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By walking 3/2 of his usual speed a person reach his office 10 minutes earlier. Find his usual times.
- a)5 min
- b)10 min
- c)20 min
- d)None
- e)All of the above
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
By walking 3/2 of his usual speed a person reach his office 10 minutes...
Let distance = 1.5 km. speed = 1km/hr
Actual time =1.5/1= 1.5hr
Now speed 3/2 km/hr, distance same.
Time = 1.5distance/3/2speed =1 hr
time difference =1.5 - 1 = 0.5 =10minutes given.
so, actual time = 1.5 =0.5×3 = 10×3 =30 minutes Ans.
Actual time =1.5/1= 1.5hr
Now speed 3/2 km/hr, distance same.
Time = 1.5distance/3/2speed =1 hr
time difference =1.5 - 1 = 0.5 =10minutes given.
so, actual time = 1.5 =0.5×3 = 10×3 =30 minutes Ans.
Community Answer
By walking 3/2 of his usual speed a person reach his office 10 minutes...
Solution:
Let the usual time taken by the person be x minutes.
According to the question, when the person walks at 3/2 of his usual speed, he reaches the office 10 minutes earlier than his usual time.
So, we can write:
x - 10 = (2/3)x
Multiplying both sides by 3, we get:
3x - 30 = 2x
Subtracting x from both sides, we get:
x = 30
Therefore, the person's usual time taken to reach the office is 30 minutes.
Hence, the correct answer is option 'B' (10 min).
Let the usual time taken by the person be x minutes.
According to the question, when the person walks at 3/2 of his usual speed, he reaches the office 10 minutes earlier than his usual time.
So, we can write:
x - 10 = (2/3)x
Multiplying both sides by 3, we get:
3x - 30 = 2x
Subtracting x from both sides, we get:
x = 30
Therefore, the person's usual time taken to reach the office is 30 minutes.
Hence, the correct answer is option 'B' (10 min).
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By walking 3/2 of his usual speed a person reach his office 10 minutes earlier. Find his usual times.a)5 minb)10 minc)20 mind)Nonee)All of the aboveCorrect answer is option 'B'. Can you explain this answer?
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