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A mole of N2H4 loses ten moles of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y? (there is no change in the oxidation number of hydrogen)
  • a)
    -1
  • b)
    -3
  • c)
    +3
  • d)
    +5
Correct answer is option 'C'. Can you explain this answer?
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A mole of N2H4 loses ten moles of electrons to form a new compound Y. ...
Oxidation State of Nitrogen in Compound Y

Given: A mole of N2H4 loses ten moles of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y? (there is no change in the oxidation number of hydrogen)

Solution:

The oxidation state of N in N2H4 is -2 (Hydrazine is a neutral compound, so the sum of oxidation states is zero. H has an oxidation state of +1, so N has an oxidation state of -2).

When N2H4 loses ten moles of electrons, it becomes a cation with a charge of +10.

Let the oxidation state of N in the new compound Y be x.

As the compound Y is formed by the loss of electrons from N2H4, the sum of the oxidation states of all the elements in Y will be equal to the charge on the cation formed from N2H4.

Therefore, the sum of the oxidation states of all the elements in Y = +10

The sum of the oxidation states of all the hydrogen atoms in Y is zero (as there is no change in the oxidation number of hydrogen).

Therefore, the sum of the oxidation states of all the N atoms in Y = +10

As the compound Y has all the nitrogen from N2H4, the number of N atoms in Y = 2

Therefore, 2x = +10

x = +5

Hence, the oxidation state of nitrogen in the compound Y is +5.

Answer: Option (c) 3
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A mole of N2H4 loses ten moles of electrons to form a new compound Y. ...
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A mole of N2H4 loses ten moles of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y? (there is no change in the oxidation number of hydrogen)a)-1b)-3c)+3d)+5Correct answer is option 'C'. Can you explain this answer?
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