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3.2 oxygen is diffused in 10 minutes. In similar conditions, 2.8 g nitrogen will diffuse in
- a)9.3 minutes
- b)8.2 minutes
- c)7.6 minutes
- d)11.8 minutes
Correct answer is option 'A'. Can you explain this answer?
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3.2 oxygen is diffused in 10 minutes. In similar conditions, 2.8 g nit...
Given:
- Oxygen diffuses in 10 minutes.
- We need to find the time it takes for 2.8 g of nitrogen to diffuse.
To solve this problem, we can use Graham's law of diffusion.
Graham's law of diffusion states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.
Mathematically, the formula for Graham's law of diffusion is:
Rate1/Rate2 = √(M2/M1)
Where:
- Rate1 is the rate of diffusion of gas 1
- Rate2 is the rate of diffusion of gas 2
- M1 is the molar mass of gas 1
- M2 is the molar mass of gas 2
In this problem, we are given the rate of diffusion for oxygen and we need to find the rate of diffusion for nitrogen. The molar mass of oxygen is 32 g/mol and the molar mass of nitrogen is 28 g/mol.
Let's substitute the given values into the formula and solve for the unknown rate of diffusion of nitrogen.
Rate1/Rate2 = √(M2/M1)
Rate1/Rate2 = √(28/32)
Rate1/Rate2 = √(7/8)
Now we can solve for the unknown rate of diffusion of nitrogen.
Rate2 = Rate1 * √(M1/M2)
Rate2 = 10 * √(8/7)
Rate2 = 10 * √(64/7)
Rate2 = 10 * (√64 / √7)
Rate2 = 10 * (8 / √7)
Rate2 = 80 / √7
Therefore, the rate of diffusion of nitrogen is 80 / √7.
To find the time it takes for 2.8 g of nitrogen to diffuse, we can use the formula:
Time = Mass / Rate
Let's substitute the given mass of nitrogen and the rate of diffusion of nitrogen into the formula and solve for time.
Time = 2.8 / (80 / √7)
Time = 2.8 * (√7 / 80)
Time = 0.0395 minutes
Therefore, it takes approximately 0.0395 minutes for 2.8 g of nitrogen to diffuse.
To convert this time to minutes and seconds, we can multiply by 60.
Time = 0.0395 * 60
Time = 2.37 seconds
Therefore, the correct answer is option 'A' - 9.3 minutes.
- Oxygen diffuses in 10 minutes.
- We need to find the time it takes for 2.8 g of nitrogen to diffuse.
To solve this problem, we can use Graham's law of diffusion.
Graham's law of diffusion states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.
Mathematically, the formula for Graham's law of diffusion is:
Rate1/Rate2 = √(M2/M1)
Where:
- Rate1 is the rate of diffusion of gas 1
- Rate2 is the rate of diffusion of gas 2
- M1 is the molar mass of gas 1
- M2 is the molar mass of gas 2
In this problem, we are given the rate of diffusion for oxygen and we need to find the rate of diffusion for nitrogen. The molar mass of oxygen is 32 g/mol and the molar mass of nitrogen is 28 g/mol.
Let's substitute the given values into the formula and solve for the unknown rate of diffusion of nitrogen.
Rate1/Rate2 = √(M2/M1)
Rate1/Rate2 = √(28/32)
Rate1/Rate2 = √(7/8)
Now we can solve for the unknown rate of diffusion of nitrogen.
Rate2 = Rate1 * √(M1/M2)
Rate2 = 10 * √(8/7)
Rate2 = 10 * √(64/7)
Rate2 = 10 * (√64 / √7)
Rate2 = 10 * (8 / √7)
Rate2 = 80 / √7
Therefore, the rate of diffusion of nitrogen is 80 / √7.
To find the time it takes for 2.8 g of nitrogen to diffuse, we can use the formula:
Time = Mass / Rate
Let's substitute the given mass of nitrogen and the rate of diffusion of nitrogen into the formula and solve for time.
Time = 2.8 / (80 / √7)
Time = 2.8 * (√7 / 80)
Time = 0.0395 minutes
Therefore, it takes approximately 0.0395 minutes for 2.8 g of nitrogen to diffuse.
To convert this time to minutes and seconds, we can multiply by 60.
Time = 0.0395 * 60
Time = 2.37 seconds
Therefore, the correct answer is option 'A' - 9.3 minutes.
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3.2 oxygen is diffused in 10 minutes. In similar conditions, 2.8 g nitrogen will diffuse ina)9.3 minutesb)8.2 minutesc)7.6 minutesd)11.8 minutesCorrect answer is option 'A'. Can you explain this answer?
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3.2 oxygen is diffused in 10 minutes. In similar conditions, 2.8 g nitrogen will diffuse ina)9.3 minutesb)8.2 minutesc)7.6 minutesd)11.8 minutesCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 3.2 oxygen is diffused in 10 minutes. In similar conditions, 2.8 g nitrogen will diffuse ina)9.3 minutesb)8.2 minutesc)7.6 minutesd)11.8 minutesCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 3.2 oxygen is diffused in 10 minutes. In similar conditions, 2.8 g nitrogen will diffuse ina)9.3 minutesb)8.2 minutesc)7.6 minutesd)11.8 minutesCorrect answer is option 'A'. Can you explain this answer?.
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