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A man walks 2 km towards North. Then he turns to East and walks 10 km. After this he turns to North and walks 3 km. Again he turns towards East and walks 2 km. How far is he from the starting point?
  • a)
    10 km
  • b)
    13 km
  • c)
    15 km
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?
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A man walks 2 km towards North. Then he turns to East and walks 10 km....
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Most Upvoted Answer
A man walks 2 km towards North. Then he turns to East and walks 10 km....
Given information:
- A man walks 2 km towards North.
- He then turns to East and walks 10 km.
- After this, he turns to North and walks 3 km.
- He turns towards East again and walks 2 km.

To find:
- How far is he from the starting point?

Solution:
Let's draw a diagram to visualize the man's movements:

N
|
|
|
W------O------E
|
|
|
S

- O represents the starting point.
- The man walks 2 km towards North, reaching point A.
- From A, he walks 10 km towards East, reaching point B.
- From B, he walks 3 km towards North, reaching point C.
- From C, he walks 2 km towards East, reaching point D.

To find the distance between O and D (the final point), we can use the Pythagorean theorem:

OD² = (OB + BD)² + OC²
OD² = (10 + 2)² + 3²
OD² = 12² + 3²
OD² = 144 + 9
OD² = 153
OD ≈ 12.37 km (rounded to two decimal places)

Therefore, the man is approximately 12.37 km away from the starting point. The correct answer is option B (13 km).
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Community Answer
A man walks 2 km towards North. Then he turns to East and walks 10 km....
Total distance in east = 10+2 = 12km
total distance in north = 2+3 = 5km
acc. to pythogorus theorem , shortest dist. =>
sqrt(12*12 + 5*5) => sqrt(169) = 13
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A man walks 2 km towards North. Then he turns to East and walks 10 km. After this he turns to North and walks 3 km. Again he turns towards East and walks 2 km. How far is he from the starting point?a)10 kmb)13 kmc)15 kmd)None of theseCorrect answer is option 'B'. Can you explain this answer?
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