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By walking 3/2 of his usual speed a person reach his office 10 minutes earlier. Find his usual time.
- a)25 min
- b)30 min
- c)40 min
- d)None
- e)All of the above
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
By walking 3/2 of his usual speed a person reach his office 10 minutes...
Assume speed= x and time= t to reach work.
Distance = x*t.
Now, he reaches 10 minutes early. So= t - 10 minutes.
Distance remains the same.
x*t = x*(t-10)*3/2
2t = 3t - 30
t =30 minutes.
Distance = x*t.
Now, he reaches 10 minutes early. So= t - 10 minutes.
Distance remains the same.
x*t = x*(t-10)*3/2
2t = 3t - 30
t =30 minutes.
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Community Answer
By walking 3/2 of his usual speed a person reach his office 10 minutes...
Given: A person walked at 3/2 of his usual speed and reached his office 10 minutes earlier.
To find: The person's usual time to reach his office.
Solution:
Let's assume the person's usual speed be 'S' and the usual time taken to reach his office be 'T'.
Then, the distance between his home and office can be calculated as follows:
Distance = Speed × Time
Distance = S × T
Now, the person walks at 3/2 of his usual speed. Therefore, his new speed will be:
New Speed = 3/2 × S
His new time taken to reach his office can be calculated as follows:
New Time = T - 10 (given)
Distance = New Speed × New Time
Distance = (3/2 × S) × (T - 10)
Distance = 3/2 × S × T - 15S
Now, equating the two distances, we get:
S × T = 3/2 × S × T - 15S
Solving the above equation, we get:
T = 30 minutes
Therefore, the person's usual time taken to reach his office is 30 minutes.
Hence, the correct answer is option 'B' - 30 min.
To find: The person's usual time to reach his office.
Solution:
Let's assume the person's usual speed be 'S' and the usual time taken to reach his office be 'T'.
Then, the distance between his home and office can be calculated as follows:
Distance = Speed × Time
Distance = S × T
Now, the person walks at 3/2 of his usual speed. Therefore, his new speed will be:
New Speed = 3/2 × S
His new time taken to reach his office can be calculated as follows:
New Time = T - 10 (given)
Distance = New Speed × New Time
Distance = (3/2 × S) × (T - 10)
Distance = 3/2 × S × T - 15S
Now, equating the two distances, we get:
S × T = 3/2 × S × T - 15S
Solving the above equation, we get:
T = 30 minutes
Therefore, the person's usual time taken to reach his office is 30 minutes.
Hence, the correct answer is option 'B' - 30 min.
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By walking 3/2 of his usual speed a person reach his office 10 minutes earlier. Find his usual time.a)25 minb)30 minc)40 mind)Nonee)All of the aboveCorrect answer is option 'B'. Can you explain this answer?
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