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Byof 2/5 his usual speed a student reach his school 30 minutes late. Find his usual time?
- a)10 min
- b)20 min
- c)30 min
- d)None of these
- e)All of the above
Correct answer is option 'B'. Can you explain this answer?
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Byof 2/5 his usual speed a student reach his school 30 minutes late. F...
Question Analysis:
The question states that a student reaches his school 30 minutes late when he travels at 2/5 of his usual speed. We need to find the student's usual time to reach the school.
Given:
Speed at which the student reaches the school when late: 2/5 of his usual speed
Time taken to reach the school when late: 30 minutes
Solution:
Let's assume that the student's usual time to reach the school is T minutes.
When the student travels at 2/5 of his usual speed, the time taken is 30 minutes more than the usual time.
1. Calculating Speed:
To calculate the student's speed when traveling at 2/5 of his usual speed, we can use the formula:
Speed = Distance/Time
Since the distance remains the same, we can compare the speeds using the following equation:
Usual Speed / (2/5 of Usual Speed) = T / (T + 30)
Simplifying the equation, we get:
(5/2) * T = T + 30
Solving for T, we find:
(5/2) * T - T = 30
(5/2 - 2/2) * T = 30
(3/2) * T = 30
T = 30 * (2/3)
T = 20 minutes
Therefore, the student's usual time to reach the school is 20 minutes.
Hence, the correct answer is option B.
The question states that a student reaches his school 30 minutes late when he travels at 2/5 of his usual speed. We need to find the student's usual time to reach the school.
Given:
Speed at which the student reaches the school when late: 2/5 of his usual speed
Time taken to reach the school when late: 30 minutes
Solution:
Let's assume that the student's usual time to reach the school is T minutes.
When the student travels at 2/5 of his usual speed, the time taken is 30 minutes more than the usual time.
1. Calculating Speed:
To calculate the student's speed when traveling at 2/5 of his usual speed, we can use the formula:
Speed = Distance/Time
Since the distance remains the same, we can compare the speeds using the following equation:
Usual Speed / (2/5 of Usual Speed) = T / (T + 30)
Simplifying the equation, we get:
(5/2) * T = T + 30
Solving for T, we find:
(5/2) * T - T = 30
(5/2 - 2/2) * T = 30
(3/2) * T = 30
T = 30 * (2/3)
T = 20 minutes
Therefore, the student's usual time to reach the school is 20 minutes.
Hence, the correct answer is option B.
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Byof 2/5 his usual speed a student reach his school 30 minutes late. Find his usual time?a)10 minb)20 minc)30 mind)None of thesee)All of the aboveCorrect answer is option 'B'. Can you explain this answer?
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