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Two charges 3.2×10^-19 C and -3.2×10^-9 C kept 2.4A apart forms a dipole.if ot is lept in uniform electric feild of intensity 4×10^5 volt/m then what will be its electrical energy in equilibrium ?
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Two charges 3.2×10^-19 C and -3.2×10^-9 C kept 2.4A apart forms a dip...
Calculating Electric Dipole Moment:
The electric dipole moment (p) can be calculated using the formula p = qd, where q is the charge and d is the distance between the charges. Given that the charges are 2.4A apart, we can calculate the electric dipole moment of the system as follows:
p = (3.2×10^-19 C)(2.4A) = 7.68×10^-19 C·m
Electric Potential Energy:
The electric potential energy (U) of a dipole in an electric field can be calculated using the formula U = -pEcosθ, where E is the electric field strength, θ is the angle between the dipole moment and the electric field, and the negative sign indicates that the dipole experiences a torque in the field.
Calculating the Angle:
Since the dipole is placed in a uniform electric field, the dipole moment will align with the field direction, so the angle θ between them is 0. Therefore, cosθ = 1 and the potential energy of the dipole can be calculated as:
U = -(7.68×10^-19 C·m)(4×10^5 V/m) = -3.072×10^-13 J
Explanation:
When the dipole is placed in a uniform electric field, it will experience a torque and align with the field direction. This alignment results in a potential energy that is negative and proportional to the dipole moment and the electric field strength. The negative sign indicates that the dipole is in a stable equilibrium position in the field.
Community Answer
Two charges 3.2×10^-19 C and -3.2×10^-9 C kept 2.4A apart forms a dip...
Given here
q = 3.2×10^-19
distance between dipole, d= 2.4×10^-10m
and E= 4×10^5
now p = qd
and
we know U=pE
all value are given here multiply them then u will got it ans.
q = 3.2×10^-19
distance between dipole, d= 2.4×10^-10m
and E= 4×10^5
now p = qd
and
we know U=pE
all value are given here multiply them then u will got it ans.
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Two charges 3.2×10^-19 C and -3.2×10^-9 C kept 2.4A apart forms a dipole.if ot is lept in uniform electric feild of intensity 4×10^5 volt/m then what will be its electrical energy in equilibrium ?
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Two charges 3.2×10^-19 C and -3.2×10^-9 C kept 2.4A apart forms a dipole.if ot is lept in uniform electric feild of intensity 4×10^5 volt/m then what will be its electrical energy in equilibrium ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two charges 3.2×10^-19 C and -3.2×10^-9 C kept 2.4A apart forms a dipole.if ot is lept in uniform electric feild of intensity 4×10^5 volt/m then what will be its electrical energy in equilibrium ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two charges 3.2×10^-19 C and -3.2×10^-9 C kept 2.4A apart forms a dipole.if ot is lept in uniform electric feild of intensity 4×10^5 volt/m then what will be its electrical energy in equilibrium ?.
Two charges 3.2×10^-19 C and -3.2×10^-9 C kept 2.4A apart forms a dipole.if ot is lept in uniform electric feild of intensity 4×10^5 volt/m then what will be its electrical energy in equilibrium ? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two charges 3.2×10^-19 C and -3.2×10^-9 C kept 2.4A apart forms a dipole.if ot is lept in uniform electric feild of intensity 4×10^5 volt/m then what will be its electrical energy in equilibrium ? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two charges 3.2×10^-19 C and -3.2×10^-9 C kept 2.4A apart forms a dipole.if ot is lept in uniform electric feild of intensity 4×10^5 volt/m then what will be its electrical energy in equilibrium ?.
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