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A nuclear reactor has a power of 16 Kw. If the energy per fission is 200 MeV, the number of fissions per second is
- a)5 x 1016
- b)5 x 1017
- c)5 x 1014
- d)5 x 1015
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
A nuclear reactor has a power of 16 Kw. If the energy per fission is 2...
If 1 fission gives 200 MeV energy then x no. of fissions gives 16×10^3J of energy in 1sec.
so x= 16×10^3/200×10^6×1.6×10^-19 = 5×10^14.
so x= 16×10^3/200×10^6×1.6×10^-19 = 5×10^14.
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Community Answer
A nuclear reactor has a power of 16 Kw. If the energy per fission is 2...
Number of fissions per second = Power of reactor / Energy per fission
Given:
Power of reactor = 16 kW = 16 x 10^3 W
Energy per fission = 200 MeV
Converting the energy from MeV to Joules:
1 MeV = 1.6 x 10^-13 J
200 MeV = 200 x 1.6 x 10^-13 J = 3.2 x 10^-11 J
Number of fissions per second = (16 x 10^3 W) / (3.2 x 10^-11 J)
Let's simplify the above expression:
Number of fissions per second = (16 x 10^3 W) x (1 / (3.2 x 10^-11 J))
We can rewrite this expression as:
Number of fissions per second = (16 x 10^3 W) x (1 / (3.2 x 10^-11 J)) x (10^11 / 10^11)
Simplifying further:
Number of fissions per second = (16 x 10^3 W) x (10^11 / (3.2 J))
Number of fissions per second = (16 x 10^3 W) x (10^11 J^-1 / (3.2 J))
Number of fissions per second = (16 x 10^3 W) x (3.125 x 10^10 J^-1)
Number of fissions per second = 50 x 10^5 W x 3.125 x 10^10 J^-1
Number of fissions per second = 156.25 x 10^15 J / s
Rounding off to the nearest value, we get:
Number of fissions per second ≈ 5 x 10^14
Therefore, the correct answer is option C) 5 x 10^14.
Given:
Power of reactor = 16 kW = 16 x 10^3 W
Energy per fission = 200 MeV
Converting the energy from MeV to Joules:
1 MeV = 1.6 x 10^-13 J
200 MeV = 200 x 1.6 x 10^-13 J = 3.2 x 10^-11 J
Number of fissions per second = (16 x 10^3 W) / (3.2 x 10^-11 J)
Let's simplify the above expression:
Number of fissions per second = (16 x 10^3 W) x (1 / (3.2 x 10^-11 J))
We can rewrite this expression as:
Number of fissions per second = (16 x 10^3 W) x (1 / (3.2 x 10^-11 J)) x (10^11 / 10^11)
Simplifying further:
Number of fissions per second = (16 x 10^3 W) x (10^11 / (3.2 J))
Number of fissions per second = (16 x 10^3 W) x (10^11 J^-1 / (3.2 J))
Number of fissions per second = (16 x 10^3 W) x (3.125 x 10^10 J^-1)
Number of fissions per second = 50 x 10^5 W x 3.125 x 10^10 J^-1
Number of fissions per second = 156.25 x 10^15 J / s
Rounding off to the nearest value, we get:
Number of fissions per second ≈ 5 x 10^14
Therefore, the correct answer is option C) 5 x 10^14.
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A nuclear reactor has a power of 16 Kw. If the energy per fission is 200 MeV, the number of fissions per second isa)5 x 1016b)5 x 1017c)5 x 1014d)5 x 1015Correct answer is option 'C'. Can you explain this answer?
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