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If 0.24g of a volatile liquid upon vapourization gives 45ml of vapours at NTP. What will be the vapour density of the substance? (Density of H = 0.089 gL⁻1)
- a)95.39
- b)5.993
- c)95.93
- d)56.0
Correct answer is option 'D'. Can you explain this answer?
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If 0.24g of a volatile liquid upon vapourization gives 45ml of vapours...
Given:
- Mass of volatile liquid = 0.24 g
- Volume of vapours = 45 mL
- Density of hydrogen = 0.089 g/L
To Find:
Vapour density of the substance
Solution:
1. Convert volume of vapours to volume at STP
- NTP = 1 atm and 298 K
- STP = 1 atm and 273 K
- Using the Combined Gas Law,
(P1 x V1)/T1 = (P2 x V2)/T2
- P1 = P2 = 1 atm
- T1 = 298 K
- T2 = 273 K
- V1 = 45 mL
- V2 = ?
(V1/T1) = (V2/T2)
V2 = (V1 x T2)/T1
V2 = (45 mL x 273 K)/298 K
V2 = 41.15 mL
2. Convert mass to moles
- Molar mass of substance = ?
- Let's assume the substance is a hydrocarbon
- So, molar mass = (12 x a) + (1 x b)
- where a and b are the number of carbon and hydrogen atoms respectively
- Let's assume the substance has 1 carbon and 4 hydrogen atoms
- Molar mass = (12 x 1) + (1 x 4) = 16 g/mol
- Moles of substance = mass/molar mass
- Moles of substance = 0.24 g/16 g/mol
- Moles of substance = 0.015 mol
3. Calculate Vapour density
- Vapour density = (Molar mass of substance/2) x (Volume of vapours/Volume at STP)
- Vapour density = (16 g/mol/2) x (45 mL/41.15 mL) x (1 L/1000 mL) x (1/0.089 g)
- Vapour density = 56.0
Therefore, the Vapour density of the substance is 56.0.
- Mass of volatile liquid = 0.24 g
- Volume of vapours = 45 mL
- Density of hydrogen = 0.089 g/L
To Find:
Vapour density of the substance
Solution:
1. Convert volume of vapours to volume at STP
- NTP = 1 atm and 298 K
- STP = 1 atm and 273 K
- Using the Combined Gas Law,
(P1 x V1)/T1 = (P2 x V2)/T2
- P1 = P2 = 1 atm
- T1 = 298 K
- T2 = 273 K
- V1 = 45 mL
- V2 = ?
(V1/T1) = (V2/T2)
V2 = (V1 x T2)/T1
V2 = (45 mL x 273 K)/298 K
V2 = 41.15 mL
2. Convert mass to moles
- Molar mass of substance = ?
- Let's assume the substance is a hydrocarbon
- So, molar mass = (12 x a) + (1 x b)
- where a and b are the number of carbon and hydrogen atoms respectively
- Let's assume the substance has 1 carbon and 4 hydrogen atoms
- Molar mass = (12 x 1) + (1 x 4) = 16 g/mol
- Moles of substance = mass/molar mass
- Moles of substance = 0.24 g/16 g/mol
- Moles of substance = 0.015 mol
3. Calculate Vapour density
- Vapour density = (Molar mass of substance/2) x (Volume of vapours/Volume at STP)
- Vapour density = (16 g/mol/2) x (45 mL/41.15 mL) x (1 L/1000 mL) x (1/0.089 g)
- Vapour density = 56.0
Therefore, the Vapour density of the substance is 56.0.
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If 0.24g of a volatile liquid upon vapourization gives 45ml of vapours...
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If 0.24g of a volatile liquid upon vapourization gives 45ml of vapours at NTP. What will be the vapour density of the substance? (Density of H = 0.089 gL⁻1)a)95.39b)5.993c)95.93d)56.0Correct answer is option 'D'. Can you explain this answer?
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If 0.24g of a volatile liquid upon vapourization gives 45ml of vapours at NTP. What will be the vapour density of the substance? (Density of H = 0.089 gL⁻1)a)95.39b)5.993c)95.93d)56.0Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If 0.24g of a volatile liquid upon vapourization gives 45ml of vapours at NTP. What will be the vapour density of the substance? (Density of H = 0.089 gL⁻1)a)95.39b)5.993c)95.93d)56.0Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 0.24g of a volatile liquid upon vapourization gives 45ml of vapours at NTP. What will be the vapour density of the substance? (Density of H = 0.089 gL⁻1)a)95.39b)5.993c)95.93d)56.0Correct answer is option 'D'. Can you explain this answer?.
If 0.24g of a volatile liquid upon vapourization gives 45ml of vapours at NTP. What will be the vapour density of the substance? (Density of H = 0.089 gL⁻1)a)95.39b)5.993c)95.93d)56.0Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If 0.24g of a volatile liquid upon vapourization gives 45ml of vapours at NTP. What will be the vapour density of the substance? (Density of H = 0.089 gL⁻1)a)95.39b)5.993c)95.93d)56.0Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 0.24g of a volatile liquid upon vapourization gives 45ml of vapours at NTP. What will be the vapour density of the substance? (Density of H = 0.089 gL⁻1)a)95.39b)5.993c)95.93d)56.0Correct answer is option 'D'. Can you explain this answer?.
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