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Equivalent conductance of an electrolyte containing NaF at infinite dilution is 90.1 ohm-1icm2. If NaF is replaced by KF what is the value of equivalent conductance?
- a)90.1 ohm-1 cm2
- b)111.2ohm- 1cm2
- c)0
- d)222.4 ohm-1 cm2
Correct answer is option 'A'. Can you explain this answer?
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Equivalent conductance of an electrolyte containing NaF at infinite di...
Given: Equivalent conductance of NaF at infinite dilution = 90.1 ohm-1 cm2
To find: Equivalent conductance of KF at infinite dilution
Solution:
- The equivalent conductance of an electrolyte at infinite dilution is the sum of the equivalent conductance of its cation and anion at infinite dilution.
- Therefore, the equivalent conductance of KF at infinite dilution can be calculated as follows:
- The cation in KF is K+ and its equivalent conductance at infinite dilution is known to be 73.5 ohm-1 cm2. (This value is commonly given in reference books or can be looked up online).
- The anion in KF is F- which has the same charge as the anion in NaF, therefore its equivalent conductance at infinite dilution should be the same as that of NaF, which is 90.1 ohm-1 cm2.
- Therefore, the equivalent conductance of KF at infinite dilution is the sum of the equivalent conductance of K+ and F- at infinite dilution. i.e.,
Equivalent conductance of KF at infinite dilution = 73.5 + 90.1 = 163.6 ohm-1 cm2
- However, the correct answer is given as option A which is equal to the equivalent conductance of NaF at infinite dilution. This could be due to an error in the question or answer choices, or it could be that the question is specifically asking for the equivalent conductance of KF in relation to NaF, in which case the correct answer would indeed be option A.
Therefore, the equivalent conductance of KF at infinite dilution is 163.6 ohm-1 cm2, but the correct answer given in the options is A which is 90.1 ohm-1 cm2, the equivalent conductance of NaF at infinite dilution.
To find: Equivalent conductance of KF at infinite dilution
Solution:
- The equivalent conductance of an electrolyte at infinite dilution is the sum of the equivalent conductance of its cation and anion at infinite dilution.
- Therefore, the equivalent conductance of KF at infinite dilution can be calculated as follows:
- The cation in KF is K+ and its equivalent conductance at infinite dilution is known to be 73.5 ohm-1 cm2. (This value is commonly given in reference books or can be looked up online).
- The anion in KF is F- which has the same charge as the anion in NaF, therefore its equivalent conductance at infinite dilution should be the same as that of NaF, which is 90.1 ohm-1 cm2.
- Therefore, the equivalent conductance of KF at infinite dilution is the sum of the equivalent conductance of K+ and F- at infinite dilution. i.e.,
Equivalent conductance of KF at infinite dilution = 73.5 + 90.1 = 163.6 ohm-1 cm2
- However, the correct answer is given as option A which is equal to the equivalent conductance of NaF at infinite dilution. This could be due to an error in the question or answer choices, or it could be that the question is specifically asking for the equivalent conductance of KF in relation to NaF, in which case the correct answer would indeed be option A.
Therefore, the equivalent conductance of KF at infinite dilution is 163.6 ohm-1 cm2, but the correct answer given in the options is A which is 90.1 ohm-1 cm2, the equivalent conductance of NaF at infinite dilution.
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Equivalent conductance of an electrolyte containing NaF at infinite dilution is 90.1 ohm-1icm2. If NaF is replaced by KF what is the value of equivalent conductance?a)90.1 ohm-1cm2b)111.2ohm- 1cm2c)0d)222.4 ohm-1 cm2Correct answer is option 'A'. Can you explain this answer?
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Equivalent conductance of an electrolyte containing NaF at infinite dilution is 90.1 ohm-1icm2. If NaF is replaced by KF what is the value of equivalent conductance?a)90.1 ohm-1cm2b)111.2ohm- 1cm2c)0d)222.4 ohm-1 cm2Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Equivalent conductance of an electrolyte containing NaF at infinite dilution is 90.1 ohm-1icm2. If NaF is replaced by KF what is the value of equivalent conductance?a)90.1 ohm-1cm2b)111.2ohm- 1cm2c)0d)222.4 ohm-1 cm2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Equivalent conductance of an electrolyte containing NaF at infinite dilution is 90.1 ohm-1icm2. If NaF is replaced by KF what is the value of equivalent conductance?a)90.1 ohm-1cm2b)111.2ohm- 1cm2c)0d)222.4 ohm-1 cm2Correct answer is option 'A'. Can you explain this answer?.
Equivalent conductance of an electrolyte containing NaF at infinite dilution is 90.1 ohm-1icm2. If NaF is replaced by KF what is the value of equivalent conductance?a)90.1 ohm-1cm2b)111.2ohm- 1cm2c)0d)222.4 ohm-1 cm2Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Equivalent conductance of an electrolyte containing NaF at infinite dilution is 90.1 ohm-1icm2. If NaF is replaced by KF what is the value of equivalent conductance?a)90.1 ohm-1cm2b)111.2ohm- 1cm2c)0d)222.4 ohm-1 cm2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Equivalent conductance of an electrolyte containing NaF at infinite dilution is 90.1 ohm-1icm2. If NaF is replaced by KF what is the value of equivalent conductance?a)90.1 ohm-1cm2b)111.2ohm- 1cm2c)0d)222.4 ohm-1 cm2Correct answer is option 'A'. Can you explain this answer?.
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Equivalent conductance of an electrolyte containing NaF at infinite dilution is 90.1 ohm-1icm2. If NaF is replaced by KF what is the value of equivalent conductance?a)90.1 ohm-1cm2b)111.2ohm- 1cm2c)0d)222.4 ohm-1 cm2Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Equivalent conductance of an electrolyte containing NaF at infinite dilution is 90.1 ohm-1icm2. If NaF is replaced by KF what is the value of equivalent conductance?a)90.1 ohm-1cm2b)111.2ohm- 1cm2c)0d)222.4 ohm-1 cm2Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Equivalent conductance of an electrolyte containing NaF at infinite dilution is 90.1 ohm-1icm2. If NaF is replaced by KF what is the value of equivalent conductance?a)90.1 ohm-1cm2b)111.2ohm- 1cm2c)0d)222.4 ohm-1 cm2Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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