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The correct order of N-compounds in its decreasingorder of oxidation states is
- a)HNO3, NO, N2, NH4Cl
- b)HNO3, NO, NH4Cl, N2
- c)HNO3, NH4Cl, NO, N2
- d)NH4Cl, N2, NO, HNO3
Correct answer is option 'A'. Can you explain this answer?
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The correct order of N-compounds in its decreasingorder of oxidation s...
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The correct order of N-compounds in its decreasingorder of oxidation s...
The correct order of N-compounds in decreasing order of oxidation states is:
Explanation:
To determine the decreasing order of oxidation states of N-compounds, we need to consider the oxidation states of nitrogen in each compound.
1. HNO3 (Nitric Acid)
The oxidation state of nitrogen in HNO3 is +5. Nitric acid is a strong oxidizing agent and nitrogen is in its highest oxidation state in this compound.
2. NO (Nitric Oxide)
The oxidation state of nitrogen in NO is +2. Nitric oxide is a free radical and nitrogen is in an intermediate oxidation state.
3. N2 (Nitrogen Gas)
The oxidation state of nitrogen in N2 is 0. Nitrogen gas exists as a diatomic molecule with a neutral oxidation state.
4. NH4Cl (Ammonium Chloride)
The oxidation state of nitrogen in NH4Cl is -3. In this compound, nitrogen is in its lowest oxidation state as part of the ammonium ion (NH4+), where it has gained three electrons.
Overall Order:
Therefore, the correct order of N-compounds in decreasing order of oxidation states is:
HNO3 > NO > N2 > NH4Cl
Summary:
The correct order of N-compounds in decreasing order of oxidation states is HNO3, NO, N2, NH4Cl. Nitric acid (HNO3) has the highest oxidation state of nitrogen (+5), followed by nitric oxide (NO) with an oxidation state of +2. Nitrogen gas (N2) has an oxidation state of 0, and ammonium chloride (NH4Cl) has the lowest oxidation state of nitrogen (-3).
Explanation:
To determine the decreasing order of oxidation states of N-compounds, we need to consider the oxidation states of nitrogen in each compound.
1. HNO3 (Nitric Acid)
The oxidation state of nitrogen in HNO3 is +5. Nitric acid is a strong oxidizing agent and nitrogen is in its highest oxidation state in this compound.
2. NO (Nitric Oxide)
The oxidation state of nitrogen in NO is +2. Nitric oxide is a free radical and nitrogen is in an intermediate oxidation state.
3. N2 (Nitrogen Gas)
The oxidation state of nitrogen in N2 is 0. Nitrogen gas exists as a diatomic molecule with a neutral oxidation state.
4. NH4Cl (Ammonium Chloride)
The oxidation state of nitrogen in NH4Cl is -3. In this compound, nitrogen is in its lowest oxidation state as part of the ammonium ion (NH4+), where it has gained three electrons.
Overall Order:
Therefore, the correct order of N-compounds in decreasing order of oxidation states is:
HNO3 > NO > N2 > NH4Cl
Summary:
The correct order of N-compounds in decreasing order of oxidation states is HNO3, NO, N2, NH4Cl. Nitric acid (HNO3) has the highest oxidation state of nitrogen (+5), followed by nitric oxide (NO) with an oxidation state of +2. Nitrogen gas (N2) has an oxidation state of 0, and ammonium chloride (NH4Cl) has the lowest oxidation state of nitrogen (-3).
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The correct order of N-compounds in its decreasingorder of oxidation states isa)HNO3, NO, N2, NH4Clb)HNO3, NO, NH4Cl, N2c)HNO3, NH4Cl, NO, N2d)NH4Cl, N2, NO, HNO3Correct answer is option 'A'. Can you explain this answer?
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