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A block of mass m is equal to 5 kg is kept on a horizontal rough platform undergoing rotation if coefficient of friction between the block and the platform is 0.4 and block is rotating in a circle of radius 4 metre then it's possible time period maybe ?
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A block of mass m is equal to 5 kg is kept on a horizontal rough platf...
Calculation of Time Period of Block on Rotating Platform



  • Given: mass of block, m = 5 kg

  • Coefficient of friction, μ = 0.4

  • Radius of rotation, r = 4 m



Calculating Centripetal Force and Frictional Force



  • Centripetal force (Fc) = m * v2 / r, where v is the velocity of the block

  • Frictional force (Ff) = μ * m * g, where g is the acceleration due to gravity



Calculating Maximum Velocity and Time Period



  • The maximum velocity is achieved when the centripetal force is equal to the frictional force

  • Equating Fc and Ff, we get: v = √(μ * g * r)

  • Time period (T) = 2πr / v



Substituting Values to Calculate Time Period



  • Substituting the given values, we get: v = √(0.4 * 9.8 * 4) = 3.136 m/s

  • Time period (T) = 2π * 4 / 3.136 = 7.97 seconds (approx)



Conclusion



  • The possible time period for the block on the rotating platform is approximately 7.97 seconds.

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A block of mass m is equal to 5 kg is kept on a horizontal rough platf...
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A block of mass m is equal to 5 kg is kept on a horizontal rough platform undergoing rotation if coefficient of friction between the block and the platform is 0.4 and block is rotating in a circle of radius 4 metre then it's possible time period maybe ?
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