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The volume of an air bubble is doubled as it rises from the bottom of lake to its surface.The atmospheric pressure is 75 cm of mercury.The ratio of density of mercury to that of lake water is 40/3 .The depth of the lake in metre is 1)10 2)15 3)20 4)25?
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The volume of an air bubble is doubled as it rises from the bottom of ...

Given Data:
- Atmospheric pressure: 75 cm of mercury
- Ratio of density of mercury to lake water: 40/3

Calculating the Depth of the Lake:
- When the air bubble rises, the pressure decreases.
- Using Boyle's Law (P1V1 = P2V2), we can find the pressure at the surface when the volume is doubled.
- Let the initial volume of the air bubble be V1 and the final volume be 2V1.
- Initial pressure (P1) = 75 cm of mercury
- Final pressure (P2) = atmospheric pressure = 0 cm of mercury
- Applying Boyle's Law: P1V1 = P2V2
- 75 * V1 = 0 * 2V1
- V1 = 0

Calculating the Density of the Lake:
- The pressure at the bottom of the lake can be calculated by converting the atmospheric pressure to the unit of density.
- Density of mercury = 13.6 g/cm³
- Density of water = 1 g/cm³
- Ratio of density = 40/3
- Pressure at the bottom of the lake = 75 cm of mercury = 75 * 13.6 = 1020 g/cm²

Calculating the Depth:
- Using the formula: Pressure = Density x Acceleration due to gravity x Height
- 1020 = (40/3) x 9.8 x h
- h = 1020 / ((40/3) x 9.8)
- h = 15 meters

Therefore, the depth of the lake is 15 meters.

Answer: 2) 15
Community Answer
The volume of an air bubble is doubled as it rises from the bottom of ...
Option 1) 10 metre
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The volume of an air bubble is doubled as it rises from the bottom of lake to its surface.The atmospheric pressure is 75 cm of mercury.The ratio of density of mercury to that of lake water is 40/3 .The depth of the lake in metre is 1)10 2)15 3)20 4)25?
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