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Pulling force making an angle θ to the horizontal is applied on a block of weight W placed on a horizontal table. If the angle of friction is α. then the magnitude of force required to move the body is equal toa)W sin α/g tan (θ-α)b)W cos α/cos(θ-α)c)W sin α/cos(θ-α)d)W tan α/sin(θ-α)Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Pulling force making an angle θ to the horizontal is applied on a block of weight W placed on a horizontal table. If the angle of friction is α. then the magnitude of force required to move the body is equal toa)W sin α/g tan (θ-α)b)W cos α/cos(θ-α)c)W sin α/cos(θ-α)d)W tan α/sin(θ-α)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Pulling force making an angle θ to the horizontal is applied on a block of weight W placed on a horizontal table. If the angle of friction is α. then the magnitude of force required to move the body is equal toa)W sin α/g tan (θ-α)b)W cos α/cos(θ-α)c)W sin α/cos(θ-α)d)W tan α/sin(θ-α)Correct answer is option 'C'. Can you explain this answer?.

Solutions for Pulling force making an angle θ to the horizontal is applied on a block of weight W placed on a horizontal table. If the angle of friction is α. then the magnitude of force required to move the body is equal toa)W sin α/g tan (θ-α)b)W cos α/cos(θ-α)c)W sin α/cos(θ-α)d)W tan α/sin(θ-α)Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

Here you can find the meaning of Pulling force making an angle θ to the horizontal is applied on a block of weight W placed on a horizontal table. If the angle of friction is α. then the magnitude of force required to move the body is equal toa)W sin α/g tan (θ-α)b)W cos α/cos(θ-α)c)W sin α/cos(θ-α)d)W tan α/sin(θ-α)Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Pulling force making an angle θ to the horizontal is applied on a block of weight W placed on a horizontal table. If the angle of friction is α. then the magnitude of force required to move the body is equal toa)W sin α/g tan (θ-α)b)W cos α/cos(θ-α)c)W sin α/cos(θ-α)d)W tan α/sin(θ-α)Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Pulling force making an angle θ to the horizontal is applied on a block of weight W placed on a horizontal table. If the angle of friction is α. then the magnitude of force required to move the body is equal toa)W sin α/g tan (θ-α)b)W cos α/cos(θ-α)c)W sin α/cos(θ-α)d)W tan α/sin(θ-α)Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Pulling force making an angle θ to the horizontal is applied on a block of weight W placed on a horizontal table. If the angle of friction is α. then the magnitude of force required to move the body is equal toa)W sin α/g tan (θ-α)b)W cos α/cos(θ-α)c)W sin α/cos(θ-α)d)W tan α/sin(θ-α)Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Pulling force making an angle θ to the horizontal is applied on a block of weight W placed on a horizontal table. If the angle of friction is α. then the magnitude of force required to move the body is equal toa)W sin α/g tan (θ-α)b)W cos α/cos(θ-α)c)W sin α/cos(θ-α)d)W tan α/sin(θ-α)Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice NEET tests.