A man walks 2 km towards North. Then he turns to East and walks 10 km....
Given information:
- A man walks 2 km towards North.
- He then turns to East and walks 10 km.
- After this, he turns to North and walks 3 km.
- He turns towards East again and walks 2 km.
To find:
- How far is he from the starting point?
Solution:
Let's draw a diagram to visualize the man's movements:
N
|
|
|
W------O------E
|
|
|
S
- O represents the starting point.
- The man walks 2 km towards North, reaching point A.
- From A, he walks 10 km towards East, reaching point B.
- From B, he walks 3 km towards North, reaching point C.
- From C, he walks 2 km towards East, reaching point D.
To find the distance between O and D (the final point), we can use the Pythagorean theorem:
OD² = (OB + BD)² + OC²
OD² = (10 + 2)² + 3²
OD² = 12² + 3²
OD² = 144 + 9
OD² = 153
OD ≈ 12.37 km (rounded to two decimal places)
Therefore, the man is approximately 12.37 km away from the starting point. The correct answer is option B (13 km).
A man walks 2 km towards North. Then he turns to East and walks 10 km....
Total distance in east = 10+2 = 12km
total distance in north = 2+3 = 5km
acc. to pythogorus theorem , shortest dist. =>
sqrt(12*12 + 5*5) => sqrt(169) = 13