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Equivalent conductance of NaCl, HCl and CH3COONa at infinite dilution are 126.45, 425.16 and 91ohm^-1 cm^-1 respectively. The equivalent conductance of CH3COOH at infinite dilution would be A) 101.38 ohm^-1 cm^2 B) 253.62 ohm^-1 cm^2 C) 389.71 ohm^-1 cm^2 D) 678.9 ohm^-1 cm^2?
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Equivalent conductance of NaCl, HCl and CH3COONa at infinite dilution ...
Equivalent Conductance of NaCl, HCl, and CH3COONa at Infinite Dilution
Given data:
- Equivalent conductance of NaCl at infinite dilution = 126.45 Ω^-1 cm^-1
- Equivalent conductance of HCl at infinite dilution = 425.16 Ω^-1 cm^-1
- Equivalent conductance of CH3COONa at infinite dilution = 91 Ω^-1 cm^-1
Calculation of Equivalent Conductance of CH3COOH at Infinite Dilution
To find the equivalent conductance of CH3COOH at infinite dilution, we can use the concept of ionic mobility and the Kohlrausch's law of independent migration of ions.
The equivalent conductance of an electrolyte is given by the sum of the conductances of its respective ions:
Λeq = λ+ + λ-
where Λeq is the equivalent conductance and λ+ and λ- are the conductances of the cation and anion, respectively.
We can consider CH3COOH as CH3COO- (acetate ion) and H+ (hydrogen ion). Since the conductance of CH3COONa is given, we can calculate the conductance of CH3COO- as follows:
Λeq(CH3COO-) = Λeq(CH3COONa) - Λeq(Na+)
Λeq(CH3COO-) = 91 Ω^-1 cm^-1 - 126.45 Ω^-1 cm^-1
Λeq(CH3COO-) = -35.45 Ω^-1 cm^-1
Now, we can calculate the conductance of H+ (λH+):
λH+ = Λeq(CH3COOH) - Λeq(CH3COO-)
λH+ = Λeq(CH3COOH) - (-35.45 Ω^-1 cm^-1)
λH+ = Λeq(CH3COOH) + 35.45 Ω^-1 cm^-1
Given that the equivalent conductance of HCl is 425.16 Ω^-1 cm^-1, we can write:
425.16 Ω^-1 cm^-1 = Λeq(CH3COOH) + 35.45 Ω^-1 cm^-1
Λeq(CH3COOH) = 425.16 Ω^-1 cm^-1 - 35.45 Ω^-1 cm^-1
Λeq(CH3COOH) = 389.71 Ω^-1 cm^-1
Therefore, the equivalent conductance of CH3COOH at infinite dilution is 389.71 Ω^-1 cm^-1.
Answer: C) 389.71 ohm^-1 cm^2
Given data:
- Equivalent conductance of NaCl at infinite dilution = 126.45 Ω^-1 cm^-1
- Equivalent conductance of HCl at infinite dilution = 425.16 Ω^-1 cm^-1
- Equivalent conductance of CH3COONa at infinite dilution = 91 Ω^-1 cm^-1
Calculation of Equivalent Conductance of CH3COOH at Infinite Dilution
To find the equivalent conductance of CH3COOH at infinite dilution, we can use the concept of ionic mobility and the Kohlrausch's law of independent migration of ions.
The equivalent conductance of an electrolyte is given by the sum of the conductances of its respective ions:
Λeq = λ+ + λ-
where Λeq is the equivalent conductance and λ+ and λ- are the conductances of the cation and anion, respectively.
We can consider CH3COOH as CH3COO- (acetate ion) and H+ (hydrogen ion). Since the conductance of CH3COONa is given, we can calculate the conductance of CH3COO- as follows:
Λeq(CH3COO-) = Λeq(CH3COONa) - Λeq(Na+)
Λeq(CH3COO-) = 91 Ω^-1 cm^-1 - 126.45 Ω^-1 cm^-1
Λeq(CH3COO-) = -35.45 Ω^-1 cm^-1
Now, we can calculate the conductance of H+ (λH+):
λH+ = Λeq(CH3COOH) - Λeq(CH3COO-)
λH+ = Λeq(CH3COOH) - (-35.45 Ω^-1 cm^-1)
λH+ = Λeq(CH3COOH) + 35.45 Ω^-1 cm^-1
Given that the equivalent conductance of HCl is 425.16 Ω^-1 cm^-1, we can write:
425.16 Ω^-1 cm^-1 = Λeq(CH3COOH) + 35.45 Ω^-1 cm^-1
Λeq(CH3COOH) = 425.16 Ω^-1 cm^-1 - 35.45 Ω^-1 cm^-1
Λeq(CH3COOH) = 389.71 Ω^-1 cm^-1
Therefore, the equivalent conductance of CH3COOH at infinite dilution is 389.71 Ω^-1 cm^-1.
Answer: C) 389.71 ohm^-1 cm^2
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Equivalent conductance of NaCl, HCl and CH3COONa at infinite dilution ...
Option C
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Equivalent conductance of NaCl, HCl and CH3COONa at infinite dilution are 126.45, 425.16 and 91ohm^-1 cm^-1 respectively. The equivalent conductance of CH3COOH at infinite dilution would be A) 101.38 ohm^-1 cm^2 B) 253.62 ohm^-1 cm^2 C) 389.71 ohm^-1 cm^2 D) 678.9 ohm^-1 cm^2?
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Equivalent conductance of NaCl, HCl and CH3COONa at infinite dilution are 126.45, 425.16 and 91ohm^-1 cm^-1 respectively. The equivalent conductance of CH3COOH at infinite dilution would be A) 101.38 ohm^-1 cm^2 B) 253.62 ohm^-1 cm^2 C) 389.71 ohm^-1 cm^2 D) 678.9 ohm^-1 cm^2? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Equivalent conductance of NaCl, HCl and CH3COONa at infinite dilution are 126.45, 425.16 and 91ohm^-1 cm^-1 respectively. The equivalent conductance of CH3COOH at infinite dilution would be A) 101.38 ohm^-1 cm^2 B) 253.62 ohm^-1 cm^2 C) 389.71 ohm^-1 cm^2 D) 678.9 ohm^-1 cm^2? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Equivalent conductance of NaCl, HCl and CH3COONa at infinite dilution are 126.45, 425.16 and 91ohm^-1 cm^-1 respectively. The equivalent conductance of CH3COOH at infinite dilution would be A) 101.38 ohm^-1 cm^2 B) 253.62 ohm^-1 cm^2 C) 389.71 ohm^-1 cm^2 D) 678.9 ohm^-1 cm^2?.
Equivalent conductance of NaCl, HCl and CH3COONa at infinite dilution are 126.45, 425.16 and 91ohm^-1 cm^-1 respectively. The equivalent conductance of CH3COOH at infinite dilution would be A) 101.38 ohm^-1 cm^2 B) 253.62 ohm^-1 cm^2 C) 389.71 ohm^-1 cm^2 D) 678.9 ohm^-1 cm^2? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Equivalent conductance of NaCl, HCl and CH3COONa at infinite dilution are 126.45, 425.16 and 91ohm^-1 cm^-1 respectively. The equivalent conductance of CH3COOH at infinite dilution would be A) 101.38 ohm^-1 cm^2 B) 253.62 ohm^-1 cm^2 C) 389.71 ohm^-1 cm^2 D) 678.9 ohm^-1 cm^2? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Equivalent conductance of NaCl, HCl and CH3COONa at infinite dilution are 126.45, 425.16 and 91ohm^-1 cm^-1 respectively. The equivalent conductance of CH3COOH at infinite dilution would be A) 101.38 ohm^-1 cm^2 B) 253.62 ohm^-1 cm^2 C) 389.71 ohm^-1 cm^2 D) 678.9 ohm^-1 cm^2?.
Solutions for Equivalent conductance of NaCl, HCl and CH3COONa at infinite dilution are 126.45, 425.16 and 91ohm^-1 cm^-1 respectively. The equivalent conductance of CH3COOH at infinite dilution would be A) 101.38 ohm^-1 cm^2 B) 253.62 ohm^-1 cm^2 C) 389.71 ohm^-1 cm^2 D) 678.9 ohm^-1 cm^2? in English & in Hindi are available as part of our courses for NEET.
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Equivalent conductance of NaCl, HCl and CH3COONa at infinite dilution are 126.45, 425.16 and 91ohm^-1 cm^-1 respectively. The equivalent conductance of CH3COOH at infinite dilution would be A) 101.38 ohm^-1 cm^2 B) 253.62 ohm^-1 cm^2 C) 389.71 ohm^-1 cm^2 D) 678.9 ohm^-1 cm^2?, a detailed solution for Equivalent conductance of NaCl, HCl and CH3COONa at infinite dilution are 126.45, 425.16 and 91ohm^-1 cm^-1 respectively. The equivalent conductance of CH3COOH at infinite dilution would be A) 101.38 ohm^-1 cm^2 B) 253.62 ohm^-1 cm^2 C) 389.71 ohm^-1 cm^2 D) 678.9 ohm^-1 cm^2? has been provided alongside types of Equivalent conductance of NaCl, HCl and CH3COONa at infinite dilution are 126.45, 425.16 and 91ohm^-1 cm^-1 respectively. The equivalent conductance of CH3COOH at infinite dilution would be A) 101.38 ohm^-1 cm^2 B) 253.62 ohm^-1 cm^2 C) 389.71 ohm^-1 cm^2 D) 678.9 ohm^-1 cm^2? theory, EduRev gives you an
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