**Minimum Number of Rooms Required for Seating Students in a Seminar**

To determine the minimum number of rooms required for seating students in a seminar, given that the number of students in physics, chemistry, and math are 48, 60, and 96 respectively, we need to follow the steps listed below.

**Step 1: Find the common factor**

Since we want to seat the same number of students from each subject in each room, we need to find the common factor of the number of students in each subject. The common factor of 48, 60, and 96 is 12.

**Step 2: Divide the number of students by the common factor**

Next, we need to divide the number of students in each subject by the common factor to find the number of groups that can be formed in each subject. The results are as follows:

- Physics: 48 ÷ 12 = 4 groups
- Chemistry: 60 ÷ 12 = 5 groups
- Math: 96 ÷ 12 = 8 groups

**Step 3: Find the total number of groups**

To find the total number of groups, we need to add the number of groups in each subject. The total number of groups is 4 + 5 + 8 = 17.

**Step 4: Find the minimum number of rooms required**

Finally, we need to divide the total number of groups by the number of groups that can be seated in each room to find the minimum number of rooms required. Since the same number of students from each subject can be seated in each room, the number of groups that can be seated in each room is the same as the number of rooms required. Therefore, we get:

- Total number of groups: 17
- Number of groups that can be seated in each room: 1
- Minimum number of rooms required: 17

Hence, we need a minimum of 17 rooms to seat the same number of students from each subject in each room.

Sister. take the hcf of 48 , 60 , 96 . you will get 12 as your answer . now divide 48, 60 , 96 by 12 . you will get 4,5,8 now add 4+5+8 you will get 17 rooms as your answer.