Three friends divided some bullets equally. After all of them shot 4 b...
Let bullet one has = x
remaining bullets = 3x-12
atq:
3x-12=x
=> x=6
total bullets=3x
=3×6
=18(answer)
Three friends divided some bullets equally. After all of them shot 4 b...
Problem: Three friends divided some bullets equally. After all of them shot 4 bullets the total no of remaining bullets is equal to that of one has after division. Find the original number divided.
Solution:
Let us assume that the original number of bullets divided equally among the three friends is 'x'. Therefore, each friend would get 'x/3' bullets.
After all of them shoot 4 bullets, the total number of bullets remaining is (x - 12).
Also, according to the question, the total number of bullets remaining is equal to that of one has after division, which means (x - 12) = (x/3).
Solving the above equation, we get:
x - 12 = x/3
3x - 36 = x
2x = 36
x = 18
Therefore, the original number of bullets divided equally among the three friends is 18.
Answer: The original number of bullets divided equally among the three friends is 18.