CH3 CH3
/ /
CH3-- C----CH--CH2---C---CH3
\ \
CH3 CH3
&&&

CH3 CH3
\ \
CH3-- C----CH--CH2---C---CH2---cl
/ /
CH3 CH3

Structure of the Organic Halide C5H11Cl

Introduction:
The given organic halide, C5H11Cl, reacts with sodium (Na) and dry ether to yield a product, X, which upon monochlorination produces only 2 structural chlorides. We will analyze the structure of the organic halide and explain the reaction steps in detail.

Structure Analysis:
To determine the structure of the organic halide, we will consider the given molecular formula, C5H11Cl. From the formula, we can deduce that the compound contains 5 carbon atoms, 11 hydrogen atoms, and 1 chlorine atom.

Step 1: Reaction with Sodium and Dry Ether
When the organic halide is reacted with sodium (Na) and dry ether, it undergoes a nucleophilic substitution reaction. Sodium acts as a strong nucleophile, replacing the chlorine atom in the organic halide.

Step 2: Formation of Product X
The reaction with sodium and dry ether leads to the formation of product X. The structure of product X can be determined by considering the substitution of the chlorine atom with sodium. Since the organic halide reacts with sodium to form a product with only 2 structural chlorides upon monochlorination, it implies that the chlorine atom in the organic halide is attached to a tertiary carbon atom.

Step 3: Monochlorination of Product X
When product X is subjected to monochlorination, it undergoes a substitution reaction with a chlorine molecule (Cl2). The reaction results in the substitution of one of the hydrogen atoms in product X with a chlorine atom. Since only 2 structural chlorides are formed, it suggests that the monochlorination occurs at two different positions.

Conclusion:
Based on the given information, the organic halide C5H11Cl contains a chlorine atom attached to a tertiary carbon atom. The reaction with sodium and dry ether leads to the formation of a product, X, which upon monochlorination gives only 2 structural chlorides. The specific structure of the organic halide and product X can be further determined by experimental techniques such as spectroscopy.