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In a deflection magnetometer experiment in tan A position, a short-bar magnet placed at 18 cm from the centre of the compass needle produces a deflection of 30º. If another magnet of same length but 16 times pole strength as that of first magnet is placed in tan B position at 36cm, the deflection will be
  • a)
  • b)
    30º
  • c)
    45º
  • d)
    60º
Correct answer is option 'B'. Can you explain this answer?
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In a deflection magnetometer experiment, the deflection angle (θ) produced by a magnetic field is given by the formula:

θ = tan⁻¹((2dM)/(Bl))

Where:
θ = deflection angle in radians
d = distance between the center of the compass needle and the short-bar magnet
M = magnetic moment of the short-bar magnet
B = magnetic field strength
l = length of the compass needle

Given:
d = 18 cm = 0.18 m
θ = 30 degrees = (30 * π) / 180 radians (converting degrees to radians)

We need to find the value of B, the magnetic field strength.

Rearranging the formula, we have:

B = (2dM) / (l * tan(θ))

Substituting the given values, we get:

B = (2 * 0.18 * M) / (l * tan((30 * π) / 180))

Since we don't have the values for M and l, we cannot calculate the exact value of B. The formula gives the relationship between the deflection angle and the magnetic field strength, but we need additional information about the magnetic moment and the length of the compass needle to find the exact value.
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In a deflection magnetometer experiment in tan A position, a short-bar magnet placed at 18 cm from the centre of the compass needle produces a deflection of 30º. If another magnet of same length but 16 times pole strength as that of first magnet is placed in tan B position at 36cm, the deflection will bea)0ºb)30ºc)45ºd)60ºCorrect answer is option 'B'. Can you explain this answer?
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In a deflection magnetometer experiment in tan A position, a short-bar magnet placed at 18 cm from the centre of the compass needle produces a deflection of 30º. If another magnet of same length but 16 times pole strength as that of first magnet is placed in tan B position at 36cm, the deflection will bea)0ºb)30ºc)45ºd)60ºCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In a deflection magnetometer experiment in tan A position, a short-bar magnet placed at 18 cm from the centre of the compass needle produces a deflection of 30º. If another magnet of same length but 16 times pole strength as that of first magnet is placed in tan B position at 36cm, the deflection will bea)0ºb)30ºc)45ºd)60ºCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a deflection magnetometer experiment in tan A position, a short-bar magnet placed at 18 cm from the centre of the compass needle produces a deflection of 30º. If another magnet of same length but 16 times pole strength as that of first magnet is placed in tan B position at 36cm, the deflection will bea)0ºb)30ºc)45ºd)60ºCorrect answer is option 'B'. Can you explain this answer?.
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