Given: Alpha = 0.5, n = 5 So from: Alpha = (i - 1)/(n - 1); i = 4 x 0.5 + 1 = 3; Osmostic pressure pi = iCRT = 3 x 0.1 x 0.083 x 300 = 7.48 bar.

Calculation of Osmotic Pressure of a Deci Molar Solution of Potassium Ferrocyanide

To calculate the osmotic pressure of a deci molar solution of potassium ferrocyanide, we need to consider the degree of dissociation and the van't Hoff factor.

Step 1: Determine the Degree of Dissociation
The problem states that the solution is 50% dissociated at 300K. This means that only half of the potassium ferrocyanide molecules will dissociate into their respective ions in solution.

Step 2: Calculate the Van't Hoff Factor (i)
The van't Hoff factor (i) represents the number of particles into which one molecule of the solute dissociates in solution. Since potassium ferrocyanide dissociates into three ions (K⁺, Fe(CN)₆²⁻) when it dissolves, the van't Hoff factor (i) is 3.

Step 3: Calculate the Concentration of Ions
Since the solution is deci molar, the concentration of the potassium ferrocyanide is 0.1 M. Since the solution is 50% dissociated, the concentration of the ions (K⁺ and Fe(CN)₆²⁻) will be halved. Therefore, the concentration of the ions is 0.05 M.

Step 4: Calculate the Osmotic Pressure
The osmotic pressure (π) can be calculated using the van't Hoff equation: π = iCRT, where C is the concentration of the solute, R is the ideal gas constant, and T is the temperature in Kelvin.

Plugging in the values:
i = 3 (van't Hoff factor)
C = 0.05 M (concentration of ions)
R = 0.0821 L·atm/(mol·K) (ideal gas constant)
T = 300 K (temperature)

π = 3 * 0.05 M * 0.0821 L·atm/(mol·K) * 300 K
π = 3 * 0.0123 L·atm/mol

The osmotic pressure of the deci molar solution of potassium ferrocyanide is approximately 0.0369 atm.

Conclusion
The osmotic pressure of a deci molar solution of potassium ferrocyanide can be calculated by considering the degree of dissociation and the van't Hoff factor. By using the van't Hoff equation and the given values, we determined that the osmotic pressure of the solution is approximately 0.0369 atm.

osmotic pressure equals CRTihere C =0.1 R=0.0821 T=300 i=0.5 solve it