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During the transmission of nerve impulse through a nerve fibre, the potential on the inner side of the plasma membrane has which type of electric change?
- a)First negative, then positive and again back to negative.
- b)First positive, then negative and continue to be negative
- c)First negative, then positive and continue to be positive
- d)First positive, then negative and again back to positive
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
During the transmission of nerve impulse through a nerve fibre, the po...
Plasma membrane of a non-conducting neuron is positive on the outside and negative inside. The difference in charge is about 70 to 90 mV which is called as resting potential and the membrane is said to be polarized. A typical value of resting potential is -70mV.
When a plasma membrane of neuron is stimulated, its permeability changes and sodium potassium pump stop operating which results in the positive charge inside and negative charge outside.The nerve fibre is said to be in action potential or depolarized. The action potential inside the membrane is about +30 mV.
After a period of action potential, sodium pump operates again and membrane will get resting potential of -70mV by repolarization.
Thus, Option (4) first negative, then positive and again back to negative , is correct ....
When a plasma membrane of neuron is stimulated, its permeability changes and sodium potassium pump stop operating which results in the positive charge inside and negative charge outside.The nerve fibre is said to be in action potential or depolarized. The action potential inside the membrane is about +30 mV.
After a period of action potential, sodium pump operates again and membrane will get resting potential of -70mV by repolarization.
Thus, Option (4) first negative, then positive and again back to negative , is correct ....
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During the transmission of nerve impulse through a nerve fibre, the po...
Transmission of Nerve Impulse through a Nerve Fiber:
During the transmission of a nerve impulse through a nerve fiber, there is a sequential change in the potential on the inner side of the plasma membrane. Let's understand the process step by step:
Resting Membrane Potential:
- The resting membrane potential of a neuron is approximately -70mV, which means the inside of the neuron is negatively charged compared to the outside.
- This is maintained by the Na+/K+ pump, which actively transports three sodium ions (Na+) out of the cell for every two potassium ions (K+) it brings in, thus establishing an electrochemical gradient.
Depolarization:
- When a stimulus is received by a neuron, it causes a temporary increase in the permeability of the cell membrane to sodium ions (Na+).
- Sodium channels in the membrane open, and sodium ions rush into the cell due to the concentration and electrical gradients.
- This influx of positive sodium ions causes the inside of the neuron to become more positive, resulting in depolarization.
- The potential on the inner side of the plasma membrane becomes less negative or positive.
Repolarization:
- After depolarization, the sodium channels close, and potassium channels open, allowing potassium ions (K+) to move out of the cell.
- This movement of positive potassium ions out of the cell restores the negative charge inside the neuron.
- The potential on the inner side of the plasma membrane becomes more negative again.
Hyperpolarization:
- Sometimes, after repolarization, the potassium channels remain open for a brief period, causing an excessive outflow of potassium ions.
- This leads to a more negative potential on the inner side of the plasma membrane than the resting membrane potential, resulting in hyperpolarization.
Resting Membrane Potential Restoration:
- The sodium-potassium pump restores the ionic concentrations to their resting state, bringing the membrane potential back to -70mV.
Answer Explanation:
- From the above description, we can see that the potential on the inner side of the plasma membrane initially becomes less negative or positive during depolarization.
- Then, during repolarization, it becomes more negative again.
- Finally, in some cases, there is a temporary hyperpolarization before the resting membrane potential is restored.
- Therefore, the correct answer is option 'A': First negative, then positive, and again back to negative.
During the transmission of a nerve impulse through a nerve fiber, there is a sequential change in the potential on the inner side of the plasma membrane. Let's understand the process step by step:
Resting Membrane Potential:
- The resting membrane potential of a neuron is approximately -70mV, which means the inside of the neuron is negatively charged compared to the outside.
- This is maintained by the Na+/K+ pump, which actively transports three sodium ions (Na+) out of the cell for every two potassium ions (K+) it brings in, thus establishing an electrochemical gradient.
Depolarization:
- When a stimulus is received by a neuron, it causes a temporary increase in the permeability of the cell membrane to sodium ions (Na+).
- Sodium channels in the membrane open, and sodium ions rush into the cell due to the concentration and electrical gradients.
- This influx of positive sodium ions causes the inside of the neuron to become more positive, resulting in depolarization.
- The potential on the inner side of the plasma membrane becomes less negative or positive.
Repolarization:
- After depolarization, the sodium channels close, and potassium channels open, allowing potassium ions (K+) to move out of the cell.
- This movement of positive potassium ions out of the cell restores the negative charge inside the neuron.
- The potential on the inner side of the plasma membrane becomes more negative again.
Hyperpolarization:
- Sometimes, after repolarization, the potassium channels remain open for a brief period, causing an excessive outflow of potassium ions.
- This leads to a more negative potential on the inner side of the plasma membrane than the resting membrane potential, resulting in hyperpolarization.
Resting Membrane Potential Restoration:
- The sodium-potassium pump restores the ionic concentrations to their resting state, bringing the membrane potential back to -70mV.
Answer Explanation:
- From the above description, we can see that the potential on the inner side of the plasma membrane initially becomes less negative or positive during depolarization.
- Then, during repolarization, it becomes more negative again.
- Finally, in some cases, there is a temporary hyperpolarization before the resting membrane potential is restored.
- Therefore, the correct answer is option 'A': First negative, then positive, and again back to negative.
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During the transmission of nerve impulse through a nerve fibre, the potential on the inner side of the plasma membrane has which type of electric change?a)First negative, then positive andagain back to negative.b)First positive, then negative and continue to be negativec)First negative, then positive and continue to be positived)First positive, then negative and again back to positiveCorrect answer is option 'A'. Can you explain this answer?
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