avg = (1/T) * ∫[0 to T] 10Sin^2(wt) dt
To calculate the average power, we need to integrate Sin^2(wt) over one complete cycle. The integral of Sin^2(wt) is equal to T/2, where T is the time period.
Therefore, the average power dissipated is:
P_avg = (1/T) * (T/2)
= 1/2
Since the power dissipation is given in watts, the answer can be rounded to the nearest whole number.
So, the power dissipation in the circuit is **1 watt** (approximately).
Therefore, the correct option is not provided in the given choices.
To find the power dissipation in the circuit, we need to calculate the total impedance and then use the formula for power dissipation.
**1. Finding the total impedance:**
The impedance of the circuit can be calculated using the formula:
Z = sqrt(R^2 + (Xl - Xc)^2)
Given:
R = 10 ohm
Xl = Xc = 20 ohm
Substituting the values, we get:
Z = sqrt((10)^2 + (20 - 20)^2)
= sqrt(100 + 0)
= sqrt(100)
= 10 ohm
**2. Calculating the power dissipation:**
The power dissipated in a series R-L-C circuit is given by the formula:
P = V^2 / Z
Given:
V = 10Sinwt volt
Z = 10 ohm
Substituting the values, we get:
P = (10Sinwt)^2 / 10
= 100Sin^2(wt) / 10
= 10Sin^2(wt)
Since the power is given by the square of the sine function, the average power over one complete cycle is given by:
P_avg = (1/T) * ∫[0 to T] 10Sin^2(wt) dt
To calculate the average power, we need to integrate Sin^2(wt) over one complete cycle. The integral of Sin^2(wt) is equal to T/2, where T is the time period.
Therefore, the average power dissipated is:
P_avg = (1/T) * (T/2)
= 1/2
Since the power dissipation is given in watts, the answer can be rounded to the nearest whole number.
So, the power dissipation in the circuit is **1 watt** (approximately).
Therefore, the correct option is not provided in the given choices.
Community Answer
A series R-L-C (R= 10 ohm, Xl = Xc = 20 ohm) circuit is supplied by V ...
C)5 watt .. using the equations..p=(v^2)÷R
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A series R-L-C (R= 10 ohm, Xl = Xc = 20 ohm) circuit is supplied by V = 10Sinwt volt then power dissipation in circuit is A) zero B) 10 watt C) 5 watt D) 2.5 watt?
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A series R-L-C (R= 10 ohm, Xl = Xc = 20 ohm) circuit is supplied by V = 10Sinwt volt then power dissipation in circuit is A) zero B) 10 watt C) 5 watt D) 2.5 watt? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A series R-L-C (R= 10 ohm, Xl = Xc = 20 ohm) circuit is supplied by V = 10Sinwt volt then power dissipation in circuit is A) zero B) 10 watt C) 5 watt D) 2.5 watt? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A series R-L-C (R= 10 ohm, Xl = Xc = 20 ohm) circuit is supplied by V = 10Sinwt volt then power dissipation in circuit is A) zero B) 10 watt C) 5 watt D) 2.5 watt?.
A series R-L-C (R= 10 ohm, Xl = Xc = 20 ohm) circuit is supplied by V = 10Sinwt volt then power dissipation in circuit is A) zero B) 10 watt C) 5 watt D) 2.5 watt? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A series R-L-C (R= 10 ohm, Xl = Xc = 20 ohm) circuit is supplied by V = 10Sinwt volt then power dissipation in circuit is A) zero B) 10 watt C) 5 watt D) 2.5 watt? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A series R-L-C (R= 10 ohm, Xl = Xc = 20 ohm) circuit is supplied by V = 10Sinwt volt then power dissipation in circuit is A) zero B) 10 watt C) 5 watt D) 2.5 watt?.
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