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An electromagnetic wave emitted by source travels 21km to arrive at a receiver, the wave while travelling in another path is reflected from a surface at 19km away and further travels 12km to reach the same receiver, if destruction interference occurs at the receiving end, the wavelength of the wave is?
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An electromagnetic wave emitted by source travels 21km to arrive at a ...
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An electromagnetic wave emitted by source travels 21km to arrive at a ...
Explanation:

Given Data:
- Distance travelled by the wave from the source to the receiver = 21 km
- Distance travelled by the wave from the reflecting surface to the receiver = 12 km
- Distance between the reflecting surface and the receiver = 19 km

Understanding the Problem:
In this problem, we have an electromagnetic wave emitted by a source and received at a receiver. The wave travels two different paths before reaching the receiver. One path is a direct path from the source to the receiver, while the other path involves reflection from a surface before reaching the receiver. We are given the distances travelled by the wave in each path, and we need to determine the wavelength of the wave.

Using the Concept of Path Difference:
To solve this problem, we can use the concept of path difference. Path difference is the difference in the distances travelled by two waves to reach a point. In destructive interference, the path difference between two waves is equal to half the wavelength.

Calculating the Path Difference:
Let's calculate the path difference in this problem:
- Path 1: Direct path from the source to the receiver = 21 km
- Path 2: Reflection from the surface and then reaching the receiver = (19 km + 12 km) = 31 km

Path Difference = Path 2 - Path 1
Path Difference = 31 km - 21 km
Path Difference = 10 km

Calculating the Wavelength:
We know that the path difference is equal to half the wavelength in destructive interference. So, we can use the following formula to calculate the wavelength:

Path Difference = (wavelength/2)

Substituting the given path difference into the formula:

10 km = (wavelength/2)

Solving for the wavelength:

wavelength = 20 km

Therefore, the wavelength of the electromagnetic wave is 20 km.
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An electromagnetic wave emitted by source travels 21km to arrive at a receiver, the wave while travelling in another path is reflected from a surface at 19km away and further travels 12km to reach the same receiver, if destruction interference occurs at the receiving end, the wavelength of the wave is?
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An electromagnetic wave emitted by source travels 21km to arrive at a receiver, the wave while travelling in another path is reflected from a surface at 19km away and further travels 12km to reach the same receiver, if destruction interference occurs at the receiving end, the wavelength of the wave is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An electromagnetic wave emitted by source travels 21km to arrive at a receiver, the wave while travelling in another path is reflected from a surface at 19km away and further travels 12km to reach the same receiver, if destruction interference occurs at the receiving end, the wavelength of the wave is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electromagnetic wave emitted by source travels 21km to arrive at a receiver, the wave while travelling in another path is reflected from a surface at 19km away and further travels 12km to reach the same receiver, if destruction interference occurs at the receiving end, the wavelength of the wave is?.
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