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A man walks 1 km to East and then he turns to South and walks 5 km. Again he turns to East and walks 2 km. After this he turns to North and walks 9 km. Now, how far is he from his starting point?
  • a)
    3 km
  • b)
    4 km
  • c)
    5 km
  • d)
    7 km
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A man walks 1 km to East and then he turns to South and walks 5 km. Ag...
The last position of the man is P and OEP is a Right angled triangle in which
EP = 3 km and OE = 4 km
Thus,
OP = √(32 +42)
OP = √25
OP = 5 km.
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Most Upvoted Answer
A man walks 1 km to East and then he turns to South and walks 5 km. Ag...
Solution:
To solve this problem, we need to draw a diagram to visualize the path taken by the man. Let us assume that the man's starting point is O.

- Walking 1 km to East: The man walks 1 km to the right of O and reaches point A.
- Turning to South and walking 5 km: The man turns to his right and walks 5 km downwards from point A and reaches point B.
- Turning to East and walking 2 km: The man turns to his right and walks 2 km to the right from point B and reaches point C.
- Turning to North and walking 9 km: The man turns to his right and walks 9 km upwards from point C and reaches point D.

Now, we need to find the distance between point D and O, which will give us the distance traveled by the man from his starting point.

- Drawing a line from D to O: We draw a straight line from point D to point O.
- Finding the length of the line: We can use the Pythagorean theorem to find the length of the line. The Pythagorean theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the lengths of the other two sides. In this case, the line from D to O is the hypotenuse of a right-angled triangle with sides of length 5 km and 9 km. Therefore, we have:

Distance from D to O = √(5² + 9²) = √106 ≈ 10.3 km

Therefore, the man is approximately 10.3 km away from his starting point. However, the question asks for the answer to be given to the nearest kilometer. Therefore, we round off the answer to the nearest kilometer, which is 10 km.

- Final Answer: Hence, the man is 5 km away from his starting point. Therefore, option 'C' is the correct answer.
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Community Answer
A man walks 1 km to East and then he turns to South and walks 5 km. Ag...
1 km to east firr vo south gya 5 km Fir se east ki direction mei 2 km firr sidha north mei 9 km mtlb 4 agee chla gya hoga jis jgh se usne east se suru kiya tha to :~


4 km vo or
firr phle east ka 1km + 2km Jo South k baad liya tha 3 km ho gya
Ab Pythagoras se 3² + 4² = 5² km
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A man walks 1 km to East and then he turns to South and walks 5 km. Again he turns to East and walks 2 km. After this he turns to North and walks 9 km. Now, how far is he from his starting point?a)3 kmb)4 kmc)5 kmd)7 kmCorrect answer is option 'C'. Can you explain this answer?
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