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A parallel monochromatic beam of light is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the first minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of slit is
  • a)
    Zero
  • b)
    π
  • c)
    π2
  • d)
    2 π
Correct answer is option 'D'. Can you explain this answer?
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The correct option is b) π (pi).

At the first minimum of the diffraction pattern, the waves from the two edges of the slit interfere destructively. This means that the phase difference between the two waves is half a wavelength out of phase, which corresponds to a phase difference of π (pi).
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A parallel monochromatic beam of light is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the first minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of slit isa)Zerob)πc)π2d)2 πCorrect answer is option 'D'. Can you explain this answer?
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