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When 1 g of water at 0 degree Celsius and 1×10*5 N/m2 pressure is converteded into Ice of volume 1.092cm3,the workdone Will be????? ans is 0.0091 how?
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When 1 g of water at 0 degree Celsius and 1×10*5 N/m2 pressure is conv...
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When 1 g of water at 0 degree Celsius and 1×10*5 N/m2 pressure is conv...
Given:
Mass of water (m) = 1 g = 0.001 kg
Pressure (P) = 1 × 10^5 N/m^2
Volume of ice (V) = 1.092 cm^3 = 1.092 × 10^(-6) m^3
To find:
Work done (W) in converting water to ice
Formula:
Work done (W) = Pressure (P) × Change in volume (ΔV)
Conversion of Volume:
The volume of water at 0°C is 1 cm^3, and the volume of ice at 0°C is 1.092 cm^3. Therefore, the change in volume (ΔV) can be calculated as:
ΔV = Volume of ice - Volume of water
ΔV = 1.092 cm^3 - 1 cm^3
ΔV = 0.092 cm^3
Since 1 cm^3 is equal to 1 × 10^(-6) m^3:
ΔV = 0.092 × 10^(-6) m^3
ΔV = 9.2 × 10^(-8) m^3
Calculation:
Using the given formula, we can now calculate the work done:
W = P × ΔV
W = (1 × 10^5 N/m^2) × (9.2 × 10^(-8) m^3)
W = 9.2 × 10^(-3) Nm
W = 9.2 mJ (millijoules)
Therefore, the work done in converting 1 g of water at 0°C and 1 × 10^5 N/m^2 pressure into ice with a volume of 1.092 cm^3 is 9.2 mJ.
Answer:
The work done is 0.0091 J (or 9.2 mJ).
Mass of water (m) = 1 g = 0.001 kg
Pressure (P) = 1 × 10^5 N/m^2
Volume of ice (V) = 1.092 cm^3 = 1.092 × 10^(-6) m^3
To find:
Work done (W) in converting water to ice
Formula:
Work done (W) = Pressure (P) × Change in volume (ΔV)
Conversion of Volume:
The volume of water at 0°C is 1 cm^3, and the volume of ice at 0°C is 1.092 cm^3. Therefore, the change in volume (ΔV) can be calculated as:
ΔV = Volume of ice - Volume of water
ΔV = 1.092 cm^3 - 1 cm^3
ΔV = 0.092 cm^3
Since 1 cm^3 is equal to 1 × 10^(-6) m^3:
ΔV = 0.092 × 10^(-6) m^3
ΔV = 9.2 × 10^(-8) m^3
Calculation:
Using the given formula, we can now calculate the work done:
W = P × ΔV
W = (1 × 10^5 N/m^2) × (9.2 × 10^(-8) m^3)
W = 9.2 × 10^(-3) Nm
W = 9.2 mJ (millijoules)
Therefore, the work done in converting 1 g of water at 0°C and 1 × 10^5 N/m^2 pressure into ice with a volume of 1.092 cm^3 is 9.2 mJ.
Answer:
The work done is 0.0091 J (or 9.2 mJ).
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When 1 g of water at 0 degree Celsius and 1×10*5 N/m2 pressure is converteded into Ice of volume 1.092cm3,the workdone Will be????? ans is 0.0091 how?
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When 1 g of water at 0 degree Celsius and 1×10*5 N/m2 pressure is converteded into Ice of volume 1.092cm3,the workdone Will be????? ans is 0.0091 how? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about When 1 g of water at 0 degree Celsius and 1×10*5 N/m2 pressure is converteded into Ice of volume 1.092cm3,the workdone Will be????? ans is 0.0091 how? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When 1 g of water at 0 degree Celsius and 1×10*5 N/m2 pressure is converteded into Ice of volume 1.092cm3,the workdone Will be????? ans is 0.0091 how?.
When 1 g of water at 0 degree Celsius and 1×10*5 N/m2 pressure is converteded into Ice of volume 1.092cm3,the workdone Will be????? ans is 0.0091 how? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about When 1 g of water at 0 degree Celsius and 1×10*5 N/m2 pressure is converteded into Ice of volume 1.092cm3,the workdone Will be????? ans is 0.0091 how? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When 1 g of water at 0 degree Celsius and 1×10*5 N/m2 pressure is converteded into Ice of volume 1.092cm3,the workdone Will be????? ans is 0.0091 how?.
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