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When the gate-to-source voltage VGS of a MOSFET with a threshold voltage of 400mV, working in saturation is 900mV, the drain current is observed to be 1mA. Neglecting the channel width modulation effect and assuming that the MOSFET is operating at saturation, the drain current for an applied VGS of 1400mV is
  • a)
    0.5 mA
  • b)
    2.0 mA
  • c)
    3.5 mA
  • d)
    4.0 mA
Correct answer is option 'D'. Can you explain this answer?
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When the gate-to-source voltageVGS of a MOSFET with a threshold voltag...
The MOSFET current is saturation is given by,
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When the gate-to-source voltageVGS of a MOSFET with a threshold voltag...
Solution:

Given data:

Threshold voltage (VTH) = 400mV

Gate-to-source voltage (VGS) for saturation = 900mV

Drain current (ID) at VGS = 900mV and saturation = 1mA

To find:

The drain current (ID) for VGS = 1400mV

Explanation:

The MOSFET operates in saturation region when VGS > VTH and VDS > (VGS - VTH).

From the given data, VGS = 900mV is the gate-to-source voltage that puts the MOSFET into saturation region and the corresponding drain current is 1mA.

Now, we need to find the drain current when the gate-to-source voltage is increased to 1400mV.

As per the question, we can assume that the MOSFET operates in saturation region.

The drain current in saturation region is given by:

ID = (μnCox/2) * (W/L) * (VGS - VTH)^2

where, μn is the electron mobility, Cox is the oxide capacitance per unit area, W is the channel width, L is the channel length.

From the question, we can neglect the channel width modulation effect. Hence, the drain current equation reduces to:

ID = (μnCox/2) * (W/L) * (VGS - VTH)^2

Given, ID = 1mA, VGS = 900mV

Substituting the given values, we get:

1 mA = (μnCox/2) * (W/L) * (900 mV - 400 mV)^2

Solving for (W/L), we get:

(W/L) = 2 * ID / (μnCox * (VGS - VTH)^2)

Now, we can use this value of (W/L) to calculate the drain current for VGS = 1400mV.

Given, VGS = 1400mV

Substituting the given values, we get:

ID = (μnCox/2) * (W/L) * (VGS - VTH)^2

ID = (μnCox/2) * (2 * ID / (μnCox * (900 mV - 400 mV)^2)) * (1400 mV - 400 mV)^2

ID = 4 mA

Therefore, the drain current for VGS = 1400mV is 4mA.

Hence, the correct answer is option D.
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When the gate-to-source voltageVGS of a MOSFET with a threshold voltage of400mV, working in saturation is900mV, the drain current is observed to be1mA. Neglecting the channel width modulation effect and assuming that the MOSFET is operating at saturation, the drain current for an appliedVGS of1400mV isa)0.5 mAb)2.0 mAc)3.5 mAd)4.0 mACorrect answer is option 'D'. Can you explain this answer?
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