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In series RLC circuit, L = 1 mH, C = 0.1 uF. R=10 ohm and applied voltage is V= 9 sinwt. At resonance peak voltage across capacitor is:?
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In series RLC circuit, L = 1 mH, C = 0.1 uF. R=10 ohm and applied volt...
As the condition is of resonance , there won't be any contribution of capacitor and inductor in the TOTAL REACTANCE.....V=V0 Sin wt.....peak voltage V0=9V
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In series RLC circuit, L = 1 mH, C = 0.1 uF. R=10 ohm and applied volt...
Resonance in RLC Circuit
Resonance in an RLC circuit occurs when the inductive and capacitive reactances cancel each other out, resulting in only the resistance affecting the circuit.
Calculation of Resonant Frequency
The resonant frequency (f) of an RLC circuit can be calculated using the following formula:
f = 1/(2π√LC)
Substituting the given values, we get:
f = 1/(2π√1x10^-3x0.1x10^-6)
f = 1591.55 Hz
Peak Voltage Across Capacitor
At resonance, the impedance of the circuit is minimum, and the current flowing through it is maximum. The voltage across the capacitor (Vc) can be calculated using the following formula:
Vc = IXC
where I is the current flowing through the circuit, and XC is the capacitive reactance.
At resonance, XC = XL, where XL is the inductive reactance. The current flowing through the circuit (I) can be calculated using Ohm's law:
I = V/R
where V is the applied voltage and R is the resistance of the circuit.
Substituting the given values, we get:
I = 9/10
I = 0.9 A
At resonance, XC = XL = 2πfL = 2π(1591.55)(0.001) = 10
Substituting the values, we get:
Vc = (0.9)(10^-7)
Vc = 90 mV
Therefore, the peak voltage across the capacitor at resonance is 90 mV.
Resonance in an RLC circuit occurs when the inductive and capacitive reactances cancel each other out, resulting in only the resistance affecting the circuit.
Calculation of Resonant Frequency
The resonant frequency (f) of an RLC circuit can be calculated using the following formula:
f = 1/(2π√LC)
Substituting the given values, we get:
f = 1/(2π√1x10^-3x0.1x10^-6)
f = 1591.55 Hz
Peak Voltage Across Capacitor
At resonance, the impedance of the circuit is minimum, and the current flowing through it is maximum. The voltage across the capacitor (Vc) can be calculated using the following formula:
Vc = IXC
where I is the current flowing through the circuit, and XC is the capacitive reactance.
At resonance, XC = XL, where XL is the inductive reactance. The current flowing through the circuit (I) can be calculated using Ohm's law:
I = V/R
where V is the applied voltage and R is the resistance of the circuit.
Substituting the given values, we get:
I = 9/10
I = 0.9 A
At resonance, XC = XL = 2πfL = 2π(1591.55)(0.001) = 10
Substituting the values, we get:
Vc = (0.9)(10^-7)
Vc = 90 mV
Therefore, the peak voltage across the capacitor at resonance is 90 mV.
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In series RLC circuit, L = 1 mH, C = 0.1 uF. R=10 ohm and applied voltage is V= 9 sinwt. At resonance peak voltage across capacitor is:?
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In series RLC circuit, L = 1 mH, C = 0.1 uF. R=10 ohm and applied voltage is V= 9 sinwt. At resonance peak voltage across capacitor is:? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In series RLC circuit, L = 1 mH, C = 0.1 uF. R=10 ohm and applied voltage is V= 9 sinwt. At resonance peak voltage across capacitor is:? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In series RLC circuit, L = 1 mH, C = 0.1 uF. R=10 ohm and applied voltage is V= 9 sinwt. At resonance peak voltage across capacitor is:?.
In series RLC circuit, L = 1 mH, C = 0.1 uF. R=10 ohm and applied voltage is V= 9 sinwt. At resonance peak voltage across capacitor is:? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In series RLC circuit, L = 1 mH, C = 0.1 uF. R=10 ohm and applied voltage is V= 9 sinwt. At resonance peak voltage across capacitor is:? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In series RLC circuit, L = 1 mH, C = 0.1 uF. R=10 ohm and applied voltage is V= 9 sinwt. At resonance peak voltage across capacitor is:?.
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